A student measured the diameter of a small steel ball

A student measued the diameter of a small steel ball using a screw gauge of least count `1.001 cm`. The main scale reading is `5 mm` and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero erroof `-0.004 cm`, the correct diameter of the ball is A. `0.529 cm` B. `0.521 cm` C. `0.503 cm` D. `0.525 cm`

A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of -0.004 cm, the correct diameter of the ball is Question A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of -0.004 cm, the correct diameter of the ball is

Pitch of the circular scale P = 0 . 5 m m Number of divisions on circular scale N = 5 0 So least count of screw gauge L.C = N P ​ = 5 0 0 . 5 ​ m m = 0 . 0 1 m m Now, main scale reading is given as M.S.R = 2 m m Marking on circular scale n = 2 5 Thus, diameter of sphere d = M . S . R + n × L . C ⟹ d = 2 m m + 2 5 × 0 . 0 1 m m = 2 . 2 5 m m Thus option D is correct. A student measured the diameter of a small steel ball using a screw gauge of least count 0 . 0 0 1 c m . The main scale reading is 5 m m and zero of circular scale division coincides with 2 5 divisions above the reference level. If screw gauge has a zero error of - 0 . 0 0 4 c m , the correct diameter of the ball is In a screw gauge, 5 complete rotations of the screw cause it to move a linear distance of 0 . 2 5 c m. There are 1 0 0 circular scale divisions. The thickness of a wire measured by this screw gauge gives a reading of 4 main scale divisions and 3 0 circular scale divisions. Assuming negligible zero error, the thickness of the wire is: When the gap is closed without placing any object in the screw gauge, whose least count is 0 . 0 0 5 m m, then the 5 t h division on its circular scale is with the reference line on the main scale. When a small sphere is placed reading on main scale advances by 4 divisions, whereas circular scale reading advances by five times to the corresponding reading when no object was placed. There are 2 0 0 divisions on the circular scale. The radius of the sphere is:-

A student measured the diameter of a small steel ball using a screw gauge of least count $0.001 \mathrm$ - Noon Academy

A student measured the diameter of a small steel ball using a screw gauge of least count 0.01 mm. The main scale reading is 0.5 cm and zero of circular scale coincides with 35 divisions above the reference level. If screw gauge has a zero error of − 0 , 002 cm, then the correct diameter of the ball is • 5.37 cm • 0.533 cm • 0.535 cm • 0.537 cm Views: 5,437 M emits γ-ray photon of frequency ' v'. capture, the energy liberated, (in kWh ), is: The loss of internal energy by the nucleus is : [Take ' c' as the speed of electromagnetic wave] [Mass of nucleon = 1 GeV / c 2 ] [Main Sep. 06 , 2020 ( i ) ] (a) 4.5 × 1 0 5 [July 20, 2021 (I)] 3. Find the Binding energy per neucleon for 50 120 ​ Sn. Mass of (a) hv (b) 0 proton m p ​ = 1.00783 U, mass of neutron m n ​ = 1.00867 U and mass of tin nucleus m Sn ​ = 119.902199 U. 10. (a) 20. (b) ​ (c) h v [ 1 − 2 Mc hv ​ ] ​ (d) h v [ 1 + 2 M c 2 h v ​ ] (take 1 U = 931 MeV ) [Main Sep. 04, 2020 (II)] (a) 7.5 MeV (b) 9.0 MeV (c) 8.0 MeV (d) 8.5 MeV 4. In a reactor, 2 kg of 92 ​ U 235 fuel is fully used up in 30 days. 30. (c) The energy released per fission is 200 MeV. Given that the Avogadro number, N = 6.023 × 1 0 26 per kilo mole and 1 eV 8. ( b , c ) Mass of 2 4 ​ He = 4.0026 u [Main Sep. 02, 2020 (1)] When 20 g of 3 7 ​ Li is converted into 2 4 ​ He by proton (a) 35 MW (b) 60 MW (c) 125 MW (d) 54 MW A student measured the diameter of a small steel ball using a screw gauge of least count 0.01 mm. The main scale reading is 0.5 cm and zer...

A student measured the diameter of a small steel ball using a screw gauge of least count 0.001cm. The main scale reading is 5 mm and zero of circular scale division coincides with 25 divisions above the reference level . If the screw gauge has a zero error of -0.004 cm,then what is the correct diameter of the ball? A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of –0.004 cm, the correct diameter of the ball is. 0.521 cm.