11th commerce maths 2 exercise 1.1 answers

Maharashtra State Board HSC 11th Commerce Mathematics and Statistics Digest Pdf, 11th Commerce Maharashtra State Board Maths Solution Book Pdf Part 1 & 2 free download in English Medium and Marathi Medium 2021-2022. Maharashtra State Board 11th Commerce Maths Digest Pdf 11th Maths Part 1 Digest Pdf 11th Maths 1 Digest Pdf Chapter 1 Sets and Relations • • • Mathematics and Statistics Commerce Part 1 Chapter 2 Functions • • 11th Maths Part 1 Digest Pdf Chapter 3 Complex Numbers • • • • 11th Commerce Maths Solutions Chapter 4 Sequences and Series • • • • • • Maths Commerce Class 11 Chapter 5 Locus and Straight Line • • • • • Maths in Commerce 11th Chapter 6 Determinants • • • • Class 11 Commerce Maths Part 1 Chapter 7 Limits • • • • • Commerce Maths Class 11 Chapter 8 Continuity • • 11th Commerce Maths 1 Textbook Pdf Chapter 9 Differentiation • • • 11th Commerce Maths Solution Book Pdf Part 2 11th Commerce Maths Book Pdf Chapter 1 Partition Values • • • • Class 11 Commerce Maths Book Chapter 2 Measures of Dispersion • • • • 11th Commerce Maths Textbook Pdf Chapter 3 Skewness • • Maths Class 11 Commerce Chapter 4 Bivariate Frequency Distribution and Chi Square Statistic • • • Maths 11th Commerce Chapter 5 Correlation • • Commerce Maths Book Class 11 Chapter 6 Permutations and Combinations • • • • • • • • Class 11 Maths Commerce Book Chapter 7 Probability • • • • • 11 Commerce Statistics Solutions Chapter 8 Linear Inequations • • • • 11th Maths Part 1 Digest Pdf Chapter 9 Comme...

Maharashtra State Board 11th Maths Solutions Guide Shaalaa provides solutions for Maharashtra State Board 11th Maths Solutions Digest. Shaalaa is undoubtedly a site that most of your classmates are using to perform well in exams. You can solve 11th Maths Book Solutions Maharashtra State Board textbook questions by using Shaalaa.com to verify your answers. This will help you practise better and become more confident. Balbharati Solutions for 11th Maths Chapterwise List | 11th Maths Digest The answers to the Balbharati books are the best study material for students. The following links are • • • • • • • • • Appears in • • Concepts covered in Bivariate Frequency Distribution and Chi Square Statistic are Bivariate Frequency Distribution, Categorical Variables, Chi-Square Statistic ( χ2 ), Classification and Tabulation of Bivariate Data, Conditional Frequency Distributions, Contingency Table, Marginal Frequency Distributions Concepts covered in Permutations and Combinations are Circular Permutations, Combination, Concept of Addition Principle, Concept of Factorial Function, Concept of Multiplication Principle, Fundamental Principles of Counting, Introduction of Permutations and Combinations, Permutations, Permutations When All Objects Are Distinct, Permutations When All Objects Are Not Distinct, Permutations When Repetitions Are Allowed, Properties of Combinations, Properties of Permutations Balbharati Solutions for Mathematics and Statistics 2 (Commerce) 11th Standard HSC Maha...

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Balbharati Maharashtra State Board Maharashtra State Board 11th Commerce Maths Solutions Chapter 1 Partition Values Ex 1.2 Question 1. Calculate D 6 and P 85 for the following data: 79, 82, 36, 38, 51, 72, 68, 70, 64, 63 Solution: The given data can be arranged in ascending order as follows: 36, 38, 51, 63, 64, 68, 70, 72, 79, 82 Here, n = 10 D 6 = value of 6\(\left(\frac\) observation = value of (85 × 0. 11)th observation = value of (9.35)th observation = value of 9th observation + 0.35(value of 10th observation – value of 9th observation) = 19 + 0.35(82 – 79) = 79 + 0.35(3) = 79 + 1.05 ∴ P 85 = 80.05 Question 2. The daily wages (in ₹) of 15 labourers are as follows: 230, 400, 350, 200, 250, 380, 210, 225, 375, 180, 375, 450, 300, 350, 250 Calculate D 8 and P 90. Solution: The given data can be arranged in ascending order as follows: 180, 200, 210, 225, 230, 250, 250, 300, 350, 350, 375, 375, 380, 400, 450 Here, n = 15 D 8 = value of 8\(\left(\frac\) observation = value of (65 × 2.01)th observation = value of (130.65)th observation The cumulative frequency which is just greater than (or equal to) 130.65 is 150. ∴ P 65 = 280 Question 4. From the following data calculate the rent of the 15th, 65th, and 92nd house. Solution: Arranging the given data in ascending order. Here, n = 100 P 15 = value of 15 = value of 15\(\left(\frac\) × 100 = 30% (b) The difference between any two consecutive mid values of weight is 5 kg. The class intervals must of width 5, with 40, 45,….. as th...

Balbharati Maharashtra State Board Maharashtra State Board 11th Commerce Maths Solutions Chapter 1 Sets and Relations Ex 1.2 Question 1. If (x – 1, y + 4) = (1, 2), find the values of x and y. Solution: (x – 1, y + 4) = (1, 2) By the definition of equality of ordered pairs, we have x – 1 = 1 and y + 4 = 2 ∴ x = 2 and y = -2 Question 2. If \(\left(x+\frac Categories Post navigation

Balbharati Maharashtra State Board Maharashtra State Board 11th Commerce Maths Solutions Chapter 1 Partition Values Ex 1.1 Question 1. Compute all the quartiles for the following series of observations: 16, 14.9, 11.5, 11.8, 11.1, 14.5, 14, 12, 10.9, 10.7, 10.6, 10.5, 13.5, 13, 12.6 Solution: The given data can be arranged in ascending order as follows: 10.5, 10.6, 10.7, 10.9, 11.1, 11.5, 11.8, 12, 12.6, 13, 13.5, 14, 14.5, 14.9, 16 Here, n = 15 Q 1 = value of \(\left(\frac\) observation = value of (3 × 4)th observation = value of 12th observation ∴ Q 3 = 14 Question 2. The heights (in cm.) of 10 students are given below: 148, 171, 158, 151, 154, 159, 152, 163, 171, 145 Calculate Q 1 and Q 3 for the above data. Solution: The given data can be arranged in ascending order as follows: 145, 148, 151, 152, 154, 158, 159, 163, 171, 171 Here, n = 10 Q 1 = value of \(\left(\frac\) observation = value of (3 × 25.25)th observation = value of (75.75)th observation Cumulative frequency which is just greater than (or equal to) 75.75 is 87. ∴ Q 3 = 650 ∴ the expenditure below which 75% of families include their expenditure is ₹ 650. Question 5. Calculate all the quartiles for the following frequency distribution: Solution: We construct the less than cumulative frequency table as given below: Here, n = 300 Q 1 = value of \(\left(\frac\) observation = value of (3 × 75.25)th observation = value of (225.75)th observation Cumulative frequency which is just greater than (or equal to) 225.75 i...