- A man 4 times as old as his son. After 16 years, he will be only twice as old as his son. Find their present ages.
- SOLUTION: A man is now 5 times as old as his son, four years ago the product of their ages was 52. Find their present ages.
- SOLUTION: 5 years ago, a man was 7 times as old as his son. 5years hence, father will be 3 times as old as his son. Find their present ages.
- SOLUTION: Four years ago man was six times as old as his son but in five years time he will be only three times as old as his son, what are their present ages
- Math problem: Age problems
- SOLUTION: At present time a man is four times as old as his son. Six years ago he was as 10 times as old. Find their present age.
A man 4 times as old as his son. After 16 years, he will be only twice as old as his son. Find their present ages.
Let the present age of the son = x years. Therefore, the present age of his father = 4x years. So, after 16 years, Son’s age = (x + 16) and father’s age = (4x + 16) years According to the question: ⇒ 4 x + 16 = 2 ( x + 16 ) ⇒ 4 x + 16 = 2 x + 32 ⇒ 4 x – 2 x = 32 – 16 ⇒ 2 x = 16 Dividing both sides by 2, we get ⇒ 2 x 2 = 16 2 ⇒ x = 8 So, the present age of the son = x = 8 years, And the present age of the father = 4x = 4(8) = 32 years
SOLUTION: A man is now 5 times as old as his son, four years ago the product of their ages was 52. Find their present ages.
You can A man is now 5 times as old as his son. M = 5S 4 years ago the product of their ages = 52 M - 4 * S - 4 = 52 Replace M with 5S 5S - 4 * S - 4 = 52 5S^2 - 20S - 4S + 16 = 52 5S^2 - 24S + 16 - 52 = 0 5S^2 - 24S - 36 = 0 (5S + 6)(s - 6) = 0 5S + 6 = 0 5S = -6 S = -6/5 (No answer as x < 0) s - 6 = 0 s = 6 Son = 6 years old Father = 30 years old Hope this helps. :-)
SOLUTION: 5 years ago, a man was 7 times as old as his son. 5years hence, father will be 3 times as old as his son. Find their present ages.
You can Sons age 5 years ago=x father's age = 7x their present age = x+5 and 7x+5 resp Sons age 5 years hence = x+10(since x is sons age 5 years ago from present age and we are talking of his age 5 years hence from his present age so 5+5=10) fathers age 5 years hence =3(x+10) hence the fathers present age will be 3(x+10)-5 also fathers present age =7x+5 therefore 7x+5=3(x+10)-5 7x+5=3x+30-5 7x-3x=25-5 4x=20 x=5 sons age 5 years ago=5years fathers age =5*7=35years present age of the son=10years(5+5) fathers age=35+5=40 years sons age 5 years hence= 5+10=15years fathers age =3*(5+10)=45 years Answer by kritikapd(4) ( You can Let present age of son = X Age of son before 5 years = X-5 So, Present age of father = 7(X-5)+5 ……… (i) Age of son after 5 years = X+5 Age of father after 5 years = 3(X+5) So, present age of father = 3(X+5)-5 ……….(ii) Equating age of father i.e. (i) and (ii) 7(X- 5)+5 = 3(X+ 5)-5 7X – 35+5 = 3X + 15-5 7X-3X = 15 - 5 + 35 - 5 4X = 40 X = 40/4 . X (son)= 10 , Father (3(10+5)-5)= 40 yrs
SOLUTION: Four years ago man was six times as old as his son but in five years time he will be only three times as old as his son, what are their present ages
SOLUTION: Four years ago man was six times as old as his son but in five years time he will be only three times as old as his son, what are their present ages SOLUTION: Four years ago man was six times as old as his son but in five years time he will be only three times as old as his son, what are their present ages You can Write an equation for each statement, simplify Four years ago man was six times as old as his son m - 4 = 6(s - 4) m - 4 = 6s - 24 m - 6s = -24 + 4 m - 6s = -20 but in five years time he will be only three times as old as his son, m + 5 = 3(s + 5) m + 5 = 3s + 15 m - 3s = 15 - 5 m - 3s = 10 Use elimination on these two equations m - 3s = 10 m - 6s = -20 ----------------subtraction eliminates m, find s 0 + 3s = 30 s = 30/3 s = 10 yrs is the son's present age and m - 3(10) = 10 m = 10 + 30 m = 40 yrs is Dad's age : : Check this in the statement: "Four years ago man was six times as old as his son" 40 - 4 = 6(10-4) 36 = 6(6)
Math problem: Age problems
A) Alex is three times as old as he was two years ago. How old is he now? b) Casey was twice as old as his sister three years ago. Now he is five years older than his sister. How old is Casey? c) Jessica is four years younger than Jennifer now. In 10 years, Jessica will be twice the age that Jennifer is now. Find the present ages of Jennifer and Jessica, Correct answer: A = 3 C = 16 J = 2 N = 6 Step-by-step explanation: A=3(A-2) A=3·(A-2) 2A = 6 A = 6 / 2 = 3 A = 3 Our simple C = 2(S-3) C = S+5 C = 2·(S-3) C = S+5 C-2S = -6 C-S = 5 Row 2 - Row 1 → Row 2 C-2S = -6 S = 11 S = 11 / 1 = 11 C = -6+2S = -6+2 · 11 = 16 C = 16 S = 11 Our J = N - 4 J+10 = 2·N J-N = -4 J-2N = -10 Row 2 - Row 1 → Row 2 J-N = -4 -N = -6 N = -6 / -1 = 6 J = -4+N = -4+6 = 2 J = 2 N = 6 Our A) Alex is three times as old as he was two years ago. How old is he now? b) Casey was twice as old as his sister three years ago. Now he is five years older than his sister. How old is Casey? c) Jessica is four years younger than Jennifer now. In 10 years, Jessica will be twice the age that Jennifer is now. Find the present ages of Jennifer and Jessica, • algebra • • Units of physical quantities: • Grade of the word problem: • • Related math problems and questions: • Brother age One brother talks about his younger brother: "2 years ago, I was three times my brother's age. In 3 years, I will be twice as old as my brother." How old is each brother now? • The ages 2 The ages of the two persons differ by 18 years. Twelve...
SOLUTION: At present time a man is four times as old as his son. Six years ago he was as 10 times as old. Find their present age.
You can At present time a man is four times as old as his son. Six years ago he was as 10 times as old. Find their present age. -------------- Equations: m = 4s m-6 = 10(s-6) ---- Substitute for "m" and solve for "s": 4s-6 = 10s-60 6s = 54 s = 9 yrs (son's age now) m = 4s = 36 (father's age now) ------------ Cheers, Stan H. -----------------
