A circular park of radius 20 m is situated in a colony. three boys ankur, syed and david are sitting at equal distance on its boundary each having a toy telephone in his hands to talk each other. find the length of the string of each phone.

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Transcript Ex 9.2, 6 A circular park of radius 20 m is situated in a colony. Three boys Ankur, Syed and David are sitting at equal distance on its boundary each having a toy telephone in his hands to talk each other. Find the length of the string of each phone. Given: Circular park with radius 20m Let Ankur, Syed and David be donated by points A,S & D resp. Given all three are sitting at equal distances, i.e., AS = SD = AD To find: Length of AS = SD = AD Explanation: Let AS = SD = AD = 2x In ASD, all sides are equal, ∴ ASD is an equilateral triangle We draw OP ⊥ SD So, SP = DP = 1/2 SD ⇒ SP = DP = 2𝑥/2 = x Join OS & AO In Δ OPS By Pythagoras theorem OS2 = OP2 + PS2 (20)2 = OP2 + x2 400 = OP2 + x2 400 – x2 = OP2 OP2 = 400 – x2 OP = √("400 – x2" ) Now, AP = AO + OP √("3" )x = 20 + √("400 – x2" ) √("3" )x – 20 = √("400 – x2" ) √("400 – x2" ) = √("3" )x – 20 Squaring both sides (√("400 – x2" ))^2= (√("3" )x – 20)2 400 – x2 = (√3x)2 + (20)2 – 2 ×(√3x) × (20) "400 – x2 =" 3x2 + 400 – 40√3x "400 – 400 + 40" √3 "x =" 3x2 + x2 "40" √3 "x =" 4x2 4x2 = 40√3x "x2" /"x" = 40/4 √3 x = 10√3 m AS = SD = AD = 2x = 2 × 10√3 = 20√3 m ∴ Length of string of each phone is 20√3 m Show More

question is a circular Park of radius 20m is situated in a call and 3 boys Ankur sides and David are sitting at equal distance on its monetary each having a toy telephone routine ladki Ankur Shayad and they are sitting at three points on the circle and distance to and we have to find the length of the string of phone centroid of the triangle To Ham khologi and which is equal to GC of circle write ab Hamen pata hai ki jo ji point Hai divide hypotenuse of a reduced equal and radius is 2020 ka square error 403 cquel 2cd square series key value and quality value kya Gai 300 CD key value kya hai 10 Rotary M Kya Hoga Ab yah kya hai the midpoint of BC Agar DC ki volume Mein Pata Hai To BC ki value Kya Hogi to x dc2 x of 10 root 3 value ke aage 20 root 3 cm for this is the answer to this question

The correct option is A 20√3 Let situation of Ankur, Syed and David be A, S and D respectively in the circular path. OS = OD = OA = 20m construction: Draw OM ⊥ SA Now, AS = SD = AD So, ASD is an equilateral triangle. ∠ A = 60 ∘ ∠ M A O = 30 ∘ M O = A O 2 [In right angled triangle, the side opposite to 30 ∘ is half of hypotenuse] M O = 20 2 = 10 A M 2 = A O 2 − M O 2 = 20 2 − 10 2 400 - 100 = 300 A M = √ 300 A S = 2 A M = 2 √ 300 = 2 × 10 √ 3 = 20 √ 3

The correct option is A 20√3 Let situation of Ankur, Syed and David be A, S and D respectively in the circular path. OS = OD = OA = 20m construction: Draw OM ⊥ SA Now, AS = SD = AD So, ASD is an equilateral triangle. ∠ A = 60 ∘ ∠ M A O = 30 ∘ M O = A O 2 [In right angled triangle, the side opposite to 30 ∘ is half of hypotenuse] M O = 20 2 = 10 A M 2 = A O 2 − M O 2 = 20 2 − 10 2 400 - 100 = 300 A M = √ 300 A S = 2 A M = 2 √ 300 = 2 × 10 √ 3 = 20 √ 3

Transcript Ex 9.2, 6 A circular park of radius 20 m is situated in a colony. Three boys Ankur, Syed and David are sitting at equal distance on its boundary each having a toy telephone in his hands to talk each other. Find the length of the string of each phone. Given: Circular park with radius 20m Let Ankur, Syed and David be donated by points A,S & D resp. Given all three are sitting at equal distances, i.e., AS = SD = AD To find: Length of AS = SD = AD Explanation: Let AS = SD = AD = 2x In ASD, all sides are equal, ∴ ASD is an equilateral triangle We draw OP ⊥ SD So, SP = DP = 1/2 SD ⇒ SP = DP = 2𝑥/2 = x Join OS & AO In Δ OPS By Pythagoras theorem OS2 = OP2 + PS2 (20)2 = OP2 + x2 400 = OP2 + x2 400 – x2 = OP2 OP2 = 400 – x2 OP = √("400 – x2" ) Now, AP = AO + OP √("3" )x = 20 + √("400 – x2" ) √("3" )x – 20 = √("400 – x2" ) √("400 – x2" ) = √("3" )x – 20 Squaring both sides (√("400 – x2" ))^2= (√("3" )x – 20)2 400 – x2 = (√3x)2 + (20)2 – 2 ×(√3x) × (20) "400 – x2 =" 3x2 + 400 – 40√3x "400 – 400 + 40" √3 "x =" 3x2 + x2 "40" √3 "x =" 4x2 4x2 = 40√3x "x2" /"x" = 40/4 √3 x = 10√3 m AS = SD = AD = 2x = 2 × 10√3 = 20√3 m ∴ Length of string of each phone is 20√3 m Show More

