Class 8 maths ch 11 ex 11.1

Class 8 Maths NCERT (https://ncert.nic.in/) Chapter 11 Direct and Inverse Proportions all exercises in English Medium as well as Hindi Medium are given below to download in PDF format. For any inconvenience regarding website, please call us, we will immediately solve the problem. Offline apps 2023-24 are more helpful in case of slow internet. In Chapter 11 Direct and Inverse Proportions, we will study the applications in daily life. When the two quantities increase or decrease simultaneously, it is called Direct Proportion whereas if other quantity decreases for increasing values of one quantity, is is called inverse proportion. In this chapter most of the word problems are based on daily life only and easier way to solve them is also given. According to the Vidyaarthee pahale dee gaee raashiyon kee ek saranee bana len aur phir jaanch le ki donon raashiyaan saath saath badh raheen hain ya ek badh rahee aur doosaree ghat rahee hai. udahaaran ke lie ham anaar ke mooly ko hee len. jaise – jaise aanar kee maatra mein vrddhi hotee hai, vaise – vaise usake mooly mein bhee vrddhi hotee hai. atah yahaan seedha anupaat hai arthaat anaar kee maatra aur usaka mooly anukramanupaatee hain.

Contents • 1 Selina Concise Mathematics Class 8 ICSE Solutions Chapter 11 Algebraic Expressions (Including Operations on Algebraic Expressions) • 1.1 Algebraic Expressions Exercise 11A – Selina Concise Mathematics Class 8 ICSE Solutions • 1.2 Algebraic Expressions Exercise 11B – Selina Concise Mathematics Class 8 ICSE Solutions • 1.3 Algebraic Expressions Exercise 11C – Selina Concise Mathematics Class 8 ICSE Solutions • 1.4 Algebraic Expressions Exercise 11D – Selina Concise Mathematics Class 8 ICSE Solutions • 1.5 Algebraic Expressions Exercise 11E – Selina Concise Mathematics Class 8 ICSE Solutions • 1.5.1 Selina Concise Mathematics Class 8 ICSE Solutions Selina Concise Mathematics Class 8 ICSE Solutions Chapter 11 Algebraic Expressions (Including Operations on Algebraic Expressions) Selina Publishers Concise Mathematics Class 8 ICSE Solutions Chapter 11 Algebraic Expressions (Including Operations on Algebraic Expressions) Algebraic Expressions Exercise 11A – Selina Concise Mathematics Class 8 ICSE Solutions Question 1. Separate the constants and variables from the following : Solution: Question 2. Write the number of terms in each of the following polynomials. (i) 5x 2 + 3 x ax (ii) ax ÷ 4 – 7 (iii) ax – by + y x z (iv) 23 + a x b ÷ 2. Solution: Question 3. Separate monomials, binomials, trinomials and polynomials from the following algebraic expressions : Solution: Question 4. Write the degree of each polynomial given below : Solution: Question 5. Write the coefficien...

Question 1. Rakesh can do a piece of work in 20 days. How much work can he do in 4 days ? Solution: Rakesh can do it in 20 days = 1 his 1 day’s work = \(\frac \) Question 4. Mohan takes 9 hours to mow a large lawn. He and Sohan together can mow it in 4 hours. How long will Sohan take to mow the lawn if he works alone ? Solution: Question 5. Sita can finish typing a 100 page document in 9 hours, Mita in 6 hours and Rita in 12 hours. How long will they take to type a 100 page document if they work together? Solution: Sita can do a work in 1 hour = \(\frac \) Question 25. Two taps A and B can fill an overhead tank in 10 hours and 15 hours respectively. Both the taps are opened for 4 hours and then B is turned off. How much time will A take to fill the remaining tank ? Solution: Question 26. A pipe can fill a cistern in 10 hours. Due to a leak in the bottom, it is filled in 12 hours. When the cistern is full, in how much time will it be emptied by the leak? Solution: Question 27. A cistern has two inlets A and B which can fill it in 12 hours and 15 hours respectively. An outlet can empty the full cistern in 10 hours. If all the three pipes are opened together in the empty cistern, how much time will they take to fill the cistern completely ? Solution: Question 28. A cistern can be filled by a tap in 4 hours and emptied by an outlet pipe in 6 hours. How long will it take to fill the cistern of both the tap and the pipe are opened together ? Solution: Hope given If you have any ...

