Two trains, 250 meters and 150 meters long respectively, are running on parallel lines. if they are running in the same directions, the faster train crosses the slower train in 40 seconds. if they are moving in the opposite direction they pass each other in eight seconds. what is the speed of the slower train?

Registration gives you: • Tests Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan Prep. All are free for GMAT Club members. • Applicant Stats View detailed applicant stats such as GPA, GMAT score, work experience, location, application status, and more • Books/Downloads Download thousands of study notes, question collections, GMAT Club’s Grammar and Math books. All are free! and many more benefits! The answer is 20 m/s. Let the faster train run at x m/s and the slower train run at y m/s. The first statement states that it will take 70 seconds to cross each other running in the same direction. The first important thing her is that the faster train is behind the slower train, otherwise they would never cross. Secondly, in order to cross the slower train, the faster train will need to cover 350m MORE (250 m + 100 m) in the 70 seconds than the other train. \(\frac = 1\) \(35 = x + y\) (Equation 2) Solving these two equations, you get x = 20 m/s, and y = 15 m/s. Two trains of length 100m and 250m run on parallel lines. when they run in the same direction it will take 70 sec to cross each other and when they run in opposite direction, they take 10 sec to cross each other. find the speed of faster train. Alternative approach: To cross each other (either in same or opposite direction), the trains have to cover a distance of 250 + 100 = 350 m (the faster train should cover the entire slower train and then its own length so that they complete...

More • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • The correct option is D 16 s Given, Speed of train1 S 1 = 40 km/hr Length of train 1 = 150m Speed of train2 S 2 = 32 km/hr Length of train 2 = 170m Relative speed of train = ( S 1 + S 2 ) = ( 32 + 40 ) = 72 km/hr Converting it into m/s, 72 × 5 18 = 20 m/s Time taken by the two trains to cross each other = Sum of the lengths of the trains Relative speed of the trains = 150 + 170 20 = 320 20 = 16 s

Given: Length of train 1 = 150 m Length of train 2 = 250 m Speed of train 1 = 40 km/hr Speed of train 2 = 50 km/hr Formula used: Distance = Speed × Time When the two objects travel in the opposite direction their relative speed = (a + b) km/hr Calculation: Total distance = 150 m + 250 m = 400m Relative speed = (40 + 50) = 90 km/hr ⇒ 90 × (5/18) = 25m/sec ⇒ Time = 400/25 = 16 sec ∴ They will pass each other in 16 seconds

Question Download Solution PDF Two trains of length 300 m and 100 m respectively run on parallel lines of rails. When running in the same direction the faster train passes the slower train in 40 seconds. When they run in opposite directions with the same speed as earlier, they pass each other in 20 seconds. Find the speed of the slower train. Let the speed of faster train be x and that of slower train be y ⇒ Distance to be crossed by the faster train = Sum of length of both trains = 400 m Train travelling in same direction: ⇒ Time taken = 40 sec In same direction, ⇒ Relative speed = x – y = 400/40 = 10 m/s(I) Train travelling in opposite direction: ⇒ Time taken = 20 sec In opposite direction, ⇒ Relative speed = x + y = 400/20 = 20 m/s (II) Adding (I) and (II), ⇒ 2x = 30 m/s ⇒ x = 15 m/s Substitute in (1), ⇒ 15 – y = 10 m/s∴ y = 5 m/s SBI PO Final Result Out ((Advertisement No. CRPD/PO/2022-23/18)! Candidates who are qualified in the mains exam are eligible to attend the Interview, Group Exercise and Psychometric Test. The Group Exercise and Interview will be held in April 2023. The State Bank of India (SBI) released the official notification of the

The correct option is D 80sec Time = Distance traveled / Speed Here, distance = Sum of the lengths of the two trains = 250 m + 150 m = 400 m And, speed here is the relative speed between two trains = 50 km/hr - 32 km/hr (as they are moving in the same direction) = 18 km/hr We have to convert this relative speed into m/s, so, 18 × 5 18 = 5 m / s So, time taken =400/5 = 80 seconds

Two trains, 250 metres and 150 metres long respectively, are running on parallel lines. If they are running in the same directions, the faster train crosses the slower train in 40 seconds. If they are moving in the opposite direction they pass each other in eight seconds. What is the speed of the slower train? Next Question Two persons , Ram & Lakshman , who are at a distance of 100 km from each other, move towards each other from two places P and Q at speeds of 20 kmph and 25 kmph respectively. Lakshman reaches P, returns immediately and meets Ram at R, who started on the return journey to P immediately after reaching Q. What is the distance between Q and R?

Length of each train = 500 m Effective distance which needs to be covered by each train to cross over = 500 + 500 = 1000 m velocity of first train = 10 m/s velocity of second train = 15 m/s net relative velocity = 15 - (-10) (as the trains are travelling in opposite directions) = 25 m/s time taken to travel 1000 with velocity 25 m/s = 1000 / 25 = 40 seconds

Time, Speed and Distance- Distance= Speed*time For a non-uniform motion Average speed= Total distance travelled/Total time taken When the body travels at ‘u’ m/s for t1 seconds and ‘v’ m/s for t2 seconds, then Average speed= (ut1+vt2)/(t1+t2) When the body travels l distance at ‘u’ m/s and ‘m’ distance at ‘v’ m/s; Average speed = (mu+lv)/(l+m) Relative Speed: Speed of a moving body w.r.t. another moving body is called relative speed. Speed of A w.r.t. B (i) When they are moving in same direction; Relative speed of A= A-B (ii) When they are moving in opposite direction; Relative speed of A= A+B Key points on Trains When a train is crossing a pole distance travelled by the train= length of train When a train of length l is crossing a bridge of length b; the distance travelled by train=l+b When a train of length l is crossing a platform of length p; then distance travelled by train=l+p When a train of length l1 is crossing/ overtaking another train l2; then distance travelled = l1+l2 Exercise questions 1.Train A traveling at 60 km/hr leaves Mumbai for Delhi at 6 P.M. Train B traveling at 90 km/hr also leaves Mumbai for Delhi at 9 P.M. Train C leaves Delhi for Mumbai at 9 P.M. If all three trains meet at the same time between Mumbai and Delhi, what is the speed of Train C if the distance between Delhi and Mumbai is 1260 kms? A) 60 km/hr B) 90 km/hr C) 120 km/hr D) 135 km/hr 2.Two trains A and B start simultaneously from stations X and Y towards each other respectively. After m...