Ayush and deeksha made pictures. ayush made his picture on a rectangular sheet of length 60 cm and breadth of 20 cm while deeksha made hers on a rectangular sheet of length 40 cm and breadth 35 cm. both these pictures have to be separately framed. find the difference between their costs of framing, if the cost of framing is ₹3 per cm.

  1. Ayush made his picture on a rectangular sheet of length 60 cm and breadth 20cm wide, area of picture is
  2. gemh111.pdf
  3. NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area InText Questions
  4. NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion
  5. CBSE Class 7 Ncert Maths Book perimeter and area chapter 11


Download: Ayush and deeksha made pictures. ayush made his picture on a rectangular sheet of length 60 cm and breadth of 20 cm while deeksha made hers on a rectangular sheet of length 40 cm and breadth 35 cm. both these pictures have to be separately framed. find the difference between their costs of framing, if the cost of framing is ₹3 per cm.
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Ayush made his picture on a rectangular sheet of length 60 cm and breadth 20cm wide, area of picture is

Given : ⬤ Length of Rectangular Sheet is 60 cm. ⬤ Breadth of Rectangular Sheet is 20 cm .To Find : ⬤ Area of Rectangle .Formula Used : • l = length • b = breadth Solution : According to the Formula :- l × b 60 × 20 1200 Therefore , The Area of the Rectangular Sheet is 1200 cm² . ═════════════════════════Related Formulas : • Perimeter of Rectangle = 2 (l + b) • Area of Square = Side × Side • Area of Rectangle = l × b • Perimeter of Square = 4 × Side • Diagonal of Rectangle = √l² + b² • Area of Triangle = 1/2 × b × h • Area of Parallelogram = b × h ═════════════════════════

gemh111.pdf

Page 1 : 11.1 INTRODUCTION, , be NC, re ER, pu T, bl, is, he, d, , Perimeter and, Area, In Class VI, you have already learnt perimeters of plane figures and areas of squares and, rectangles. Perimeter is the distance around a closed figure while area is the part of plane or, region occupied by the closed figure., In this class, you will learn about perimeters and areas of a few more plane figures., AND, , RECTANGLES, , ©, , 11.2 SQUARES, , no, tt, , o, , Ayush and Deeksha made pictures. Ayush made his picture on a rectangular sheet of length, 60 cm and breadth 20 cm while Deeksha made hers on a rectangular sheet of length 40 cm, and breadth 35 cm. Both these pictures have to be separately framed and laminated., Who has to pay more for framing, if the cost of framing is ` 3.00 per cm?, If the cost of lamination is ` 2.00 per cm2, who has to pay more for lamination?, For finding the cost of framing, we need to find perimeter and then multiply it by the rate, for framing. For finding the cost of lamination, we need to find area and then multiply it by the, rate for lamination., , TRY THESE, What would you need to find, area or perimeter, to answer the following?, 1. How much space does a blackboard occupy?, 2. What is the length of a wire required to fence a rectangular flower bed?, 3. What distance would you cover by taking two rounds of a triangular park?, 4. How much plastic sheet do you need to cover a rectangular swimming pool?, Do you remember,, Perimeter of a regular p...

NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area InText Questions

Question 1. Ayush and Deeksha made pictures. Ayush made his picture on a rectangular sheet of length 60 cm and breadth 20 cm while Deeksha made hers on a rectangular sheet of length 40 cm and breadth 35 cm. Both of these pictures have to be separately framed and laminated. Who has to pay more for framing, if the cost of framing is ₹ 3.00 per cm? If the rate of lamination is ₹ 2.00 per cm 2, who has to pay more for lamination? Solution: For finding the cost of framing, we need to find the perimeter and then multiple it by the rate for framing. In case of Ayush : Perimeter of the rectangular sheet = 2 (Length + Breadth) = 2 × (60 + 20) cm = 2 × 80 cm = 160 cm ∴ Cost of framing at the rate of ₹ 3 per cm = ₹ (3 × 160) = ₹ 480 In case of Deeksha : Perimeter of the rectangular sheet = 2 × (40 + 35) cm = 2 × 75 cm = 150 cm ∴ Cost of framing at the rate of ₹ 3 per cm = ₹ (3 × 150) = ₹ 450 Thus, Ayush paid more for framing (as 480 > 450). For finding the cost of lamination, we need to find the area and then multiply it by the rate for lamination. In the case of Ayush : Area of the rectangular sheet = (60 × 20) cm 2 =1200 cm 2 ∴ Cost of lamination at the rate of ₹ 2 per cm 2 = ₹ (2 × 1200) = ₹ 2400 In the case of Deeksha : Area of the rectangular sheet = (40 × 35) cm 2 = 1400 cm 2 ∴ Cost of lamination at the rate of ₹ 2 per cm 2 = ₹ (2 × 1400) = ₹ 2800 Thus, Deeksha paid more for lamination (as 2800 > 2400). Try These (Page 205) Question 1. What would you need to find, area, or peri...

NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion

NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion are discussed in this article. These NCERT solutions are created by the expert team at careers360 considering the latest CBSE syllabus 2023. In our daily life, we compare things like he is taller than me by 10 cm, Ramesh got double of my marks in Maths. The first statement is a comparison which means that the difference in height of both is 10 cm. The second statement is showing the ratio of marks. You can say that the ratio of marks obtained by Ramesh and it is 2: 1. In this article, you will get CBSE NCERT solutions for Class 6 Maths chapter 12 Ratio and Proportion. Table of contents It is advisable to also cover all the topics of NCERT Class 6 Maths Books to score well. If comparing quantities do not have the same unit, first convert them into the same unit and then find the ratio. Students must try to complete the NCERT Class 6 Maths Syllabus in at the earliest. You should try to solve all the NCERT questions by yourself so you won't these silly mistakes. You can take help from the NCERT Solutions for Class 6. Question:1 Saurabh takes 15 minutes to reach school from his house and Sachin takes one hour to reach school from his house. Find the ratio of the time taken by Saurabh to the time taken by Sachin. Answer: Time taken by Saurabh = 15 minutes Time taken by Sachin= 1 hour = 60 minutes. To find ratios we have to convert the given quantit...

CBSE Class 7 Ncert Maths Book perimeter and area chapter 11

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