Two pipes a and b can fill a tank in 12 hours and 15 hours respectively

  1. Aptitude Questions: Pipes & Cistern Set 2
  2. Two pipes can fill a tank in 10 hours and 12 hours respectively, while a third pipe empties the full tank in 20 hours. If all the three pipes operate simultaneously, in how much time will the tak be full? a 7 hrs 15 min b 7 hrs 30 min c 7 hrs 45 min d 8 hrs
  3. Two pipes A & B can fill the tank in 12 hours and 36 hours respectively. If both the pipes are opened simultaneously, how much time will be required to fill the tank?
  4. Two pipes A and B can fill a cistern in 8 hours and 12 hours respectively. The pipes when opened simultaneously takes
  5. Pipes and Cisterns
  6. Two pipes together can fill a tank in 12 hours. If the first pipe can fill the tank 10 hours faster than the second then how many hours will the second pipe take to fill the tank?
  7. Two pipes can fill a tank with water in 15 and 12 hours respectively and the third pipe can empty it in hours. If the pipers are opened in order at 8,9 and 11 A. M. respectively, the thank will be emptied at
  8. Aptitude Questions: Pipes & Cistern Set 2
  9. Two pipes A and B can fill a cistern in 8 hours and 12 hours respectively. The pipes when opened simultaneously takes
  10. Two pipes together can fill a tank in 12 hours. If the first pipe can fill the tank 10 hours faster than the second then how many hours will the second pipe take to fill the tank?


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Aptitude Questions: Pipes & Cistern Set 2

Click Here Click Here Hello Aspirants. Welcome to Online Quantitative Aptitude Section with explanation in AffairsCloud.com. Here we are creating question sample in Pipes & Cistern which is common for all competitive exams. We have included Some questions that are repeatedly asked in bank exams !!! • Two pipes A and B can fill a tank in 4 hours and 5 hours respectively. If they are opened on alternate hours and if pipe B is opened first, in how many hours, the tank fill in A.7hrs B.6hrs C.4.30hrs D.5hrs E.None of these Answer – C.4.30hrs Explanation : A+B = 1/4+1/5=9/20…………..2h A+B = 18/20………………………4h =9/10 Remaining = 1-9/10 = 1/10…it take 1/2 hr=> B Already 4+ remaining 2(B) = 4+1/2 = 4.30hrs • A tap can fill a tank completely in 6 hours. After half the tank is filled , one more similar tap is opened. What is the total time taken to fill the tank completely ? A.4hrs 20min B.3hrs 30min C.3hrs 10min D.4hrs 30min E.None of these Answer – D. 4hrs 30min Explanation : Tab fill the half tank in 3hrs Now another similar tab opened 1/6+1/6 = 2/6 = 1/3 Remaining half tank filled in 1.5hrs Total time = 3+1.5 = 4hrs 30min • A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 7 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled? A.9.00hrs B.9.20hrs C.9.30hrs D.9.33hrs E.None of these Answer – D. 9.33hrs Explanation : 1/4 – 1/7 = 7-4/28 Cistern filled in = 28/3 = 9.33hrs • A pipe can fill a tank in 5...

Two pipes can fill a tank in 10 hours and 12 hours respectively, while a third pipe empties the full tank in 20 hours. If all the three pipes operate simultaneously, in how much time will the tak be full? a 7 hrs 15 min b 7 hrs 30 min c 7 hrs 45 min d 8 hrs

More • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • Q. Tick (✓) the correct answer: Two pipes can fill a tank in 10 hours and 12 hours respectively, while a third pipe empties the full tank in 20 hours. If all the three pipes operate simultaneously, in how much time will the tank be full? (a) 7 hrs 15 min (b) 7 hrs 30 min (c) 7 hrs 45 min (d) 8 hrs

Two pipes A & B can fill the tank in 12 hours and 36 hours respectively. If both the pipes are opened simultaneously, how much time will be required to fill the tank?