Rajasthan Board RBSE Class 8 Maths Solutions Chapter 11 Mensuration Ex 11.1 Question 1. A square and a rectangular field with measurements as given in the figure have the same perimeter. Which field has a larger area? Answer: Let x be the breadth of the rectangle. It is given that the perimeter of rectangle = perimeter of square ∴ 2(80 + x) = 4 × 60 or 80 + x = 120 or x = 120 - 80 = 40 i.e.,breadth of the rectangle = 40 m Now, area of the square = (60 × 60) m 2 = 3600 m 2 and, the area of the rectangle = (40 × 80) m 2 = 3200 m 2 Since 3600 m 2> 3200 m 2 ∴ Area of the square field (a) is greater. Question 2. Kaushik has a square plot with the measurement as shown in the figure. She wants to construct a house in the middle of the plot. A garden is developed around the house. Find the total cost of developing a garden around the house at the rate of ₹ 55 per m 2. Answer: Area of garden = Area of the outer square - Area of the inner rectangle = 25 × 25 m 2 - 20 × 15 m 2 = (625 - 300) m 2 = 325 m 2 Cost of developing a garden @ ₹ 55 per sq. meter = ₹ (55 × 325) = ₹ 17,875 Question 3. The shape of a garden is rectangular in the middle and semi circular at the ends as shown in the diagram. Find the area and the perimeter of this garden [Length of rectangle is 20 - (3.5 + 3.5) metres]. Answer: Total area of the garden = Area of the rectangular portion + The sum of the areas of the pair of semicircle = (13 × 7)m 2 + (2 × \(\frac\) = 4.4 cm ∴ Perimeter of the figure = 4.4 cm + 2 cm ...

NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.1, are part of NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.1 Question 1. A square and a rectangular field with measurements as given in the figure have the same perimeter. Which field has a larger area? Solution. Area of the square field = a x a = 60 m x 60 m = 3,600 \( \) = 45000. Question 5. An ant is moving around a few food pieces of different shapes scattered on the floor. For which food-piece would the ant have to take a longer round? Remember, the circumference of a circle can be obtained by using the expression c = 2πr, where r is the radius of the circle. Solution. We hope the NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.1, help you. If you have any query regarding NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.1, drop a comment below and we will get back to you at the earliest. Filed Under: Tagged With:

NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.1 are part of • • • Board CBSE Textbook NCERT Class Class 8 Subject Maths Chapter Chapter 11 Chapter Name Mensuration Exercise Ex 11.1 Number of Questions Solved 5 Category NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.1 Ex 11.1 Class 8 Maths Question 1. A square and a rectangular field with measurements as given in the following figure have the same perimeter. Which field has a larger area? Solution: Let x be the breadth of the rectangle. It is given that the perimeter of a rectangle = perimeter of the square. ∴ 2 (80 + x) = 4 x 60 ⇒ 80 + x = 120 ⇒ x = 120 – 80 =40 i.e., breadth of the rectangle = 40 m Now area of the square = (60 x 60) m = 3600 m 2 and the area of the rectangle = (40 x 80) m 2 = 3200 m 2 Hence, the square field has a larger area. Ex 11.1 Class 8 Maths Question 2. Mrs. Kaushik has a square plot with the measurement as shown in the figure. She wants to construct a house in the middle of the plot. A garden is developed around the house. Find the total cost of developing a garden around the house at the rate of ₹ 55 per m 2. Solution: Area of the garden = Area of the outer square – Area of the inner rectangle = 25 x 25 m 2– 20 x 15 m 2 = (625 – 300) m 2 = 325 m 2 Cost of developing a garden at the rate of ₹ 55 per sq. metre = ₹ (55 x 325) = ₹ 17,875 Ex 11.1 Class 8 Maths Question 3. The shape of a garden is rectangular in the middle and semi circular at the ends as shown in the d...

NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Exercise 11.1 NCERT Solutions for Class 8 Maths Chapter 11, Mensuration, consist of a set of questions and answers for all the textbook problems. All the solutions are prepared by BYJU’S experts, based on the latest CBSE syllabus and guidelines. The main aim is to give students the advantage of quality Download PDF carouselExampleControls112 Previous Next  Access Other Exercise Solutions of Class 8 Maths Chapter 11 Mensuration Access Answers to NCERT Class 8 Maths Chapter 11 Mensuration Exercise 11.1 Page number 171 1. A square and a rectangular field with measurements as given in the figure have the same perimeter. Which field has a larger area? Solution: Side of a square = 60 m (Given) And the length of rectangular field, l = 80 m (Given) According to the question, Perimeter of rectangular field = Perimeter of square field 2(l+b) = 4×Side (using formulas) 2(80+b) = 4×60 160+2b = 240 b = 40 Breadth of the rectangle is 40 m. Now, Area of Square field = (side) 2 = (60) 2 = 3600 m 2 And Area of Rectangular field = length×breadth = 80×40 = 3200 m 2 Hence, area of the square field is larger. 2. Mrs.Kaushik has a square plot with the measurement as shown in the figure. She wants to construct a house in the middle of the plot. A garden is developed around the house. Find the total cost of developing a garden around the house at the rate of Rs. 55 per m 2.  Solution: Side of a square plot = 25 m Formula: Area of squ...