Class 8 maths ex 8.2

NCERT Solutions for Class 11 Maths Chapter 8 Binomial Theorem Ex 8.2 are part of • Board CBSE Textbook NCERT Class Class 11 Subject Maths Chapter Chapter 8 Chapter Name Binomial Theorem Exercise Ex 8.2 Number of Questions Solved 12 Category NCERT Solutions for Class 11 Maths Chapter 8 Binomial Theorem Ex 8.2 Ex 8.2 Class 11 Maths Question 1. Find the coefficient of x 5 in (x + 3) 8 Solution. Suppose x 5 occurs in the (r + 1) th term of the expansion (x + 3) 8 Ex 8.2 Class 11 Maths Question 2. a 5 b 7in (a-2b) 12 Solution. Suppose a 5 b 7 occurs in the (r + 1) th term of the expansion (a – 2b) 12. Write the general term in the expansion of Ex 8.2 Class 11 Maths Question 3. (x 2 – y) 6 Solution. Ex 8.2 Class 11 Maths Question 4. (x 2 – yx) 12, x ≠ 0 Solution. We have given, (x 2– yx) 12 = (x 2 + (- yx)) 12, x ≠ 0 Ex 8.2 Class 11 Maths Question 5. Find the 4th term in the expansion of (x – 2y) 12. Solution. Ex 8.2 Class 11 Maths Question 6. Find the 13th term in the expansion of \(\) Solution. Ex 8.2 Class 11 Maths Question 9. In the expansion of (1 + a) m+n, prove that coefficients of a m and a n are equal. Solution. Ex 8.2 Class 11 Maths Question 10. The coefficients of the (r – 1) th, r th and (r + 1) th terms in the expansion of (x + 1 ) n are in the ratio 1: 3: 5. Find n and r. Solution. Ex 8.2 Class 11 Maths Question 11. Prove that the coefficient of x n in the expansion of (1 + x) 2n is twice the coefficient of x n in the expansion of (1 + x) 2n-1. Solution. Ex 8.2 Cla...

NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Ex 8.2 are part of • • Board CBSE Textbook NCERT Class Class 8 Subject Maths Chapter Chapter 8 Chapter Name Comparing Quantities Exercise Ex 8.2 Number of Questions Solved 10 Category NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Ex 8.2 Ex 8.2 Class 8 Maths Question 1. A man got a 10% increase in his salary. If his new salary is ₹ 1,54,000, find his original salary. Solution: Let the salary before increment be ₹ 100. Then, Increase in salary = ₹ 10 ∴ Increased salary = ₹ (100 +10) = ₹ 110 If increased salary is ₹ 110, original salary = ₹100 If increased salary is ₹ 154000, original salary = ₹ \(\left( \frac \times 154000 \right) \) = ₹ 14000 Hence, the salary of the man before increment was ₹ 140000. Ex 8.2 Class 8 Maths Question 2. On Sunday 845 people went to the Zoo. On Monday only 169 people went. What is the per cent decrease in the people visiting the Zoo on Monday? Solution: On Sunday the number of people went to Zoo = 845 On Monday the number of people went to Zoo = 169 ∴ Decrease in the people visiting the Zoo = (845-169) =676 Ex 8.2 Class 8 Maths Question 3. A shopkeeper buys 80 articles for ₹ 2,400 and sells them for a profit of 16%. Find the selling price of one article. Solution: CP of 80 articles = ₹ 24000 Ex 8.2 Class 8 Maths Question 4. The cost of an article is ₹ 15,500. ₹ 450 were spent on its repairs. If it is sold for a profit of 15%, find the selling price of the artic...

NCERT Solutions Class 8 Maths Chapter 8 Exercise 8.2 Comparing Quantities The NCERT solutions for Class 8 maths Chapter 8 Exercise 8.2 Comparing Quantities has many narratives built around the foundations of ratios and percentages. There are examples where the value of original quantity increases and one needs to find out the increase in The questions in Class 8 maths NCERT solutions Chapter 8 Exercise 8.2 are in the long format and they at times mask the applicability of the principle of ratios and percentages. These sums have provided hints too but it's more fun to ignore the hint initially and try the problem by yourself. These questions will help in developing the necessary logical skills, which will be needed to frame the elements of the problem in a proper mathematical equation. The pdf file of the questions in the ☛ Download NCERT Solutions Class 8 Maths Chapter 8 Exercise 8.2 Exercise 8.2 Class 8 Chapter 8 Download PDF More Exercises in Class 8 Maths Chapter 8 • • NCERT Solutions Class 8 Maths Chapter 8 Exercise 8.2 Tips The students need to understand how the introduction of percentages and ratios enriches the transfer of information. To be able to compare unlike quantities it's a great way to convert them to a standard scale. Percentages and Download Cuemath NCERT Solutions PDF for free and start learning! NCERT Video Solutions for Class 8 Maths Chapter 8 Exercise 8.2 Video Solutions for Class 8 Maths Chapter 8 Exercise 8.2

Table of Contents • • • • • • • • • • • • • • • • • • NCERT Solutions for Class 8 Maths Exercise 8.2 Class 8 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 8 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free. NCERT solutions for Class 8 Maths Comparing Quantities NCERT Solutions for Class 8 Maths Comparing Quantities Class –VIII Mathematics (Ex. 8.2) NCERT SOLUTION 1. A man got 10% increase in his salary. If his new salary is Rs.1,54,000, find his original salary. Ans. Let original salary be Rs.100. Therefore New salary i.e., 10% increase = 100 + 10 = Rs.110 New salary is Rs.110, when original salary = Rs.100 New salary is Rs.1, when original salary = New salary is Rs.1,54,000, when original salary = = Rs.1,40,000 Hence original salary is Rs. 1,40,000. NCERT Solutions for Class 8 Maths Exercise 8.2 2. On Sunday 845 people went to the Zoo. On Monday only 169 people went. What is the percent decrease in the people visiting the Zoo on Monday? Ans. On Sunday, people went to the Zoo = 845 On Monday, people went to the Zoo = 169 Number of decrease in the people = 845 – 169 = 676 Decrease percent = = 80% Hence decrease in the people visiting the Zoo is 80%. 3. A shopkeeper buys 80 articl...

Transcript Ex 8.2, 1 Find the 20th and nth terms of the G.P. 5/2, 5/4, 5/8,…. G.P. is 5/2, 5/4, 5/8,…. We know that an = arn – 1 where an = nth term of GP n is the number of terms a is the first term r is the common ratio Here, First term a = 5/2 Common ratio r = (5/4)/(5/2) = 5/4 × 2/5 = 1/2 We need to find nth term, nth term of GP = an = arn-1 Putting a = 5/2 , d = 1/2 = 5/2 (1/2)^(𝑛−1) = 5/2 (1/2^(𝑛−1) ) = (5/(〖2 (2〗^(𝑛−1)))) = 5/(2)"n − 1 + 1" = 5/2^𝑛 Hence, the nth term of GP is 5/2^𝑛 For 20th term of GP Putting n = 20 in an a20 = 5/2^20 Thus, 20th term of GP is 5/2^20 Show More

NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 • • • NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Exercise 8.2 Ex 8.2 Class 7 Maths Question 1. Convert the given fractional numbers to per cents: Solution: Ex 8.2 Class 7 Maths Question 2. Convert the given decimal fractions to per cents: (а) 0.65 (b) 2.1 (c) 0.02 (d) 12.35 Solution: (a) 0.65 = \(\frac \times 20=5\) matches Thus, the number of matches won by them = 5 Filed Under: Tagged With: