10th class maths quadratic equations exercise 5.2 solutions

i) x 2– 3x – 10 = 0 Solution: Given : x 2– 3x – 10 = 0 ⇒ x 2– 5x + 2x – 10 = 0 ⇒ x(x – 5) + 2 (x – 5) = 0 ⇒ (x – 5) (x + 2) = 0 ⇒ x – 5 = 0 or x + 2 = 0 ⇒ x = 5 or x = -2 ⇒ x = 5 or – 2 are the roots of the given Q.E. ii) 2x 2 + x – 6 = 0 (A.P.Mar. 16) Solution: Given : 2x 2 + x – 6 = 0 ⇒ 2x 2 + 4x – 3x – 6 = 0 ⇒ 2x(x + 2) – 3(x + 2) = 0 ⇒ (x + 2) (2x – 3) = 0 ⇒ x + 2 = 0 or 2x – 3 = 0 ⇒ x = -2 or 2x = 3 ⇒ x = -2 or \(\frac\) are the roots of the given Q.E. iii) \(\sqrt\) are the roots of given Q.E. v) 100x 2– 20x + 1 = 0 Solution: Given : 100x 2– 20x + 1 = 0 ⇒ 100x 2– 10x – 10x + 1 = 0 ⇒ 10x (10x – 1) – 1(10x – 1) = 0 ⇒ (10x – 1) (10x – 1) = 0 ⇒ 10x – 1 = 0 ⇒ 10x = 1 x = \(\frac\right]\) = 6 ⇒ 24(2x) = 6(x 2– 9) ⇒ 8x = x 2– 9 ⇒ x 2– 8x – 9 = 0 ⇒ x 2– 9x + x – 9 = 0 ⇒ x(x – 9) + 1(x – 9) = 0 ⇒ (x – 9) (x + 1) = 0 ⇒ x – 9 = 0 or x + 1 = 0 x can’t be negative. ∴ x = 9 i.e., speed of the boal in still water = 9 kmph. Categories

NCERT Solutions Class 10 Maths Chapter 4 Quadratic Equations – Here are all the Class 10 Maths Chapter 4 Quadratic Equations NCERT Solutions. This solution contains questions, answers, images, step by step explanation of the complete Chapter 4 titled Quadratic Equations in Class 10. If you are a student of Class 10 who is using NCERT Textbook to study Maths, then you must come across Chapter 4 Quadratic Equations. After you have studied lesson, you must be looking for answers to its textbook questions. Here you can get complete NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations in one place. • • • • • • • • • NCERT Solutions For Class 10 Maths Chapter 4 Quadratic Equations Ex 4.1 NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Ex 4.1 are part of Board CBSE Textbook NCERT Class Class 10 Subject Maths Chapter Chapter 4 Chapter Name Quadratic Equations Exercise Ex 4.1 Number of Questions Solved 2 Category Ex 4.1 Class 10 Maths Question 1. Check whether the following are quadratic equations: (i) (x+ 1) 2=2(x-3) (ii) x – 2x = (- 2) (3-x) (iii) (x – 2) (x + 1) = (x – 1) (x + 3) (iv) (x – 3) (2x + 1) = x (x + 5) (v) (2x – 1) (x – 3) = (x + 5) (x – 1) (vi) x 2 + 3x + 1 = (x – 2) 2 (vii) (x + 2) 3 = 2x(x 2– 1) (viii) x 3 -4x 2 -x + 1 = (x-2) 3 Solution: NCERT Solutions Class 10 Maths chapter 4 Quadratic Equations- Video You can also watch the video solutions of NCERT Class10 Maths chapter 4 Quadratic Equations here. Ex 4.1 Class 10 Maths Question 2. R...

ML Aggarwal Solutions for Class 10 Maths Chapter 5 – Quadratic Equations in One Variable are provided here to help students prepare for their exams at ease. This chapter mainly deals with problems based on quadratic equations in one variable. Students having any doubts about understanding the concepts can refer to Chapter 5 – Quadratic Equations in One Variable contains five exercises, and the Download PDF carouselExampleControls111 Previous Next Access answers to ML Aggarwal Solutions for Class 10 Maths Chapter 5 – Quadratic Equations in One Variable EXERCISE 5.1 1. In each of the following, determine whether the given numbers are roots of the given equations or not; (i) x 2– 5x + 6 = 0; 2, -3 (ii) 3x 2– 13x – 10 = 0; 5, -2/3 Solution: (i) x 2– 5x + 6 = 0; 2, -3 Let us substitute the given values in the expression and check, When, x = 2 x 2– 5x + 6 = 0 (2) 2– 5(2) + 6 = 0 4 – 10 + 6 = 0 0 = 0 ∴ x = 0 When, x = -3 x 2– 5x + 6 = 0 (-3) 2– 5(-3) + 6 = 0 9 + 15 + 6 = 0 30 = 0 ∴ x ≠ 0 Hence, the value x = 2 is the root of the equation. And value x = -3 is not a root of the equation. (ii) 3x 2– 13x – 10 = 0; 5, -2/3 Let us substitute the given values in the expression and check, When, x = 5 3x 2– 13x – 10 = 0 3(5) 2– 13(5) – 10 = 0 3(25) – 65 – 10 = 0 75 – 75 = 0 0 = 0 ∴ x = 0 When, x = -2/3 3x 2– 13x – 10 = 0 3(-2/3) 2– 13(-2/3) – 10 = 0 4/9 + 26/3 – 10 = 0 4/3 + 26/3 – 10 = 0 30/3 – 10 = 0 10 – 10 = 0 ∴ x = 0 Hence, the value x = 5, -2/3 are the roots of the equation. 2. In e...

NCERT Solutions are considered an extremely helpful resource for exam preparation. Meritnation.com gives its users access to a profuse supply of NCERT questions and their solutions. CBSE Class 10 Math NCERT Solutions are created by experts of the subject, hence, sure to prepare students to score well. The questions provided in NCERT Books are prepared in accordance with CBSE, thus holding higher chances of appearing on CBSE question papers. Not only do these NCERT Solutions for Class 10 Math strengthen students’ foundation in the subject, but also give them the ability to tackle different types of questions easily. Our Class 10 Math textbook solutions give students an advantage with practical questions. These textbook solutions help students in exams as well as their daily homework routine. The solutions included are easy to understand, and each step in the solution is described to match the students’ understanding. • Mathematics NCERT Grade 10, Chapter 1, REAL NUMBERS: This chapter starts with an introduction about real numbers. A partial discussion was done in class 9th about real numbers. Further going deep into this topic, two very important properties of a real number are discussed in the first two sections namely: 1. Euclid's division algorithm 2. The fundamental theorem of arithmetic Euclid's division algorithm consists of a brief description of Euclid's division lemma. The next exercise is based on the topic of revisiting irrational numbers. Various theorems are gi...

ML Aggarwal Quadratic Equations Exe-5.2 Class 10 ICSE Maths Solutions . We Provide Step by Step Answer of Exe-5.2 Questions for Quadratic Equations in One Variable as council prescribe guideline for upcoming board exam. Visit official Website ML Aggarwal Ch-5 Quadratic Equations in one Variable Exercise- 5.2 Class 10 ICSE Maths Solutions Board ICSE Publications Avichal Publishig Company (APC) Subject Maths Class 10th Chapter-5 Quadratic Equations in one Variable Writer ML Aggarwal Book Name Understanding Topics Solution of Exe-5.2 Questions Edition 2022-2023 Answer -1 (i) x² – 3x – 10 = 0 ⇒ x² – 5x + 2x – 10 = 0 ⇒ x(x – 5) + 2(x – 5) = 0 (x + 2) (x – 5) =0 So now, (x + 2) = 0 or (x – 5) =0 x = -2 or x = 5 ∴ Value of x = -2, 5 (ii) x(2x + 5) = 3 Let us simplify the given expression, 2x 2 + 5x – 3 = 0 Now, let us factorize 2x 2 + 6x – x – 3 = 0 2x(x + 3) -1(x + 3) = 0 (2x – 1) (x + 3) = 0 So now, (2x – 1) = 0 or (x + 3) = 0 2x = 1 or x = -3 x = ½ or x = -3 ∴ Value of x = ½, -3 Question-2 (i) 3x² – 5x – 12 = 0 (ii) 21x² – 8x – 4 = 0 Answer -2 (i) 3x² – 5x – 12 = 0 ⇒ 3x² – 9x + 4x – 12 = 0 ⇒ 3x (x – 3) + 4(x – 3) = 0 (3x + 4) (x – 3) =0 So now, (3x + 4) = 0 or (x – 3) =0 3x = -4 or x = 3 x = -4/3 or x = 3 ∴ Value of x = -4/3, 3 (ii) 21x 2 – 8x – 4 = 0 Let us simplify the given expression, 21x 2 – 14x + 6x – 4 = 0 7x(3x – 2) + 2(3x – 2) = 0 (7x + 2) (3x – 2) = 0 So now, (7x + 2) = 0 or (3x – 2) = 0 7x = -2 or 3x = 2 x = -2/7 or x = 2/3 ∴ Value of x = -2/7, 2/3 Question -3 (i) 3...