The electric potential on the axis of an electric dipole at a distance ‘r from it’s centre is v. then the potential at a point at the same distance on its equatorial line will be

Views: 6,320 A and B, each of length l, carry the same current I. Wire A is bent into a circle of radius R and wire B is bent to form a square of side a. If B A ​ and B B ​ are the values of magnetic field at the centres of the circle and square respectively, then the ratio B B ​ B A ​ ​ is (a) 8 π 2 ​ (b) 16 2 ​ π 2 ​ (c) 16 π 2 ​ (d) 8 2 ​ π 2 ​ Views: 5,788 − 4.8 × 1 0 − 10 statC এব? ইলেকট্রন কক্ষের গড় ব্যাসার্ধ = 1 0 − 8 cm । [ 2.3 × 1 0 − 3 dyn ] চারিদিকে r ব্যাসাধ্ধর বৃত্তপেে घুরছে। ইলেকট্টেনের বেগ কত হবে? \[ \left[v=\sqrt\right] \] + 16 esu | বায়ুমধ্যে এদের দূরত্ব 8 cm रলে ওদের মধ্যে পারস্গরিক বল কত? [6 dyn] (7.) তিনটি আধান + 10 μ C , + 20 μ C এ্রব − 20 μ C , 2 cm বাহুবিশিষ্ট একটি সমবাহু ত্ভিভুজের শীর্মবিন্দুতে অবস্থিত। আধানগুলি বায়ুমাধ্যমে অবস্থিত খরে 8. 4 q उ q आधান দুটির মধ্যে ব্যবধান 2 r । অপর একটি আधান Q-কে এफ্রে সशশোগকারী রেখার মর্যাবিন্দুতে রাখা रল। q আथানের ওপর মোঁ বল শূন্য इढज Q-aর মাन কण रढব? [ − q ] [SCRA 2000] সরলরেখায অবশ্বিত। q आयানটিকে বোথায় স্থাপন করলে এবং সেটির মধ্যবিন্দুতে, 0.25 unit, अস্থির] Views: 5,835 V = Potential difference across the two ends of conductor and i = Current flowing through the conductor According to Ohm's law i ∝ V or i V ​ = Constant. From equation (3), v = a τ Substituting for ' a' from equation (2), we get, v = m l e V ​ τ Substituting for v in equation (4), we get or i = n A e ( m l e V ​ τ ) = ( m l n A e 2 ​ τ ) V where i V ​ = R R = n A e 2 τ m l ​ Since n , A , m , l and τ are all constant quantities i ∝ V This is O...

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11 Magnetic Forces and Fields • Introduction • 11.1 Magnetism and Its Historical Discoveries • 11.2 Magnetic Fields and Lines • 11.3 Motion of a Charged Particle in a Magnetic Field • 11.4 Magnetic Force on a Current-Carrying Conductor • 11.5 Force and Torque on a Current Loop • 11.6 The Hall Effect • 11.7 Applications of Magnetic Forces and Fields • Learning Objectives By the end of this section, you will be able to: • Calculate the potential due to a point charge • Calculate the potential of a system of multiple point charges • Describe an electric dipole • Define dipole moment • Calculate the potential of a continuous charge distribution Point charges, such as electrons, are among the fundamental building blocks of matter. Furthermore, spherical charge distributions (such as charge on a metal sphere) create external electric fields exactly like a point charge. The electric potential due to a point charge is, thus, a case we need to consider. We can use calculus to find the work needed to move a test charge q from a large distance away to a distance of r from a point charge q. Noting the connection between work and potential W = − q Δ V , W = − q Δ V , as in the last section, we can obtain the following result. E = F q t = k q r 2 . E = F q t = k q r 2 . Recall that the electric potential difference V is a scalar and has no direction, whereas the electric field E → E → is a vector. To find the voltage due to a combination of point charges, given zero voltage at...

\( \newcommand\) • Learning Objectives By the end of this section, you will be able to: • Explain point charges and express the equation for electric potential of a point charge. • Distinguish between electric potential and electric field. • Determine the electric potential of a point charge given charge and distance. Point charges, such as electrons, are among the fundamental building blocks of matter. Furthermore, spherical charge distributions (like on a metal sphere) create external electric fields exactly like a point charge. The electric potential due to a point charge is, thus, a case we need to consider. Using calculus to find the work needed to move a test charge \(q\) from a large distance away to a distance of \(r\) from a point charge \(Q\), and noting the connection between work and potential \((W=-q\Delta V)\), we can define the electric potential \(V\) of a point charge: definition: ELECTRIC POTENTIAL \(V\) OF A POINT CHARGE The electric potential \(V\) of a point charge is given by \[V=\dfrac\) is closely associated with force, a vector. Example \(\PageIndex\] Discussion The negative value for voltage means a positive charge would be attracted from a larger distance, since the potential is lower (more negative) than at larger distances. Conversely, a negative charge would be repelled, as expected. Example \(\PageIndex=mgh\).

imagine we have an electric dipole basically a negative charge and a positive charge of same value separated by some distance let's say we call it 2a traditionally we call that 2a our goal is to figure out what the potential due to this dipole is going to be at some point p let me write that show that at some point p far away from that dipole at some distance are far away these dotted lines are showing far away and just to show you the real picture um this is what it would look like if i were to actually show you this ins to scale imagine it this way that this distance r is way bigger way bigger compared to a that's what i mean when i say i want to calculate the distance potential very far away all right so let me just keep this picture somewhere over here now the question is how do i do that well i already know how to calculate potential due to a point charge we've seen the expression for that it's k q one by four epsilon naught which is called k so k q divided by r so all i have to do is figure out what's the potential due to this charge over here what's the potential due to this charge over there and then just add them up but you could say hey the problem is i don't know what's the distance of that point p from this charge and from this charge that r is the distance from the center so how do i what is this distance what is this distance that's not given to me so what i'll do is like like in most cases in physics when something is not given well you draw that and you ass...

from Example 2- Potential of an electric dipole Let’s calculate the potential of an electric dipole. Potential of an electric dipole. As you recall, dipole is a point charge system which consists of two point charges with equal magnitudes and opposite signs, separated from one another by a very small distance. Let’s say we’re interested with the potential of such a system at a certain distance, r, away from the center of a dipole. Let’s say the distance between the positive charge and the point of interest is r+, and the distance between the negative charge and the point of interest is denoted with r-. As you see, I’m not drawing any vectors, no directions, because I’m dealing with potential and potential is a scaler quantity. It’s not a vectoral quantity. It doesn’t have any directional properties. It is just electric potential energy per unit charge, and those two quantities are all scalers. Well, to be able to calculate the potential of this system, we will first calculate the potential of each one of these charges at the point of interest, so V1 is going to be equal to the potential of a point charge is the charge divided by 4 π ε0 times its distance to the point of interest, and that is r+ for this charge. Let’s call this one as V+. And for the negative charge, V-, we will have – q over 4 π ε0 r-. Total potential is the direct sum of these two scaler quantities, V+ plus V-, and therefore, V will be equal to, if we add these two quantities we will have q over 4 π ε0 r+...