Class 7 maths chapter 8 exercise 8.1 solutions

NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities * According to the CBSE Syllabus 2023-24, this chapter has been renumbered as Chapter 7. NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities download the PDF given below. If students aim to score higher in Maths, it requires the right amount of practice for every topic. More marks can be achieved by referring to Chapter 8 – Comparing Quantities contains 3 exercises, and the NCERT Solutions for Class 7 Maths available on this page provide solutions to the questions present in the exercises. Following are the concepts covered in this chapter of Class 7 Maths • Equivalent Ratios • Percentage – Another Way of Comparing Quantities • Converting Fraction Numbers to Percentage • Converting Decimals to Percentage • Converting percentage to Fraction or Decimals • Use of Percentage • Interpreting Percentage • Converting Percentage to “How Many” • Ratios to Percent • Increase or Decrease as Percent • Price Related to an Item or Buying and Selling • Profit or Loss as a Percentage • Charge Given on Borrowed Money or Simple Interest • Interest for Multiple Years Download PDF carouselExampleControls112 Previous Next Access Exercises to NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Access Answers to Maths NCERT Solutions for Class 7 Chapter 8 – Comparing Quantities Exercise 8.1 Page: 157 1. Find the ratio of: (a) ₹ 5 to 50 paise Solution:- We know that, ₹ 1 = 100 paise Then, ₹...

NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Exercise 8.1 * According to the CBSE Syllabus 2023-24, this chapter has been renumbered as Chapter 7. NCERT Solutions for Class 7 Maths Exercise 8.1 Chapter 8 Comparing Quantities in simple PDF are given here. This exercise of Download PDF carouselExampleControls112 Previous Next  Access Other Exercises of NCERT Solutions for Class 7 Maths Chapter 8 – Comparing Quantities Access Answers to NCERT Class 7 Maths Chapter 8 – Comparing Quantities Exercise 8.1 1. Find the ratio of: (a) ₹ 5 to 50 paise Solution:- We know that, ₹ 1 = 100 paise Then, ₹ 5 = 5 × 100 = 500 paise Now we have to find the ratio, = 500/50 = 10/1 So, the required ratio is 10:1. (b) 15 kg to 210 g Solution:- We know that, 1 kg = 1000 g Then, 15 kg = 15 × 1000 = 15000 g Now we have to find the ratio, = 15000/210 = 1500/21 = 500/7 … [∵divide both by 3] So, the required ratio is 500:7. (c) 9 m to 27 cm Solution:- We know that, 1 m = 100 cm Then, 9 m = 9 × 100 = 900 cm Now we have to find the ratio, = 900/27 = 100/3 … [∵divide both by 9] So, the required ratio is 100:3. (d) 30 days to 36 hours Solution:- We know that, 1 day = 24 hours Then, 30 days = 30 × 24 = 720 hours Now we have to find the ratio, = 720/36 = 20/1 … [∵divide both by 36] So, the required ratio is 20:1. 2. In a computer lab, there are 3 computers for every 6 students. How many computers will be needed for 24 students? Solution:- From the question, it is ...

NCERT Solutions Class 7 Maths Chapter 8 Comparing Quantities In our daily lives, we often come across situations where we are compelled to compare two quantities for various reasons. It may be any quantity like weight, age, grades, height, etc. Students must be aware of this concept where they must have tried calculating how many times one measurable quantity stands against another. The NCERT Solutions for The students will come across some important facts like in order to compare any two quantities their unit has to be the same. Also, in case any two ratios are equivalent, then the respective four quantities are said to be in proportion. The pdf form of the Class 7 maths NCERT solutions chapter 8 Comparing Quantities are given below and also find some of these in the exercises given below. • • • NCERT Solutions for Class 7 Maths Chapter 8 PDF The students, while studying the NCERT solutions Class 7 maths chapter 8 Comparing Quantities, will find the concepts relatable to things which they encounter in real life, which will make it interesting for them to pick up the concepts easily. The free pdf file for the chapter with the relevant exercises can be downloaded from the link given here: ☛ Download Class 7 Maths NCERT Solutions Chapter 8 Comparing Quantities NCERT Class 7 Maths Chapter 8 Download PDF NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities The • Class 7 Maths Chapter 8 Ex 8.1 - 3 Questions • Class 7 Maths Chapter 8 Ex 8.2 - 10 Questions • Class 7 M...

NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 • • • NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Exercise 8.3 Ex 8.3 Class 7 Maths Question 1. Tell what is the profit or loss in the following transactions. Also find profit per cent or loss per cent in each case. (a) Gardening shears bought for ₹ 250 and sold for ₹ 325. (b) A refrigerator bought for ₹ 12,000 and sold at ₹ 13,500. (c) A cupboard bought for ₹ 2,500 and sold at ₹ 3,000. (d) A skirt bought for ₹ 250 and sold at ₹ 150. Solution: (a) Here, CP = ₹ 250 SP = ₹ 325 Since SP > CP ∴ Profit = SP – CP = ₹ 325 – ₹ 250 = ₹ 75 Hence, the required profit = ₹ 75 and Profit per cent = 30% (b) Here, CP = ₹ 12,000 SP = ₹ 13,500 Since SP > CP ∴ Profit = SP – CP = ₹ 13,500 – ₹ 12,000 = ₹ 1,500 Hence, the required profit = ₹ 1500 × 100 profit % = \(12 \frac\) = ₹1125 Amount = Principal + Interest = ₹ 7500 + 11125 = ₹ 8625 Hence, the required amount = ₹ 8625. Ex 8.3 Class 7 Maths Question 10. What rate gives ₹ 280 as interest on a sum of ₹ 56,000 in 2 years? Solution: Given: Principal = ₹ 56,000 Interest = ₹280 Time = 2 years Rate = ? Hence, the required rate = 0.25% Ex 8.3 Class 7 Maths Question 11. If Meena gives an interest of ₹ 45 for one year at 9% rate p.a. What is the sum she has borrowed? Solution: Given: Interest = ₹ 45 Time = 1 year Rate = 9% p.a. Hence, the required sum = ₹ 500. Filed Under: Tagged With: