Exercise 13.2 class 10 in hindi

NCERT Solutions for Class 10 Maths Chapter 13 Exercise 13.4 Surface Areas & Volumes – Mensuration online in NCERT Solutions for Class 10 Maths Chapter 13 Exercise 13.4 If you need solutions in Hindi, Click for Class 10 Maths Exercise 13.4 Solutions in Hindi Medium To get the solutions in English, Click for Important Questions with Answers for Practice for Exams Surface areas and Volumes Exercise 13.4 • A bucket is in the form of a frustum of a cone and hold a 28.490 litres of water. The radii of the top and bottom are 28 cm and 21 cm respectively. Find the height of the bucket. [Answer: 15 cm] • A cone of radius 8cm and height 12cm is divided into two parts by a plane through the mid-point of its axis parallel to its base. Find the ratio of the volumes of the two parts. [Answer: 1:7 or 7:1] • The height of a cone is 60 cm. A small cone is cut off at the top by a plane parallel to the base and its volume is 1/64th the volume of original cone. Find the height from the base at which the section is made? [Answer: 45 cm] • The slant height of a frustum of a cone is 4 cm and the perimeter of its circular ends are18cm and 6 cm. Find the curved surface area of the frustum [use π = 22/7]. [Answer: 48 cm²] • A plumb line is a combination of which geometric shapes? [Answer: A cone with hemisphere] • The slant height of the frustum of a cone is 5 cm. If the difference between the radii of its two circular ends is 4cm. Write the height of the frustum. [Answer: 3 cm] • The slant height ...

NCERT Solutions for Class 10 Maths Chapter 13 - Surface Areas and Volumes Exercise 13.2 * According to the CBSE Syllabus 2023-24, this chapter has been renumbered as Chapter 12. NCERT Solutions for Class 10 Maths Chapter 13, Surface Areas and Volumes, Exercise 13.2, are available here in a downloadable PDF. The Topics covered in this article are according to the latest NCERT syllabus and guidelines. Therefore, students find the Download PDF carouselExampleControls112 Previous Next Access Other Exercise Solutions of Class 10 Maths Chapter 13 – Surface Areas and Volumes Access Answers to NCERT Class 10 Maths Chapter 13 – Surface Areas and Volumes Exercise 13.2 1. A solid is in the shape of a cone standing on a hemisphere, both having radii of 1 cm, and the height of the cone is equal to its radius. Find the volume of the solid in terms of π. Solution: Here, r = 1 cm, and h = 1 cm. The diagram is as follows. Now, Volume of solid = Volume of conical part + Volume of hemispherical part We know that the volume of cone = ⅓ πr 2h And, The volume of the hemisphere = ⅔πr 3 So, the volume of the solid will be = π cm 3 2. Rachel, an engineering student, was asked to make a model shaped like a cylinder with two cones attached at its two ends by using a thin aluminium sheet. The diameter of the model is 3 cm, and its length is 12 cm. If each cone has a height of 2 cm, find the volume of air contained in the model that Rachel made. (Assume the outer and inner dimensions of th...

प्रश्नावली 13.1 जब तक अन्यथा न कहा जाए, π = 22/7 लीजिए | Ex 13.1 Class 10 गणित Q1.दो घनों, जिनमे से प्रत्येक का आयतन 64 cm3 है, के सलंग्न फलकों को मिलाकर एक ठोस बनाया जाता है | इससे प्राप्त घनाभ का पृष्ठीय क्षेत्रफल ज्ञात कीजिए | हल: एक घन का आयतन = 64 cm3 एक किनारा = (64)1/3 = 4 cm दो घनों के फलकों को मिलाने पर l = 4 + 4 = 8 cm b = 4 cm h = 4 cm इसप्रकार इस घनाभ का पृष्ठीय क्षेत्रफल = 2(lb + bh + lh) = 2(8×4 + 4×4 + 8×4) ​= 2(32 + 16 + 32) = 2×80 = 160 cm 2 अत: इस घनाभ का प्राप्त पृष्ठीय क्षेत्रफल 160 cm 2 है | Ex 13.1 Class 10 गणित Q2. कोई बर्तन एक खोखले अर्धगोले के आकार का है जिसके ऊपर एक खोखला बेलन अध्यारोपित है | अर्धगोले का व्यास 14 cm है और इस बर्तन (पात्र) की कुल ऊँचाई 13 cm है | इस बर्तन का आंतरिक पृष्ठीय क्षेत्रफल ज्ञात कीजिए | हल : Ex 13.1 Class 10 गणित Q3. एक खिलौना त्रिज्या 3.5 cm वाले एक शंकु के आकार का है, जो उसी त्रिज्या वाले एक अर्ध गोले पर अध्यारोपित है | इस खिलौने की संपूर्ण ऊँचाई 15.5 cm है | इस खिलोने का संपूर्ण पृष्ठीय क्षेत्रफल ज्ञात कीजिए | हल: अर्धगोलाकार भाग की त्रिज्या r = 3.5 cm शंक्वाकार भाग की त्रिज्या r = 3.5 cm शंक्वाकार भाग की ऊँचाई h = 15.5 – 3.5 = 12 cm Ex 13.1 Class 10 गणित Q4. भुजा 7 cm वाले एक घनाकार ब्लाक के ऊपर एक अर्धगोला रखा हुआ है | अर्धगोले का अधिकतम व्यास क्या हो सकता है ? इस प्रकार बने ठोस का पृष्ठीय क्षेत्रफल ज्ञात कीजिए | हल : घनाकार ब्लॉक का एक किनारा = 7 cm अर्धगोले का अधिकतम व्यास d = 7 cm ठोस का पृष्ठीय क्षेत्रफल = घनाकार ब्लॉक का क्षेत्रफल + अर्धगोले का क्षेत्रफल – अर्धगोले से ढके एक वृत्त का क्षेत्रफल ⇒ ठोस का पृष्ठीय क...

NCERT Solutions for Class 10 Maths Chapter 13 Exercise 13.5 in NCERT Solutions for Class 10 Maths Chapter 13 Exercise 13.5 If you need solutions in Hindi, Click for Class 10 Maths Exercise 13.5 Solutions in Hindi Medium To get the solutions in English, Click for About 10 Maths Chapter 13 Exercise 13.5 In 10 Maths Exercise 13.5 Most of the questions are based on concepts. Question number 6 and 7 are basically the derivation of the formula of frustum. In NCERT Exemplar of class 10 Maths, some questions are given on the basis of question 6 and 7. The question number 2 can be down in two different methods, only one method is mentions in the solutions given above. Important Questions for Practice • Twelve solid spheres of the same sizes are made by melting a solid metallic cylinder of base diameter 2 cm and height 16cm. Find the radius of each sphere. • A bucket is in the form of a frustum of a cone and holda 28.490 litres of water. The radii of the top and bottom are 28 cm and 21 cm respectively. Find the height of the bucket. • A cone of radius 8cm and height 12cm is divided into two parts by a plane through the mid-point of its axis parallel to its base. Find the ratio of the volumes of the two parts. • Water is flowing at the rate of 2.52 km/hr. through a cylindrical pipe into a cylindrical tank, the radius of whose base is 40 cm. If the increase in the level of water in the tank, in half an hour is 3.15m, find internal diameter of the pipe. • A container, shaped like a rig...

Exercise 13.2 Class 10 Maths NCERT Solutions PDF Download 2022 • 13.2 Class 10 • Exercise 13.2 Class 10 • Exercise 13.2 Class 10 Maths Solutions • 13.3 Class 10 Maths PDF Download • C lass 10 Exercise 13.2 Maths NCERT Solutions Surface Areas and Volumes Exercise 13.1 Introduction Exercise 13.2 Surface Area of a Combination of Solids Exercise 13.3 Volume of a Combination of Solids Exercise 13.2 Class 10 Maths NCERT Solutions Exercise 13.2 Class 10 Maths NCERT Solutions Access Answers of Maths NCERT Class 10 Chapter 13 – Surface Areas and Volumes NCERT solutions for class 10 maths chapter 13 Surface Areas and Volumes Excercise: 13.2 Class 10 NCERT Solutions Q.1 . Ans: (Exercise 13.1 Class 10) :- The volume of the solid is given by : The volume of solid = Volume of cone + Volume of a hemisphere The volume of cone : or or And the volume of the hemisphere : or or Hence the volume of solid is : Q.2 Rachel, an engineering student, was asked to make a model shaped like a cylinder with two cones attached at its two ends by using a thin aluminum sheet. The diameter of the model is 3 cm and its length is 12 cm. If each cone has a height of 2 cm, find the volume of air contained in the model that Rachel made. (Assume the outer and inner dimensions of the model to be nearly the same.) Ans: (Exercise 13.1 Class 10) :- The volume of air present = Volume of cylinder + 2 (Volume of a cone) Now, the volume of a cylinder : or or And the volume of a cone is : or or Thus the volume of air is :...