25.3 g of sodium carbonate

25.3 g of sodium carbonate,Na2CO3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ion,Na+and carbonate ions, CO32-respectively are (Molar mass of Na2 CO3 = 106 mol-1) 25.3 g of sodium carbonate,Na 2CO 3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ion, Na +and carbonate ions, CO 3 2 -respectively are (Molar mass of Na 2 CO 3 = 106 mol -1)

25.3 g of sodium carbonate, Na2CO3 is dissolved in enough water to make 250 mL ofsolution.If sodium carbonate dissociatescompletely, molar concentration of sodium ions, Na+and carbonate ions CO2-3are respectively(Molar mass of Na2CO3 = 106 g mol-1)a)0.955 M and 1.910 Mb)1.910 M and 0.955 Mc)1.90 M and 1.910Md)0.477 M and 0.477 MCorrect answer is option 'B'. Can you explain this answer? | EduRev NEET Question Direction: Read the passage given below and answer the following questions:Boiling point or freezing point of liquid solution would be affected by the dissolved solids in the liquid phase. A soluble solid in solution has the effect of raising its boiling point and depressing its freezing point. The addition of non-volatile substances to a solvent decreases the vapour pressure and the added solute particles affect the formation of pure solvent crystals.According to many researches the decrease in freezing point directly correlated to the concentration of solutes dissolved in the solvent. This phenomenon is expressed as freezing point depression and it is useful for several applications such as freeze concentration of liquid food and to find the molar mass of an unknown solute in the solution. Freeze concentration is a high quality liquid food concentration method where water is removed by forming ice crystals. This is done by cooling the liquid food below the freezing point of the solution. The freezing point depression is referred as a colligative property and it is pr...

25.3 g of Sodium carbonate Na2CO3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ion, Na+ and carbonate ionCO32-are respectively (Molar mass of Na2CO3 = 106 g mol-1) 1. 0.955 M and 1.910 M 2. 1.910 M and 0.955 M 3. 1.90 M and 1.910 M 4. 0.477 M and 0.477 M Some Basic Concepts Of Chemistry Chemistry - Past Year Questions NEET Practice Questions, MCQs, Past Year Questions (PYQs), NCERT Questions, Question Bank, Class 11 and Class 12 Questions, and PDF solved with answers • Recommended MCQs - 118 Questions • Recommended PYQs (STRICTLY NCERT Based) • NCERT Solved Examples Based MCQs • NCERT Exemplar (Objective) Based MCQs • AR & Other Type MCQs • Past Year (2019 onward - NTA Papers) MCQs • Past Year (2016 - 2018) MCQs • Past Year (2006 - 2015) MCQs • Past Year (1998 - 2005) MCQs 25.3 g of Sodium carbonate Na 2CO 3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ion, Na + and carbonate ion CO 3 2 -are respectively (Molar mass of Na 2CO 3 = 106 g mol -1) 1. 0.955 M and 1.910 M 2. 1.910 M and 0.955 M 3. 1.90 M and 1.910 M 4. 0.477 M and 0.477 M

The correct option is C 1.910 M and 0.955 M Molarity = n s o l u t e × 1000 V s o l u t i o n ( m L ) = 25.3 × 1000 106 × 250 = 0.955 M In aquous solution, N a 2 C O 3 dissociates as; N a 2 C O 3 → 2 N a + + C O − 2 3 ∴ Molarity o f N a + = 2 × 0.955 M = 1.910 M And, Molarity o f C O 2 − 3 = 0.955 M Hence the correct answer is option (c).

25.3 g of sodium carbonate N a 2 CO 3 is dissolved in enough water to make 250 mL of a solution. If it dissociates completely, the molar concentration of sodium ions N a +and the carbonate ions CO 32 are respectively:Molar mass of N a 2 CO 3=106 g mol 1 A. 0.956 M and 0.478 MB. 1.912 M and 0.956 MC. 2.122 M and 1.061 MD. 0.954 M and 0.477 M The correct option is B 1.912 M and 0.956 M Number of moles of N a 2 C O 3 = given mass (g) molar mass (g/mol) = 25.3 106 = 0.239 molarity = moles of solute of N a 2 C O 3 total volume of solution in mL × 1000 molarity = 0.239 250 × 1000 = 0.956 M According to the reaction: N a 2 C O 3 → 2 N a + + C O 2 − 3 1 M N a 2 C O 3 will dissociate to 2 M of N a + and 1 M of C O 2 − 3 0.956 M N a 2 C O 3 dissociates to 2 × 0.956 M N a + = 1.912 M 0.956 M N a 2 C O 3 dissociates to 0.956 M of C O 2 − 3

6 8 . 4 g of A l 2 ​ ( S O 4 ​ ) 3 ​ is dissolved in enough water to make 5 0 0 m L of solution. If aluminium sulphate dissociates completely then molar concentration of aluminium ions ( A l 3 + ) and sulphate ions ( S O 4 2 − ​ ) in the solution are respectively (molar mass of A l 2 ​ ( S O 4 ​ ) 3 ​ = 3 4 2 g m o l − 1 )