Show the formation of na2o and mgo by the transfer of electrons

Solution a) Sodium has one electron in the outermost shell while oxygen has six. To complete its octet. Oxygen needs two more electrons. But to complete the octet, sodium loses one electron. In order to equalise the number of electrons lost and gained, two atoms of sodium combine with one atom of oxygen. The formation of N a 2 O is shown below b) Bronze is made up of copper and tin.

Sodium sulphate is soluble in water whereas barlum sulphate is sparingly soluble because (a) the hydration energy of N a 2 ​ S O 4 ​ is less than its lattice energy (b) the hydration energy of N a 2 ​ S O 4 ​ is more than its lattice energy (c) the lattice energy of B a S O 4 ​ is more than its lattice energy. (d) the lattice energy has no rolw to play in solubility.

In this question, we want to find out the formation, the formation of a 2 o point, so here first, we can see that the sodium that is an a has total 11 electrons 11 electrons. Therefore, if we write the electron configuration electron configuration of it, then it becomes 1 s. 22 s. 22. P, 63 s 1. So so this will lose 1 electron to form to form n a plus iron. Now the oxygen. Now we know that the oxygen is the 8, an electro 8 element of the periodic table, so it has 8 electrons. So if we write the electron configuration configuration for the oxygen, then it becomes 1 s. 22 s. 22. P. 4 point now here this will gainin gain 2 electrons 2 electrons to form o 2 minus iron. Now to form this 2 sodium irons are needed to form final…