How many natural numbers lie between 25 square and 26 square

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Perfect Squares and their Square Roots Perfect Square: Taking a positive integer and squaring it (multiplying it by itself) equals a perfect square. Example: 3 x 3 = 9 Thus: 9 is a perfect square. Taking the square root (principal square root) of that perfect square equals the original positive integer. Example: √ 9= 3 Where: 3 is the original integer. Note: An integer has no fractional or decimal part, and thus a perfect square (which is also an integer) has no fractional or decimal part. ( Perfect Squares List from 1 to 10,000. ) Positive Integer Integer Squared= Perfect Squares List Square Root of Perfect Square= Original Integer 1 1 ^2 = 1 √ 1= 1 2 2 ^2 = 4 √ 4= 2 3 3 ^2 = 9 √ 9= 3 4 4 ^2 = 16 √ 16= 4 5 5 ^2 = 25 √ 25= 5 6 6 ^2 = 36 √ 36= 6 7 7 ^2 = 49 √ 49= 7 8 8 ^2 = 64 √ 64= 8 9 9 ^2 = 81 √ 81= 9 10 10 ^2 = 100 √ 100= 10 11 11 ^2 = 121 √ 121= 11 12 12 ^2 = 144 √ 144= 12 13 13 ^2 = 169 √ 169= 13 14 14 ^2 = 196 √ 196= 14 15 15 ^2 = 225 √ 225= 15 16 16 ^2 = 256 √ 256= 16 17 17 ^2 = 289 √ 289= 17 18 18 ^2 = 324 √ 324= 18 19 19 ^2 = 361 √ 361= 19 20 20 ^2 = 400 √ 400= 20 21 21 ^2 = 441 √ 441= 21 22 22 ^2 = 484 √ 484= 22 23 23 ^2 = 529 √ 529= 23 24 24 ^2 = 576 √ 576= 24 25 25 ^2 = 625 √ 625= 25 26 26 ^2 = 676 √ 676= 26 27 27 ^2 = 729 √ 729= 27 28 28 ^2 = 784 √ 784= 28 29 29 ^2 = 841 √ 841= 29 30 30 ^2 = 900 √ 900= 30 31 31 ^2 = 961 √ 961= 31 32 32 ^2 = 1024 √ 1024= 32 33 33 ^2 = 1089 √ 1089= 33 34 34 ^2 = 1156 √ 1156= 34 35 35 ^2 = 1225 √ 1225= 35 36 36 ^2 = 1296 √ 1296= ...

Students can also reach out to Sarthaks to get Important Questions for Class 8 Maths for all other chapters. Sarthaks eConnect is a platform that provides study materials for students. Multiple Choice Questions for Class 8 are given here. Each problem carries four options, in which one is the correct answer. You can solve the Class 8 Maths MCQ Questions of square and square roots with Answers for your extensive revision for exams. Students have to find a solution for each problem and choose the correct answer. These important questions with solutions will definitely benefit all students with revision and mastering the topic. you will learn the concepts of square and square roots. There are many important questions given for the chapter that will give you an idea of what kind of question you can expect in exams. 1.A perfect square number between 30 and 40 is (a) 36 (b) 32 (c) 33 (d) 39 2.Find perfect square numbers between 50 and 60 (a)50, 54 (b) 52,58 (c) 56,59 (d) None of the above 3.Which of the following is a perfect square number? (a) 1067 (b) 7828 (c) 4333 (d) 625 4.Which of 132 2, 87 2, 72 2, and 209 2 would end with digit 1? (a) 132 2 (b) 87 2 (c) 72 2 (d) 209 2 5.Which of 105 2, 216 2, 333 2, and 111 2 would end with digit 1? (a) 105 2 (b) 216 2 (c) 333 2 (d) 111 2 6.What will be the number of zeros in the square of the number 60? (a) 1 (b) 2 (c) 3 (d) 4 7.The square of which of the following numbers will be even? 11, 111, 1111, 112 (a) 11 (b) 111 (c) 1111 (d) 112 ...

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(i) 1 2 2 = 1 4 4 1 3 2 = 1 6 9 1 6 9 − 1 4 4 = 2 5 So, there are 2 5 − 1 = 2 4 numbers lying between 1 2 2 and 1 3 2 (ii) 2 5 2 = 6 2 5 2 6 2 = 6 7 6 6 7 6 − 6 2 5 = 5 1 So, there are 5 1 − 1 = 5 0 numbers lying between 2 5 2 and 2 6 2 (iii) 9 9 2 = 9 8 0 1 1 0 0 2 = 1 0 0 0 0 1 0 0 0 0 − 9 8 0 1 = 1 9 9 So, there are 1 9 9 − 1 = 1 9 8 numbers lying between 9 9 2 and 1 0 0 2