question is a circular Park of radius 20m is situated in a call and 3 boys Ankur sides and David are sitting at equal distance on its monetary each having a toy telephone routine ladki Ankur Shayad and they are sitting at three points on the circle and distance to and we have to find the length of the string of phone centroid of the triangle To Ham khologi and which is equal to GC of circle write ab Hamen pata hai ki jo ji point Hai divide hypotenuse of a reduced equal and radius is 2020 ka square error 403 cquel 2cd square series key value and quality value kya Gai 300 CD key value kya hai 10 Rotary M Kya Hoga Ab yah kya hai the midpoint of BC Agar DC ki volume Mein Pata Hai To BC ki value Kya Hogi to x dc2 x of 10 root 3 value ke aage 20 root 3 cm for this is the answer to this question

People Also Read: A circular park of radius 20 m is situated in a colony. Three boys Ankur, Syed and David are sitting at equal distance on its boundary each having a toy telephone in his hands to talk each other. What is A circular park of radius 20m is situated in a colony. Three boys Ankur Maths NCERT Solutions Class 9 – Chapter 10 Exercise 10. Summary: If a circular park of the radius of 20m is situated in a colony, three boys Ankur, Syed, and David are sitting at equal distance on its boundary each having a toy telephone in his hands to talk to each other, then the length of the string of each phone is 34. A circular park of radius 20 m is situated in a colony. Three boys Ankur, Syed and David are sitting at equal distance on its boundary each having a toy telephone in his hands to talk each other. How to use A circular park with radius 20 m is situated in a colony. Three boys A circular park of radius 2 0 m is situated in a colony. Three boys Ankur, Syed and David are sitting at equal distance on its boundary each having a toy telephone in his hands to talk each other. A circular park of radius 20 m is situated in a colony. Three boys Ankur, Syed and David are sitting at equal distance on its boundary each having a toy telephone in their hands to talk to each other. A circular park of radius 20m is situated in a colony Three boys Ankur Syed and David are sitting at equal distance on its boundary each having a toy telephone in his hands to talk each other Find the len...

People Also Read: A circular park of radius 20 m is situated in a colony. Three boys Ankur, Syed and David are sitting at equal distance on its boundary each having a toy telephone in his hands to talk each other. What is A circular park of radius 20m is situated in a colony. Three boys Ankur Maths NCERT Solutions Class 9 – Chapter 10 Exercise 10. Summary: If a circular park of the radius of 20m is situated in a colony, three boys Ankur, Syed, and David are sitting at equal distance on its boundary each having a toy telephone in his hands to talk to each other, then the length of the string of each phone is 34. A circular park of radius 20 m is situated in a colony. Three boys Ankur, Syed and David are sitting at equal distance on its boundary each having a toy telephone in his hands to talk each other. How to use A circular park with radius 20 m is situated in a colony. Three boys A circular park of radius 2 0 m is situated in a colony. Three boys Ankur, Syed and David are sitting at equal distance on its boundary each having a toy telephone in his hands to talk each other. A circular park of radius 20 m is situated in a colony. Three boys Ankur, Syed and David are sitting at equal distance on its boundary each having a toy telephone in their hands to talk to each other. A circular park of radius 20m is situated in a colony Three boys Ankur Syed and David are sitting at equal distance on its boundary each having a toy telephone in his hands to talk each other Find the len...

question is a circular Park of radius 20m is situated in a call and 3 boys Ankur sides and David are sitting at equal distance on its monetary each having a toy telephone routine ladki Ankur Shayad and they are sitting at three points on the circle and distance to and we have to find the length of the string of phone centroid of the triangle To Ham khologi and which is equal to GC of circle write ab Hamen pata hai ki jo ji point Hai divide hypotenuse of a reduced equal and radius is 2020 ka square error 403 cquel 2cd square series key value and quality value kya Gai 300 CD key value kya hai 10 Rotary M Kya Hoga Ab yah kya hai the midpoint of BC Agar DC ki volume Mein Pata Hai To BC ki value Kya Hogi to x dc2 x of 10 root 3 value ke aage 20 root 3 cm for this is the answer to this question