B. Given pipe A can fill the tank in 12 hours. So the part of the tank filled by pipe A in 1 hour = 1/12 And Pipe B can fill the tank in 36 hours,So the part of the tank filled by pipe B in 1 hour = 1/36 So the part of the tank filled by bothpipes A and B in 1 hour = (1/12)+(1/36) = (3+1)/36 = 1/9 So the total time is taken to fill the tank by pipe A and B =9 hours So the correct answer is option B. B. पाइप A टैंक को 12 घंटे में भर सकता है। तो पाइप A टैंक के हिस्से को 1 घंटे में भर सकता है = 1/12 पाइप B, 36 घंटे में टैंक को भर सकता है। तो पाइप B टैंक के हिस्से को 1 घंटे में भर सकता है= 1/36 तो पाइप A औरB टैंक के हिस्से को 1 घंटे में भर सकता है= (1/12) + (1/36) = (3 + 1) / 36 = 1/9 अतः पाइप A और B द्वारा टैंक को भरने के लिए लिया गया कुल समय = 9 घंटे इसलिए सही उत्तर विकल्प B है। A booster pump can be used to fill as to empty the tank. The capacity of the tank is 1200 m3. The emptying capacity of the tank is 10 m3 per minute higher than its filling capacity and the pump requires 4 minutes lesser to vacant the tank than it requires to fill it. Calculate the filling capacity of the pump.

Two pipes A and B can fill a cistern in 8 hours and 12 hours respectively. The pipes when opened simultaneously takes

Correct answer is: (d) 120 hrs. Portion of cistern filled by both pipes in 1 hour = \(\frac\) Time taken by leakage to empty the tank=120 h Categories • • (31.9k) • (8.8k) • (764k) • (248k) • (10.0k) • (5.6k) • (36.4k) • (7.5k) • (10.7k) • (11.8k) • (11.2k) • (6.8k) • (4.9k) • (5.3k) • (2.8k) • (19.9k) • (959) • (2.9k) • (5.2k) • (664) • (121k) • (72.1k) • (3.8k) • (19.6k) • (1.4k) • (14.2k) • (12.5k) • (9.3k) • (7.7k) • (3.9k) • (6.7k) • (63.8k) • (26.6k) • (23.7k) • (14.6k) • (25.7k) • (530) • (84) • (766) • (49.1k) • (63.8k) • (1.8k) • (59.3k) • (24.5k)

Pipes and Cisterns

Sol : Option A Explanation: Cistern filled by both pipes in one hour = 1/12+1/20=2/15th Therefore both pipes filled the cistern in 15/2hrs. Now, due to leakage both pipes filled the cistern in 15/2+30/60=8hrs. Therefore Due to leakage, filled part in one hour = 1/8 Therefore part of cistern emptied, due to leakage in one hour = 2/15-1/8= 1/120th ∴ In 120 hrs, the leak would empty the cistern. Sol : Option C Explanation: (P+Q)’s 1 hour’s work = (1/10+1/20) = 3/20 (A+C)’s 1 hour’s work = (1/10+1/30) = 2/15 Part filled in 2 hrs = (3/20+2/15) = 17/60 Part filled in 6 hrs = (3×17/60) = 17/20 Remaining Part = (1-17/20) = 3/20 Now, it is the turn of P and Q and 3/20 part is filled by P and Q in 1 hour. Therefore, Total time taken to fill the tank = (6+1) hrs = 7 hrs

Two pipes together can fill a tank in 12 hours. If the first pipe can fill the tank 10 hours faster than the second then how many hours will the second pipe take to fill the tank?

Let the time required to fill the tank by second pipe be x hours. Then, the time required to fill the tank by first pipe is (x − 10) hours. Given: Two pipes together can fill a tank in 12 hours. According to the question, 1 x + 1 x - 10 = 1 12 ⇒ x - 10 + x x x - 10 = 1 12 ⇒ 2 x - 10 x 2 - 10 x = 1 12 ⇒ 24 x - 120 = x 2 - 10 x ⇒ x 2 - 10 x - 24 x + 120 = 0 ⇒ x 2 - 34 x + 120 = 0 ⇒ x 2 - 30 x - 4 x + 120 = 0 ⇒ x x - 30 - 4 x - 30 = 0 ⇒ x - 30 x - 4 = 0 ⇒ x = 30 , 4 But x - 10 is the time required by the first pipe to fill the tank , which is always positive . Thus , x = 30 and x ≠ 4 Hence, the second pipe will take 30 hours to fill the tank.

