Complex shapes emerge as the flake moves through differing temperature and humidity zones in the atmosphere, such that individual snowflakes differ in detail from one another, but may be categorized in eight broad classifications and at least 80 individual variants.

Problem Solution: Read three edges of the triangle, and calculate the area of the triangle using the standard formula. Formula to calculate the area of a triangle: The given sides are a, b, and c. Program: The source code to calculate the area of a triangle given three sides is given below.

Calculate sides, angles of an parallelogram step-by-step. What I want to Find. Base b Given Perimeter Base b Given Area Side a Angle α Angle β. Please pick an option first.

Solution: Length of the blackboard = 120 cm = 1.2 m. Breadth of the blackboard = 100 cm = 1 m. Area of the blackboard = area of a rectangle = length x breadth = 1.2 m x 1 m = 1.2 square-metres. Example 3: The length of a rectangular screen is 15 cm. Its area is 180 sq. cm. Find its width.

Transcript. Question 3 A rectangle with adjacent sides of lengths 5 cm and 4 cm. Let’s draw a rough figure In rectangle, Opposite sides are equal ∴ AD = BC = 4 cm AB = DC = 5 cm And, All angles are 90° ∴ ∠ A = ∠ B = ∠ C = ∠ D = 90° So, we draw the rectangle using 3 sides, and 2 angles method Steps of construction 1. Draw side AB.

Answer: the area of the triangle is 17.4cm^2 Step-by-step explanation: Finding the area of a triangle an isosceles triangle has two sides of equal length. therefore to get the base of the triangle : we need to subtract the lengths from he perimeter 30-12-12 = 6 the base of the triangle is 6 cm area of a triangle formula :

Solution: Perimeter of the triangle = 42 c m Two sides of the triangle are a = 18 c m and b = 10 c m Third side c = 42 − ( 18 + 10) c m = 42 − 28 c m = 14 c m Therefore, s = Perimeter 2 = 42 2 = 21 Area = s ( s − a) ( s − b) ( s − c) = 21 × ( 21 − 18) ( 21 − 10) ( 21 − 14) = 21 × 3 × 11 × 7 c m 2 = 3 × 7 × 7 × 3 × 11 = 3 × 7 × 11 = 21 11 c m 2

Find the area of a triangle two sides of which are 8 cm and 11 cm and perimeter is 32 cm. Medium Solution Verified by Toppr We are given, Sides of ABC are a,b & c(in cm) Let a=8 b=11 here we have perimeter, i.e., 32 cm. So, a+b+c=32 cm c=32−(a+b) =32−(8+12) c=32−19 c=13 cm Now, the semi perimeter will be S= 2perimeter= 232=16 cm

Perimeter of the triangle is 42 cm. To find :-Area of the given triangle. Solution:-Given that . Two sides of a triangle are 18 cm and . 10 cm. Let a = 18 cm. Let b = 10 cm. Let the third side be c cm. We know that. Perimeter of a triangle is equal to the sum of the lengths of the three sides. Perimeter of the given triangle = (a+b+c) cm => P.

Heron's formula for the area of a triangle is: Area = √ s(s - a)(s - b)(s - c) Where a, b and c are the sides of the triangle, and s = Semi-perimeter = Half the perimeter of the triangle . The sides of triangle given: a =18 cm, b = 10 cm. Perimeter of the triangle = (a + b + c) 42 = 18 + 10 + c. 42 = 28 + c. c = 42 - 28. c = 14 cm. Semi.

Step-by-step explanation: Let the length of the base of an isosceles triangle be x cm. Therefore, as per the given conditions, Length of the congruent sides =2x−13 cm Given, the perimeter of an isosceles triangle =24 cm. Therefore, x+2x−13+2x−13=24 ⇒5x−26=24 ⇒5x=24+26 ∴x=10 Base of a triangle =10 cm Congruent sides =2x−13 =2×10−13=20−13=7 cm

: \ ( \frac {1} {2} \) × base × perpendicular height. A rectangle can be divided into two congruent triangles. The length and width of the rectangle are the base and height of a triangle..