The correct relation between the transistor parameters α and ß are related by

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So the parameter beta for a Common Emitter Amplifier is called the Current Gain and is defined as \$\beta =\dfrac\$ What is this \$\alpha\$ called and what is its significance? Like for example \$\beta\$ can be treated as the amount by which a signal is getting modified. \$\beta\$ is a ratio between the collector and base currents whereas \$\alpha\$ is also a ratio but between the collector and emitter currents. There is no special name for \$\alpha\$ and \$\beta\$ as they are both unit-less. However, you may call \$\alpha\$ as the common-base gain and \$\beta\$ as the common-emitter gain. Either way, you will usually see \$\beta\$ in the spec sheets of BJT chips. \$\alpha\$ is always less that 1.0 because of There is a relationship between \$\alpha\$ and \$\beta\$... \$\displaystyle \beta= \frac\$ (Also, I asked a question about Yes, we have: 1 - "beta" \$\beta = \frac \$ for common-collector current gain. Thanks for contributing an answer to Electrical Engineering Stack Exchange! • Please be sure to answer the question. Provide details and share your research! But avoid … • Asking for help, clarification, or responding to other answers. • Making statements based on opinion; back them up with references or personal experience. Use MathJax to format equations. To learn more, see our

The relation between αand βparameters of current gains for a transistors is given by (1)α=β1-β (2)α=β1+β (3)α=1-ββ (4)α=1+ββ Semiconductor Electronics Physics NEET Practice Questions, MCQs, Past Year Questions (PYQs), NCERT Questions, Question Bank, Class 11 and Class 12 Questions, and PDF solved with answers • Recommended MCQs - 150 Questions • Recommended PYQs (STRICTLY NCERT Based) • Mini Q Bank - Semiconductor Electronics • NCERT Solved Examples Based MCQs • NCERT Exercise Based MCQs • NCERT Exemplar (Objective) Based MCQs • AR & Other Type MCQs • Past Year (2019 onward - NTA Papers) MCQs • Past Year (2016 - 2018) MCQs • Past Year (2006 - 2015) MCQs • Past Year (1998 - 2005) MCQs

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When a photon enters the depletion zone of a p − n junction, the photon can scatter from the valence electrons there, transferring part of its energy to each electron, which then jumps to the conduction band. Thus, the photon creates electron–hole pairs. For this reason, the junctions are often used as light detectors, especially in the x-ray and gamma-ray regions of the electromagnetic spectrum. Suppose a single 6 6 2 k e V gamma-ray photon transfers its energy to electrons in multiple scattering events inside a semiconductor with an energy gap of 1 . 1 e V, until all the energy is transferred. Assuming that each electron jumps the gap from the top of the valence band to the bottom of the conduction band, find the number of electron-hole pairs created by the process.

The common-emitter current gain (β) is the ratio of the transistor's collector current to thetransistor's base current, i.e. \(β = \frac\)

• • DC Circuits • Single Phase AC Circuits • Three Phase AC Circuits • Electrical/Electronics App & Software • Electrical / Electronics Symbols • • Resistors • Capacitors • Inductance & Magnetism • Electrical / Electronics Symbols • Electrical Design • • Light Emitting Diode • Fun With LED’s • Renewable & Green Energy • Electrical Energy • Lighting • Search for • Switch skin Table of Contents • • • • • • • • • • • • Bipolar Junction Transistor: Current Gains in BJT: There are two types of current gain in Where • I E is the emitter current • I C is the collector current • I B­ is the base current Common Base Configuration: Common Base Voltage Gain In common base configuration, BJT is used as voltage gain amplifier, where the gain A V is the ratio of output voltage to input voltage: Where • Β F is the forward current gain • I C is the collector current • I B is the base current Emitter Current: The emitter current is the combination of collector & base current. It can be calculated using any of these equations. • I E = I C + I B • I E = I C / α • I E = I B (1+ β) Collector Current: The collector current for BJT is given by: • I­ C = β FI B + I CEO ≈ β FI B • I­ C = α I E • I C = I E – I B Where I CEO is the collector to emitter leakage current (Open base). Alpha α to Beta β Conversion Formula: The gain alpha & beta are inter-convertible, & they can be converted using, • α = β / (β + 1) • β = α / (1- α) Collector-to-Emitter Voltage: V CE = V CB + V BE Where • V CE is the coll...