Two pipes can fill a tank with water in 15 and 12 hours respectively and the third pipe can empty it in hours. If the pipers are opened in order at 8,9 and 11 A. M. respectively, the thank will be emptied at

Let the tank be emptied in x hrs after 8 A.M. ∴ Tank filled by pipe in x hours = 1 5 x ​ Tank filled by second pipe in (x - 1) hours = 1 2 ( x − 1 ) ​ Tank emptied by third pipe in (x - 3) hours = 4 ( x − 3 ) ​ ∴ 1 5 x ​ + 1 2 ( x − 1 ) ​ − 4 ( x − 3 ) ​ = 0 ⇒ 6 0 4 x + 5 ( x − 1 ) − 1 5 ( x − 3 ) ​ = 0 4 x + 5 x − 5 − 1 5 x + 4 5 = 0 ⇒ − 6 x + 4 0 = 0 ⇒ x = 6 4 0 ​ = 3 2 0 ​ = 6 3 2 ​ h r s = 6 h r s 4 0 m i n ∴ The tank will be emptied at 2 : 40 p.m.

Aptitude Questions: Pipes & Cistern Set 2

Click Here Click Here Hello Aspirants. Welcome to Online Quantitative Aptitude Section with explanation in AffairsCloud.com. Here we are creating question sample in Pipes & Cistern which is common for all competitive exams. We have included Some questions that are repeatedly asked in bank exams !!! • Two pipes A and B can fill a tank in 4 hours and 5 hours respectively. If they are opened on alternate hours and if pipe B is opened first, in how many hours, the tank fill in A.7hrs B.6hrs C.4.30hrs D.5hrs E.None of these Answer – C.4.30hrs Explanation : A+B = 1/4+1/5=9/20…………..2h A+B = 18/20………………………4h =9/10 Remaining = 1-9/10 = 1/10…it take 1/2 hr=> B Already 4+ remaining 2(B) = 4+1/2 = 4.30hrs • A tap can fill a tank completely in 6 hours. After half the tank is filled , one more similar tap is opened. What is the total time taken to fill the tank completely ? A.4hrs 20min B.3hrs 30min C.3hrs 10min D.4hrs 30min E.None of these Answer – D. 4hrs 30min Explanation : Tab fill the half tank in 3hrs Now another similar tab opened 1/6+1/6 = 2/6 = 1/3 Remaining half tank filled in 1.5hrs Total time = 3+1.5 = 4hrs 30min • A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 7 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled? A.9.00hrs B.9.20hrs C.9.30hrs D.9.33hrs E.None of these Answer – D. 9.33hrs Explanation : 1/4 – 1/7 = 7-4/28 Cistern filled in = 28/3 = 9.33hrs • A pipe can fill a tank in 5...

Two pipes A and B can fill a cistern in 8 hours and 12 hours respectively. The pipes when opened simultaneously takes

Correct answer is: (d) 120 hrs. Portion of cistern filled by both pipes in 1 hour = \(\frac\) Time taken by leakage to empty the tank=120 h Categories • • (31.9k) • (8.8k) • (764k) • (248k) • (10.0k) • (5.6k) • (36.4k) • (7.5k) • (10.7k) • (11.8k) • (11.2k) • (6.8k) • (4.9k) • (5.3k) • (2.8k) • (19.9k) • (959) • (2.9k) • (5.2k) • (664) • (121k) • (72.1k) • (3.8k) • (19.6k) • (1.4k) • (14.2k) • (12.5k) • (9.3k) • (7.7k) • (3.9k) • (6.7k) • (63.8k) • (26.6k) • (23.7k) • (14.6k) • (25.7k) • (530) • (84) • (766) • (49.1k) • (63.8k) • (1.8k) • (59.3k) • (24.5k)

Two pipes together can fill a tank in 12 hours. If the first pipe can fill the tank 10 hours faster than the second then how many hours will the second pipe take to fill the tank?

Let the time required to fill the tank by second pipe be x hours. Then, the time required to fill the tank by first pipe is (x − 10) hours. Given: Two pipes together can fill a tank in 12 hours. According to the question, 1 x + 1 x - 10 = 1 12 ⇒ x - 10 + x x x - 10 = 1 12 ⇒ 2 x - 10 x 2 - 10 x = 1 12 ⇒ 24 x - 120 = x 2 - 10 x ⇒ x 2 - 10 x - 24 x + 120 = 0 ⇒ x 2 - 34 x + 120 = 0 ⇒ x 2 - 30 x - 4 x + 120 = 0 ⇒ x x - 30 - 4 x - 30 = 0 ⇒ x - 30 x - 4 = 0 ⇒ x = 30 , 4 But x - 10 is the time required by the first pipe to fill the tank , which is always positive . Thus , x = 30 and x ≠ 4 Hence, the second pipe will take 30 hours to fill the tank.

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