2 chlorobutane to 3 4 dimethylhexane

NCERT Solutions For Class 12 Chemistry chapter 10-Haloalkanes And Haloarenes NCERT Solutions for Class 12 Chemistry NCERT Solutions for class-12 Chemistry Chapter 10 Haloalkanes and Haloarenes is prepared by our senior and renowned teachers of Physics Wallah primary focus while solving these questions of class-12 in NCERT textbook, also do read theory of this Chapter 10 Haloalkanes and Haloarenes while going before solving the NCERT questions. Our Physics Wallah team Prepared Other Subjects NCERT Solutions for class 12. Chapter 10 Haloalkanes and Haloarenes Answer the following Questions. Question 1. Name the following halides according to IUPAC system and classify them as alkyl, allyl, benzyl (primary, secondary, tertiary), vinyl or aryl halides: (i) (CH 3) 2CHCH(Cl)CH 3 (ii) CH 3CH 2CH(CH 3)CH(C 2H 5)Cl (iii) CH 3CH 2C(CH 3) 2CH 2I (iv) (CH 3) 3CCH 2CH(Br)C 6H 5 (v) CH 3CH(CH 3)CH(Br)CH 3 (vi) CH 3C(C 2H 5) 2CH 2Br (vii) CH 3C(Cl)(C 2H 5)CH 2CH 3 (viii) CH 3CH=C(Cl)CH 2CH(CH 3) 2 (ix) CH 3CH=CHC(Br)(CH 3) 2 (x) p-ClC 6H 4CH 2CH(CH 3) 2 (xi) m-ClCH 2C 6H 4CH 2C(CH 3) 3 (xii) o-Br-C 6H 4CH(CH 3)CH 2CH 3 Solution : (i) 2−Chloro−3−methylbutane (Secondary alkyl halide) (ii) 3−Chloro−4−methyhexane (Secondary alkyl halide) (iii) 1−Iodo−2, 2 −dimethylbutane (Primary alkyl halide) (iv) 1−Bromo−3, 3−dimethyl−1−phenylbutane (Secondary benzyl halide) (v) 2−Bromo−3−methylbutane (Secondary alkyl halide) (vi) 1−Bromo−2−ethyl−2−methylbutane (Primary alkyl halide) (vii) 3−Chloro−3−methyl...

NCERT Solutions For Class 12 Chemistry Chapter 10 Haloalkanes and Haloarenes Read also Topics and Subtopics in NCERT Solutions for Class 12 Chemistry Chapter 10 Haloalkanes and Haloarenes : Section Name Topic Name 10 Haloalkanes and Haloarenes 10.1 Classification 10.2 Nomenclature 10.3 Nature of C–X Bond 10.4 Methods of Preparation of Haloalkanes 10.5 Preparation of Haloarenes 10.6 Physical Properties 10.7 Chemical Reactions NCERT IN TEXT QUESTIONS 10.1 Write structures of the following compounds: (i) 2-Chloro-3-methylpentane (ii) 1-Chloro-4-ethylcydohexane (iii) 4-tert. Butyl-3-iodoheptane (iv) 1,4-Dibromobut-2-ene (v) 1-Bromo-4-sec. butyl-2-methylbenzene. Ans: 10.2. Why is sulphuric acid not used during the reaction of alcohols with KI? Ans: KI is expected to give HI on reacting with H 2SO 4 which will convert alcohols (R – OH) to alkyl iodides (R – I). However, H 2SO 4 is a strong oxidising agent and it oxidises HI formed during the reaction to I 2 which does not react with alcohol. To solve the problem, H2S04 is replaced by phosphoric acid (H3P04) which provides HI for the reaction and does not give I2 as is done by H2S04. 10.3. Write structures of different dihalogen derivatives of propane. Ans: Four isomers are possible. These are : 10.4. Among the isomeric alkanes of mdlecular formula C 5H 12, identify the one that on photochemical chlorination yields (i) A single monochloride. (ii) Three isomeric monochlorides. (iii) Four isomeric monochlorides. Ans: 10.5. Draw the...

NCERT Solutions for Class 12 Science Chemistry Chapter 10 Haloalkanes And Haloarenes are provided here with simple step-by-step explanations. These solutions for Haloalkanes And Haloarenes are extremely popular among Class 12 Science students for Chemistry Haloalkanes And Haloarenes Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the NCERT Book of Class 12 Science Chemistry Chapter 10 are provided here for you for free. You will also love the ad-free experience on Meritnation’s NCERT Solutions. All NCERT Solutions for class Class 12 Science Chemistry are prepared by experts and are 100% accurate. Answer: In the presence of sulphuric acid (H 2SO 4), KI produces HI Since is an oxidizing agent, it oxidizes HI (produced in the reaction to I 2). As a result, the reaction between alcohol and HI to produce alkyl iodide cannot occur. Therefore, sulphuric acid is not used during the reaction of alcohols with KI. Instead, a non-oxidizing acid such as H 3PO 4 is used. Page No 289: Answer: (i) To have a single monochloride, there should be only one type of H-atom in the isomer of the alkane of the molecular formula C 5H 12. This is because, replacement of any H-atom leads to the formation of the same product. The isomer is neopentane. Neopentane (ii) To have three isomeric monochlorides, the isomer of the alkane of the molecular formula C 5H 12 should contain three different types of H-atoms. Therefore, the isomer is n-...