The thermal efficiency of a standard otto cycle for a compression ratio of 5.5 will be

  1. Solved Mcq Equation :1.The order of values of thermal


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Solved Mcq Equation :1.The order of values of thermal

This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer See Answer See Answer done loading Question:Mcq Equation :1.The order of values of thermal efficiency of Otto, Diesel and Dual cycle, when they have equal compression ratio and same heat input is given by :a.η dual > η diesel > η ottob.η otto > η dual > η dieselc.η otto > η diesel > η duald.η diesel > η dual > η otto2. In spark-ignition engines, 4. Consider the following statements relevant to the ignition system of SI engine: 1. Too small a dwell angle will lead to the burning of condensers and contact points. 2. Too small a dwell angle will result in misfiring. 3. Too large a dwell angle will result in the burning of condenser and contact points. 4. Too large a dwell will result in misfiring. Which of these statements are correct? 9. Consider the following statements: 1. Supercharging increases power output and increases volumetric efficiency. 2. Supercharging is more suitable for SI engines than CI engines. 3. The limits of supercharging for an SI engine is set by knock while that for a CI engine is set by thermal loading. 4. The supercharging limits for a “SI engine” only. Which of these statements are correct? *

ME200

ME 200 – Thermodynamics I – Spring 2020 Homework 38: Otto Cycles Given: An air-standard Otto cycle has a compression ratio of 8:1. At the beginning of the compression process, the pressure is 105 kPa, the temperature is 310 K (State 1). After the constant volume heat addition process, the air temperature is 1620 K (State 3). #Given Inputs: P_1 = 105 # pressure at the begining of the compression process (state 1) [kPa] T_1 = 310 # temperature at the begining of the compression process (state 1) [K] T_3 = 1620 # temperature after the constant volume heat addition process (state 3) [K] r = 8 # compression ratio of 8:1 [-] R = 0.287 # air gas constant [KJ/kgK] Find: Part (a): Net work (kJ/kg) Part (b): Thermal efficiency Part (c): T-s diagram System Diagram: The system diagram shows all the processes for the Otto cycle. We select the air in the piston-cylinder assembly as the closed system. Assumptions: 1) closed system, 2) all the processes are internally reversible, 3) adiabatic compression and expansion processes, 4) negligible changes in kinetic and potential energy, 5) ideal gas for air Basic Equations: Solution: Part (a): Net work States 1 and 2: The analysis begins by determining the properties at each state point of the cycle. The pressure and temperature at state 1 are known and the ideal gas law can be used to determine the specific volume. The ideal gas table is used to determine the internal energy and relative volume ($v_r$) at state 1. From state 1 to 2, the proc...