Rs aggarwal class 8 exercise 20a

Question 1: Find the volume, lateral surface area and the total surface area of the cuboid whose dimensions are: (i) length = 22 cm, breadth = 12 cm and height = 7.5 cm (ii) length = 15 m, breadth = 6 m and height = 9 dm (iii) length = 24 m, breadth = 25 cm and height = 6 m (iv) length = 48 cm, breadth = 6 dm and height = 1 m Answer 1: Volume of a cuboid = ( L e n g t h × B r e a d t h × H e i g h t )cubicunits Total surface area = 2 ( l b + b h + l h )sq units Lateral surface area = 2 l + b × hsq units (i) Length = 22 cm, breadth = 12 cm, height = 7.5 cm Volume = ( L e n g t h × B r e a d t h × H e i g h t ) = ( 22 × 12 × 7 . 5 ) = 1980 c m 3 Total surface area = 2 ( l b + b h + l h ) = 2 22 × 12 + 22 × 7 . 5 + 12 × 7 . 5 = 2 264 + 165 + 90 = 1038 c m 2 Lateral surface area = 2 l + b × h = 2 22 + 12 × 7 . 5 = 510 c m 2 (ii) Length = 15 m, breadth = 6 m, height = 9 dm = 0.9 m Volume = ( L e n g t h × B r e a d t h × H e i g h t ) = ( 15 × 6 × 0 . 9 ) = 81 m 3 Total surface area = 2 ( l b + b h + l h ) = 2 15 × 6 + 15 × 0 . 9 + 6 × 0 . 9 = 2 90 + 13 . 5 + 5 . 4 = 217 . 8 m 2 Lateral surface area = 2 l + b × h = 2 15 + 6 × 0 . 9 = 37 . 8 m 2 (iii) Length = 24 m, breadth = 25 cm = 0.25 m, height = 6 m Volume = ( L e n g t h × B r e a d t h × H e i g h t )= ( 24 × 0 . 25 × 6 ) = 36 m 3 Total surface area = 2 ( l b + b h + l h ) = 2 24 × 0 . 25 + 24 × 6 + 0 . 25 × 6 = 2 6 + 144 + 1 . 5 = 303 m 2 Lateral surface area = 2 l + b × h = 2 24 + 0 . 25 × 6 = 291 m 2 (iv) Length = 48 c...

Volume and Surface Area of Solids RS Aggarwal Class 8 Solutions Ex 20A Volume and Surface Area of Solids RS Aggarwal Class 8 Solutions Ex 20A RS Aggarwal Solutions Class 8 Ex 20a Q1. RS Aggarwal Class 8 Chapter 20 Exercise 20a Q2. Ex 20a Class 8 RS Aggarwal Q3. RS Aggarwal Class 8 20a Q4. RS Aggarwal Class 8 Exercise 20a Q5. RS Aggarwal Class 8 Exercise 20a Solution Q6. RS Aggarwal Class 8 Chapter 20a Q7. Exercise 20a Class 8 RS Aggarwal Q8. RS Aggarwal Class 8 20a Solution Q9. RS Aggarwal Class 8 Ex 20a Solution Q10. RS Aggarwal Solutions Class 8 Exercise 20a Q11. Ex 20a RS Aggarwal Class 8 Q12. Class 8 RS Aggarwal Exercise 20a Q13. Volume And Surface Area Of Solids Class 8 Q14. RS Aggarwal Class 8 Ex 20a Q15. Exercise 20a RS Aggarwal Class 8 Q16. RS Aggarwal Solutions Class 8 Ex 20 A Q17. RS Aggarwal Class 8 Ch 20 Ex 20a Q18. RS Aggarwal Ex 20a Class 8 Q19. RS Aggarwal Solutions Class 8 Chapter 20a Q20. Q21. Q22. Q23. Q24. Q25. Q26. Q27. Q28. Q29. Q30. For More Resources

RS Aggarwal Class 11 Straight Lines Solutions are beneficial for the students for exam preparation and revision. Class 11 CBSE Chapter 20 consists of straight lines. RS Aggarwal Solutions have detailed answers and properly solved examples for students. It has detailed chapter-wise solutions for exam points of view and also consists of previous years questions for the benefit of the students. The questions are given in RS Aggarwal Class 11 Chapter 20 solutions are following the new CBSE syllabus pattern, thus, they hold higher chances of appearing in CBSE question papers. The solutions also provide the students with the ability to try different types of questions easily. Straight lines are a fairly important chapter of geometry for the students of Class 11. By solving the problems in RS Aggarwal, which is an advanced-level textbook, students are preparing themselves for competitive exams as well as school-level exams at the same time. However, it is advised to make sure that students are solving problems from their school textbook fIrst for their school examinations. RS Aggarwal serves as a good supplement to the learning process. Use the free solutions PDF and get an upper hand over everyone else with Vedantu . RS Aggarwal Class 11 Chapter 20 Solutions, that is, the solutions of questions on straight lines have a lot of benefits which are as follows: • The solutions are prepared by experts after thorough research on the topic and going through several year’s question paper...

In this chapter, we provide RS Aggarwal Solutions for Class 8 Chapter 20 Volume and Surface Area of Solids Exercise 20A for English medium students, Which will very helpful for every student in their exams. Students can download the latest rs aggarwal class 8 ex 20a Chapter 20 Volume and Surface Area of Solids pdf, Now you will get step by step solution to each question. Textbook Class Class 8 Subject Maths Chapter Chapter 20 Chapter Name Volume and Surface Area of Solids Exercise 20 A Category RS Aggarwal Solutions Class 8 Chapter 20 Volume and Surface Area of Solids Exercise 20A Download PDF Question 1. Solution: (i) Length of cuboid (l) = 22 cm. Breadth (b) = 12 cm and height (h) = 7.5 cm. Question 2. Solution: Length of water tank (l) = 2 m 75cm = 2.75 m breadth (b) = 1 m 80cm = 1.80 m and height (h) = 1 m 40 cm = 1.40 m Volume of water filled in it = l.b.h = 2.75 x 1.80 x 1.40 m³ = 6.93 m³ Water in litres = 6.93 x 1000 = 6930 litres (1 m³ = 1000 litres) Ans. Question 3. Solution: Length of iron (l) = 1.05 m = 105 cm breadth (b) = 70 cm and height (h) = 1.5 cm volume of iron = l x b x h = 105 x 70 x 1.5 cm³ = 11025 cm³ weight of 1cm³ iron = 8 gram Total weight = 11025 x g = 88200 g =882001000kg = 88.2 kg Ans. Question 4. Solution: Area of courtyard = 3750 m² Height of gravel = 1 cm. Volume of gravel = 3750 x1100m³ = 37.50 m³ Cost of 1 m³ gravel = Rs. 6.40 Total cost = Rs. 6.40 x 37.50 = Rs. 240 Ans. Question 5. Solution: Length of hall (l) = 16 m Breadth (b) = 12.5 m h...