A rectangular courtyard is 18m 72

GIVEN: A rectangular yard is 18 m 72 cm long and 13 m 20 cm broad .It is to be paved with square tiles of the same size. TO FIND: Least possible number of such tiles. Length of the yard = 18 m 72 cm = 1800 cm + 72 cm = 1872 cm (∵ 1 m = 100 cm) Breadth of the yard =13 m 20 cm = 1300 cm + 20 cm = 1320 cm The size of the square tile of same size needed to the pave the rectangular yard is equal the HCF of the length and breadth of the rectangular yard. Prime factorisation of 1872 = 2 4 × 3 2 × 13 Prime factorisation of 1320 = 2 4 × 3 2 × 13 HCF of 1872 and 1320 = 2 3 × 3 = 24 ∴ Length of side of the square tile = 24 cm Number of tiles required = Area of each tile Area of the courtyard ​ = ( S i d e ) 2 Lenght × Breadth ​ = ( 24 c m ) 2 1872 c m × 1320 c m ​ = 4290 Thus, the least possible number of tiles required is 4290. A rectangular courtyard is 18 m 72 cm long and 13 m 20 cm broad. it is to be paved with square tiles of the same size. Find the least possible number of such tiles. Updated On May 7, 2023 Topic Real Numbers Subject Mathematics Class Class 10 Answer Type Text solution:1 Video solution: 1 Upvotes 132 Avg. Video Duration 7 min

Length of the courtyard = 18 m 72 cm = [18(100) + 72] cm [As, 1 m = 100 cm] = 1872 cm The breadth of the courtyard = 13 m 20 cm = [13(100) + 20] cm = 1320 cm To find the maximum edge of the tile we need to calculate HCF of length and breadth, Using Euler’s division lemma: a = pq + r where 0 ≤ r ≤ p 1872 = 1320 × 1 + 552 As 'r' is not equals to 0, So apply Euler's division on 1320 and 552, 1320 = 552 × 2 + 216 As 'r' is not equals to 0, So apply Euler's division on 552 and 216, 552 = 216 × 2 + 120 As 'r' is not equals to 0, So apply Euler's division on 216 and 120, 216 = 120×1 + 96 As 'r' is not equals to 0, So apply Euler's division on 120 and 96, 120 = 96 ×1 + 24 As 'r' is not equals to 0, So apply Euler's division on 96 and 24, 96 = 24 × 4 + 0 Therefore HCF of 1872 and 1320 is 24 Maximum edge can be 24 cm. Number of tile = \(\frac\) = 4290 tiles

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A rectangular perk is to be designed whose breadth is 3m less than its lenght . its area is to be 4 square metre more than the area of a park that has already been made in the shape of an isosceles triangle with its base as the breadth of rectangular park and of altitude 12 m . find length and breadth of rectangular park? Question Description A rectangular courtyard is 18 metre and 72 centimetre long and 13m 20cm broad it is to be paved with square tiles of the same size. find the least possible number of such tiles? for Class 10 2023 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A rectangular courtyard is 18 metre and 72 centimetre long and 13m 20cm broad it is to be paved with square tiles of the same size. find the least possible number of such tiles? covers all topics & solutions for Class 10 2023 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rectangular courtyard is 18 metre and 72 centimetre long and 13m 20cm broad it is to be paved with square tiles of the same size. find the least possible number of such tiles?. Solutions for A rectangular courtyard is 18 metre and 72 centimetre long and 13m 20cm broad it is to be paved with square tiles of the same size. find the least possible number of such tiles? in English & in Hindi are available as part of our courses for Class 10. Download more important topics, notes, lectures and moc...

Finding the least number of tiles required: Given that, Length = 1872 c m Width = 1320 c m The edge of the square tile must be the common divisor of the dimensions of the courtyard. So, the maximum edge of square tile = HCF of 1872 and 1320 = 24 c m So, the required number of tiles = a r e a o f c o u t y a r d A r e a o f s q u a r e t i l e = 1872 × 1320 24 2 = 4290 Thus, the least number of tiles required to cover the courtyard is 4290 .