10. an artificial satellite is moving in a circular orbit of radius 42250 km. calculate its speed if it takes 24 hours to revolve around the earth.

Answer: The orbit’s circumference is equal to 2πr. The orbit’s circumference is equivalent to 2×π×42250. The orbit’s circumference is 265330 kilometers. The orbit takes 24 hours to complete. Thus, the satellite’s speed equals 265330/24. The satellite’s frequency is 11055.41 km/h. Our satellite’s speed is 26533/8640 . [24 hour = 24 × 60 × 60 = 86400 seconds] The satellite’s pace is 3.07 km/s.

Radius of the circular orbit, r = 42250 km Time taken by the satellite to revolve around the earth = 24 hour Linear velocity of the satellite = Total distance covered in one revolution Time taken = 2 π r time = 2 × 3.142 × 42250 24 k m / h = 11062.458 km/h = 11062.458 60 × 60 k m / s = 3.07 k m s − 1 =3.1km/s (Approx.)

Transcript NCERT Question 10 An artificial satellite is moving in a circular orbit of radius 42250 km. Calculate its speed if it takes 24 hours to revolve around the earth. Radius of the orbit = 42250 km Time taken = 24 hours Distance travelled by the satellite = Circumference of circle = 2𝜋r = 2 × 22/7 × 42250 = (2 × 22 × 42250)/7 km Radius of the orbit = 42250 km Time taken = 24 hours Distance travelled by the satellite = Circumference of circle = 2𝜋r = 2 × 22/7 × 42250 = (2 × 22 × 42250)/7 km Average Speed = 232375/21 km/h = 232375/21 × 𝑘𝑚/ℎ𝑟 = 232375/21 × 𝑘𝑚/(3600 𝑠𝑒𝑐𝑜𝑛𝑑𝑠) = 232375/(21 × 3600) km/s = 232375/(21 × 3600) km/s = 9295/(21 × 144) km/s = 9295/3024 km/s = 3.07 km/s Show More