A driver of a car travelling at 52 km

Solving time: 3 mins A driver of a car travelling at 52 km h − 1 applies the brakes and accelerates uniformly in the opposite direction. The car stops in 5 s. Another driver going at 3 km h − 1 in another car applies his brakes slowly and stops in 10 s. On the same graph paper. plot the speed versus time graphs for the two cars. Which of the two cars travelled farther after the brakes were applied? (A): Initial speed of the carA u = 52 kmh − 1 = 52 × 18 5 ​ = 14.44 ms − 1 The car stops in 5 seconds i.e v = 0 at t = 5 (B) : Initial speed of the car B u = 3 kmh − 1 = 3 × 18 5 ​ = 0.83 ms − 1 The car stops in 10 seconds i.e v = 0 at t = 10 With the help of these initial and final points for both the cases, we can plot the graph of speed vs time. Area under the speed-time graph gives the distance covered. ∴ Distance covered by car A x A ​ = 2 1 ​ × 14.44 × 5 = 36.1 m ∴ Distance covered by car A x B ​ = 2 1 ​ × 0.83 × 10 = 4.15 m Thus car A travels more distance than B. Views: 5,699 15 m in the 3 rd second and 23 m in the 5 th second. The displacement in 10 s will be 1) 150 m 2) 200 m 3) 250 m 4) 300 m 4. Two cars A and B are at rest at the origin O. If A starts with a uniform velocity of 20 m / s and B starts in the same direction with a constant acceleration of 2 m / s 2, then the cars will meet after time 1) 10 s 2) 20 s 3) 30 s 4) 40 s A driver of a car travelling at 52 km h − 1 applies the brakes and accelerates uniformly in the opposite direction. The car stops in 5 s. An...

Question Updated on: 13/06/2023 a driver of a car travelling at 52 k m / h applies the brakes and acceleration uniformly in the opposite direction. The car stops in 5 s. Another driver going at 34 k m / h in another car applies his brakes slowly and stops in 10 s. On the same graph paper, plot the speed versus time graphs for the two cars. Which of the two cars travelled farther after the brakes were applied ? Solution Here, initial speed of 1 st car, u = 52 k m h = 52 × 1000 m 60 × 60 s = 14.4 m / s final speed, v = 0, time taken, t = 5 s Acceleration = final speed - initial speed time taken = 0.14 .4 5 = − 2.88 m / s 2 Negative sign is for retardation. Similarly, for second car, u = 34 k m h = 34 × 1000 m 60 × 60 s = 9.4 m / s, v = 0, t = 10 s Acceleration = v − u t = 0 − 9.4 10 = − 0.94 m / s 2 Negative sign shows retardation. To plot the speed-time graph, we take time along X-axis and speed along Y-axis. Take a point A on Y-axis to represent a speed of 14.4 m / s and take a point B on X-axis to represent a time of 5second. Join A , B. This is the speed-time graph for the 1st car, Again, take a point C on Y-axis to represent a speed of 9.4 m / s and a point D on X-axis to represent a time of 10 second. Join C , D. This is the speed time graph for the second car, As distance travelled = area ensolved between the speed-time graph and the time axis, therefore, distance travelled by the first car before it stopes, i.e., s 1 = area of Δ O A B = O A × O B 2 = 14.4 × 5 2 = 36 ...

A driver of a car travelling at 52 km h^-1 applies the brakes and accelerates uniformly in the opposite direction. The car stops in 5 s. Another driver going at 3 km h^-1 in another car applies his brakes slowly and stops in 10 s. On the same graph paper, plot the speed versus time graphs for the two cars. Which of the two cars travelled farther after the brakes were applied? 5. A driver of a car travelling at 52 km h applies the brakes and accelerates uniformly in the opposite direction. The car stops in 5 s. Another driver going at 3 km h' in another car applies! his brakes slowly and stops in 10 s. On the same graph paper, plot the speed versus time graphs for the two cars. Which of the two cars travelled farther after the brakes were applied? abito

A driver of a car travelling at 52 km h–1 applies the brakes and accelerates uniformly in the opposite direction. The car stops in 5 s. Another driver going at 34 km h–1 in another car applies his brakes slowly and stops in 10 s. On the same graph paper, plot the speed versus time graphs for the two cars. Which of the two cars travelled farther after the brakes were applied? from Science Motion Class 9 CBSE Fig. shows the distance-time graph of three objects A, B and C. Study the graph and answer the following questions: (a) Which of the three is travelling the fastest? (b) Are all three ever at the same point on the road? (c) How far has C travelled when B passes A? (d) How far has B travelled by the time it passes C? A driver of a car travelling at 52 km h –1 applies the brakes and accelerates uniformly in the opposite direction. The car stops in 5 s. Another driver going at 34 km h –1 in another car applies his brakes slowly and stops in 10 s. On the same graph paper, plot the speed versus time graphs for the two cars. Which of the two cars travelled farther after the brakes were applied?