Class 10 maths chapter 6 exercise 6.2

NCERT Solutions for Class 10 Maths Chapter 6 - Triangles Exercise 6.3 The CBSE Class 10 Chapter 6 Triangles have a total of 6 exercises. The pdf containing the NCERT Solutions of the third exercise, Exercise 6.3, is available here. The solution, apart from the pdf format, is also available below. At BYJU’S, our subject experts solve the questions in the There are plenty of questions in the NCERT textbook intended for the students to solve and practice. To score high marks in the Class 10 examination, solving and understanding all the Download PDF carouselExampleControls112 Previous Next Access other exercise solutions of class 10 Maths Chapter 6- Triangles Access Answers of Maths NCERT class 10 Chapter 6 – Triangles Exercise 6.3 1. State which pairs of triangles in Figure are similar. Write the similarity criterion used by you for answering the question and also write the pairs of similar triangles in the symbolic form: Solution: (i) Given, in ΔABC and ΔPQR, ∠A = ∠P = 60° ∠B = ∠Q = 80° ∠C = ∠R = 40° Therefore by AAA similarity criterion, ∴ ΔABC ~ ΔPQR (ii) Given, in  ΔABC and ΔPQR, AB/QR = 2/4 = 1/2, BC/RP = 2.5/5 = 1/2, CA/PA = 3/6 = 1/2 By SSS similarity criterion, ΔABC ~ ΔQRP (iii) Given, in ΔLMP and ΔDEF, LM = 2.7, MP = 2, LP = 3, EF = 5, DE = 4, DF = 6 MP/DE = 2/4 = 1/2 PL/DF = 3/6 = 1/2 LM/EF = 2.7/5 = 27/50 Here , MP/DE = PL/DF ≠LM/EF Therefore, ΔLMP and ΔDEF are not similar. (iv) In ΔMNL and ΔQPR, it is given, MN/QP = ML/QR = ...

1.2 Download Toppr – Best Learning App for Class 5 to 12 NCERT Solutions for Class 10 Maths Chapter 6 – Triangles Exercise 6.2 Class 10 Maths Chapter 6- Triangle is an important lesson from the Board exam point of view. This chapter deals with similar figures with special reference to triangles. Furthermore, students can easily study the similarity of triangles. After this chapter, they can successfully apply this knowledge for solving problems related to the topic. Similarly, it will be a step further into the study of triangles in detail for students. Toppr provides free study materials, the last 10 years of question papers, 1000+ hours of video lectures for free. So, download Toppr for Download Download Triangles – Exercise 6.2 NCERT Solutions for Class 10 Maths Chapter 6 – Triangles Exercise 6.2 contains ample questions for student’s practice. Most of the questions focus on applying different theorems to solve the problems. Furthermore, these questions are a step further into the chapter dealing with complex topics. The solved examples given above will help the students in solving the questions easily. Furthermore, NCERT Solutions for Class 10 Maths Chapter 6 – Triangles Exercise 6.2 covers one section of the chapter. The section is 6.3 which is the Similarity of Triangles. Thus, it tests the knowledge of students based on what they learned in this specific section. The PDF for NCERT Solutions for Class 10 Maths Chapter 6 – Triangles Exercise 6.2 is provided by Toppr f...

NCERT Solutions for Class 10 Maths exercise 6.2- The definition of a triangle is a polygon with three angles and three sides. A triangle's interior angles add up to 180 degrees, while its exterior angles add up to 360 degrees.The sum of the squares of two sides of a right triangle equals the square of the hypotenuse of the triangle, according to Pythagoras' theorem.Triangles examine the conditions of similarity in triangles, i.e., if their corresponding angles and sides are in the same proportion. Equiangular triangles are those in which the corresponding angles of two different triangles are equal. Table of contents When a parallel line is drawn along one of the triangle's sides and intersects the other two sides at certain points, the two sides are divided in the same proportion. Any line that divides the two sides of a triangle in the same ratio is parallel to the third side. Along with NCERT book Class 10 Maths chapter 6 exercise 6.2 the following exercises are also present. • • • • Q10 Show that ABCD is a trapezium. Answer: Draw a line EF passing through point O such that Given : In , we have So, by using basic proportionality theorem, However, its is given that Using equation 1 and 2 , we get (By basic proportionality theorem) Therefore, ABCD is a trapezium. More About NCERT Solutions for Class 10 Maths Exercise 6.2 NCERT solutions Class 10 Maths chapter 6 exercise 6.2 triangles necessitates a thorough understanding of the underlying theorems. As a result, students a...

Observe the following frequency polygon and write the answers of the questions below it. (1) Which class has the maximum number of students ? (2) Write the classes having zero frequency. (3) What is the class-mark of the class, having frequency of 50 students ? (4) Write the lower and upper class limits of the class whose class mark is 85. (5) How many students are in the class 80-90? The annual investments of a family are shown in the adjacent pie diagram. Answer the following questions based on it. (1) If the investment in shares is ₹ 2000, find the total investment. (2) How much amount is deposited in the bank? (3) How much more money is invested in immovable property than in mutual fund? (4) How much amount is invested in post? Find the correct answer from the alternatives given. No. of trees planted by each student 1 - 3 4 - 6 7 - 9 10 - 12 No. of students 7 8 6 4 The above data is to be shown by a frequency polygon. The coordinates of the points to show number of students in the class 4-6 are . . . . • (4, 8) • (3, 5) • (5, 8) • (8, 4) Shaalaa.com has the Maharashtra State Board Mathematics Maths 1 Algebra 10th Standard SSC Maharashtra State Board Maharashtra State Board solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. Balbharati textb...

AP State Board Syllabus AP State Syllabus SSC 10th Class Maths Solutions 6th Lesson Progressions Exercise 6.2 10th Class Maths 6th Lesson Progressions Ex 6.2 Textbook Questions and Answers Question 1. Fill in the blanks in the following table, given that ‘a’ is the first term, d the common difference and an the nth term of the A.P: Answer: Question 2. Find the i) 30th term of the A.P.: 10, 7, 4,…… ii) 11th term of the A.P.: -3, –\(\frac\) = 10 ⇒ n = 10 + 1 ∴ In 11 th year his salary reached Rs. 7000. Categories Post navigation