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A planet moving along an elliptical orbit is closest to the sun at a distance. A planet moving along an elliptical orbit is closest to the sun at a distance r1 and farthest away at a distance of r2. If v1 and v2 are the linear velocities at these points respectively. then the ratio v1/v2.



Updated on: March 30th, 2023. Southwest monsoon winds account for the rainfall along the Malabar Coast. The Malabar Coast receives significant rainfall in June and July, as it is the first region to be affected by the southwest monsoon.



Mass on Frictionless Incline One of the insights that comes from the setup of this problem is that the force required to push a mass m up a frictionless incline is equal to mgsinθ. Checking the limiting cases, you find that it takes no force along a horizontal frictionless surface (θ=0), and a force = mg on a vertical frictionless surface (θ.



Answer: maximum safetey speed on horizontal road = Explanation: Let the mass of vehicle =m maximum speed of vehicle = v radius of curve path= r acceleration due to gravity= g and coefficient of friction= During the motion of the vehicle the centrifugal force and frictional force will be in opposite direction to each other.



Solution Verified by Toppr Correct option is A) Total displacement of insect S=60−12=48 cm Total time taken t=2 min =120 s Insect's average velocity v avg= tS= 12048 =0.4 cm/s Solve any question of Motion in a Straight Line with:- Patterns of problems > Was this answer helpful? 0 0 Similar questions



Measles is a highly contagious disease that can lead to serious complications. Symptoms usually begin 7-14 days after you’ve been infected. Signs and Symptoms Complications Photos of Measles Last Reviewed: November 5, 2020 Source: National Center for Immunization and Respiratory Diseases, Division of Viral Diseases



A farmer moves along the boundary of a square field of side 10 m in 30 s. What will be the magnitude of displacement of the farmer at the end of 1 min 45 sec ?A. 10 mB. 10 √2 mC. 20 mD.



Complete step by step solution: Here, given that side of the square field is $l = 10m$ Therefore, the perimeter of the square is $P = 4 \times l$ [Place the value of the square length,$l = 10m$] $ \Rightarrow P = 4 \times l \\ \Rightarrow P = 4 \times 10 \\ \Rightarrow P = 40m \\ $



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