Class 10th maths chapter 3 exercise 3.4

NCERT Solutions for Class 10 Maths Chapter 3 - Pair of Linear Equations in Two Variables Exercise 3.2 NCERT Solutions for Class 10 Maths Exercise 3.2 Chapter 3 Linear Equations In Two Variables is the best way students can prepare the concept. These Solutions to all the exercises mentioned in the textbook are provided in the NCERT Solutions of Class 10 Maths. It also contains several other questions for practice. These questions will help the students prepare well for the board examinations. Solutions of NCERT act as a guide during preparation for the examinations. The students can refer to them in case of any doubts. They can practise and evaluate themselves and work on their weak points thereafter. Previous Next NCERT Solutions for Class 10 Maths Chapter 3 – Pair of Linear Equations in Two Variables Exercise 3.2 1. Form the pair of linear equations in the following problems, and find their solutions graphically. (i) 10 students of Class X took part in a Mathematics quiz. If the number of girls is 4 more than the number of boys, find the number of boys and girls who took part in the quiz. (ii) 5 pencils and 7 pens together cost 50, whereas 7 pencils and 5 pens together cost 46. Find the cost of one pencil and that of one pen. Solution: (i) Let there be x number of girls and y number of boys. As per the given question, the algebraic expression can be represented as follows. x +y = 10 x– y = 4 Now, for x+y = 10 or x = 10−y, the solutions are; For x – y = 4 or x = 4 ...

Transcript Ex 3.3, 1 (Elimination) Solve the following pair of linear equations by the elimination method and the substitution method : (i) x + y = 5 and 2x – 3y = 4 x + y = 5 2x – 3y = 4 Multiplying equation (1) by 2 2(x + y) = 2 × 5 2x + 2y = 10 Solving (3) and (2) by Elimination –5y = –6 5y = 6 y = 𝟔/𝟓 Putting y = 6/5 in (1) x + y = 5 x + 6/5 = 5 x = 5 – 6/5 x = (5 × 5 − 6)/5 x = (25 − 6)/5 x = 𝟏𝟗/𝟓 Hence, x = 19/5,𝑦=6/5 Ex 3.3, 1 (Substitution) Solve the following pair of linear equations by the elimination method and the substitution method : (i) x + y = 5 and 2x – 3y = 4 x + y = 5 2x – 3y = 4 From (1) x + y = 5 x = 5 – y Substituting x in (2) 2x – 3y = 4 2 (5 – y) – 3y = 4 10 – 2y – 3y = 4 10 – 5y = 4 –5y = 4 – 10 –5y = −6 y = (−6)/(−5) y = 𝟔/𝟓 Putting y = 6/5 in equation (1) x + y = 5 x + 6/5 = 5 x = 5 – 6/5 x = (5 × 5 − 6)/5 x = (25 − 6)/5 x = 𝟏𝟗/𝟓 Hence, x = 19/5,y=6/5 is the solution of the equations Show More

NCERT Solutions for Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables NCERT solutions for class 10 maths chapter 3 Pair of Linear Equations in Two Variables enables the students to understand and explore simple ways to solve linear equations. This is a chapter that is widely used in industrial applications. It is used to solve questions based on speed-distance, money percentage, age, force-pressure, and so on. The kids will cover algebraic methods of solving a pair of linear equations in two variables, like the elimination method, the cross-multiplication method, and equations reducible to a pair of linear equations in two variables. The NCERT solutions class 10 maths chapter 3 Pair of Linear Equations in Two Variables teaches that the general form of a • • • • • • • NCERT Solutions for Class 10 Maths Chapter 3 PDF Linear equations are implemented to overcome real-world problems in a variety of fields. To evaluate this type of equation, we must either apply the substitution technique or mathematical elimination, which is explained with appropriate examples in the ☛ Download Class 10 Maths NCERT Solutions Chapter 3 NCERT Class 10 Maths Chapter 3 Download PDF NCERT Solutions for Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables A • Class 10 Maths Chapter 3 Ex 3.1 - 3 Questions • Class 10 Maths Chapter 3 Ex 3.2 - 7 Questions • Class 10 Maths Chapter 3 Ex 3.3 - 3 Questions • Class 10 Maths Chapter 3 Ex 3.4 - 2 Questions • Class 10 Maths Chapte...

The taxi charges in a city consist of a fixed charge together with the charge for the distance covered. For a distance of 10 km, the charge paid is Rs 105 and for a journey of 15 km, the charge paid is Rs 155. What are the fixed charges and the charge per km? How much does a person have to pay for travelling a distance of 25 km? Form the pair of linear equations in the following problems, and find their solutions (if they exist) by the elimination method : Meena went to a bank to withdraw Rs 2000. She asked the cashier to give her Rs50 and Rs 100 notes only. Meena got 25 notes in all. Find how many notes of Rs 50 and Rs 100 she received. Form the pair of linear equations in the following problems, and find their solutions (if they exist) by the elimination method : A lending library has a fixed charge for the first three days and an additional charge for each day thereafter. Saritha paid Rs 27 for a book kept for seven days, while Susy paid Rs 21 for the book she kept for five days. Find the fixed charge and the charge for each extra day Form the pair of linear equations in the following problems and find their solutions (if they exist) by any algebraic method : A part of monthly hostel charges is fixed and the remaining depends on the number of days one has taken food in the mess. When a student A takes food for 20 days she has to pay Rs 1000 as hostel charges whereas a student B, who takes food for 26 days, pays Rs 1180 as hostel charges. Find the fixed charges and the c...