• NCERT Solutions • NCERT Library • RD Sharma • RD Sharma Class 12 Solutions • RD Sharma Class 11 Solutions Free PDF Download • RD Sharma Class 10 Solutions • RD Sharma Class 9 Solutions • RD Sharma Class 8 Solutions • RD Sharma Class 7 Solutions • RD Sharma Class 6 Solutions • Class 12 • Class 12 Science • NCERT Solutions for Class 12 Maths • NCERT Solutions for Class 12 Physics • NCERT Solutions for Class 12 Chemistry • NCERT Solutions for Class 12 Biology • NCERT Solutions for Class 12 Economics • NCERT Solutions for Class 12 Computer Science (Python) • NCERT Solutions for Class 12 Computer Science (C++) • NCERT Solutions for Class 12 English • NCERT Solutions for Class 12 Hindi • Class 12 Commerce • NCERT Solutions for Class 12 Maths • NCERT Solutions for Class 12 Business Studies • NCERT Solutions for Class 12 Accountancy • NCERT Solutions for Class 12 Micro Economics • NCERT Solutions for Class 12 Macro Economics • NCERT Solutions for Class 12 Entrepreneurship • Class 12 Humanities • NCERT Solutions for Class 12 History • NCERT Solutions for Class 12 Political Science • NCERT Solutions for Class 12 Economics • NCERT Solutions for Class 12 Sociology • NCERT Solutions for Class 12 Psychology • Class 11 • Class 11 Science • NCERT Solutions for Class 11 Maths • NCERT Solutions for Class 11 Physics • NCERT Solutions for Class 11 Chemistry • NCERT Solutions for Class 11 Biology • NCERT Solutions for Class 11 Economics • NCERT Solutions for Class 11 Computer Science (Python...

(i) 1 2 2 = 1 4 4 1 3 2 = 1 6 9 1 6 9 − 1 4 4 = 2 5 So, there are 2 5 − 1 = 2 4 numbers lying between 1 2 2 and 1 3 2 (ii) 2 5 2 = 6 2 5 2 6 2 = 6 7 6 6 7 6 − 6 2 5 = 5 1 So, there are 5 1 − 1 = 5 0 numbers lying between 2 5 2 and 2 6 2 (iii) 9 9 2 = 9 8 0 1 1 0 0 2 = 1 0 0 0 0 1 0 0 0 0 − 9 8 0 1 = 1 9 9 So, there are 1 9 9 − 1 = 1 9 8 numbers lying between 9 9 2 and 1 0 0 2

Students can also reach out to Sarthaks to get Important Questions for Class 8 Maths for all other chapters. Sarthaks eConnect is a platform that provides study materials for students. Multiple Choice Questions for Class 8 are given here. Each problem carries four options, in which one is the correct answer. You can solve the Class 8 Maths MCQ Questions of square and square roots with Answers for your extensive revision for exams. Students have to find a solution for each problem and choose the correct answer. These important questions with solutions will definitely benefit all students with revision and mastering the topic. you will learn the concepts of square and square roots. There are many important questions given for the chapter that will give you an idea of what kind of question you can expect in exams. 1.A perfect square number between 30 and 40 is (a) 36 (b) 32 (c) 33 (d) 39 2.Find perfect square numbers between 50 and 60 (a)50, 54 (b) 52,58 (c) 56,59 (d) None of the above 3.Which of the following is a perfect square number? (a) 1067 (b) 7828 (c) 4333 (d) 625 4.Which of 132 2, 87 2, 72 2, and 209 2 would end with digit 1? (a) 132 2 (b) 87 2 (c) 72 2 (d) 209 2 5.Which of 105 2, 216 2, 333 2, and 111 2 would end with digit 1? (a) 105 2 (b) 216 2 (c) 333 2 (d) 111 2 6.What will be the number of zeros in the square of the number 60? (a) 1 (b) 2 (c) 3 (d) 4 7.The square of which of the following numbers will be even? 11, 111, 1111, 112 (a) 11 (b) 111 (c) 1111 (d) 112 ...

Perfect Squares and their Square Roots Perfect Square: Taking a positive integer and squaring it (multiplying it by itself) equals a perfect square. Example: 3 x 3 = 9 Thus: 9 is a perfect square. Taking the square root (principal square root) of that perfect square equals the original positive integer. Example: √ 9= 3 Where: 3 is the original integer. Note: An integer has no fractional or decimal part, and thus a perfect square (which is also an integer) has no fractional or decimal part. ( Perfect Squares List from 1 to 10,000. ) Positive Integer Integer Squared= Perfect Squares List Square Root of Perfect Square= Original Integer 1 1 ^2 = 1 √ 1= 1 2 2 ^2 = 4 √ 4= 2 3 3 ^2 = 9 √ 9= 3 4 4 ^2 = 16 √ 16= 4 5 5 ^2 = 25 √ 25= 5 6 6 ^2 = 36 √ 36= 6 7 7 ^2 = 49 √ 49= 7 8 8 ^2 = 64 √ 64= 8 9 9 ^2 = 81 √ 81= 9 10 10 ^2 = 100 √ 100= 10 11 11 ^2 = 121 √ 121= 11 12 12 ^2 = 144 √ 144= 12 13 13 ^2 = 169 √ 169= 13 14 14 ^2 = 196 √ 196= 14 15 15 ^2 = 225 √ 225= 15 16 16 ^2 = 256 √ 256= 16 17 17 ^2 = 289 √ 289= 17 18 18 ^2 = 324 √ 324= 18 19 19 ^2 = 361 √ 361= 19 20 20 ^2 = 400 √ 400= 20 21 21 ^2 = 441 √ 441= 21 22 22 ^2 = 484 √ 484= 22 23 23 ^2 = 529 √ 529= 23 24 24 ^2 = 576 √ 576= 24 25 25 ^2 = 625 √ 625= 25 26 26 ^2 = 676 √ 676= 26 27 27 ^2 = 729 √ 729= 27 28 28 ^2 = 784 √ 784= 28 29 29 ^2 = 841 √ 841= 29 30 30 ^2 = 900 √ 900= 30 31 31 ^2 = 961 √ 961= 31 32 32 ^2 = 1024 √ 1024= 32 33 33 ^2 = 1089 √ 1089= 33 34 34 ^2 = 1156 √ 1156= 34 35 35 ^2 = 1225 √ 1225= 35 36 36 ^2 = 1296 √ 1296= ...