A refrigerator whose coefficient of performance is 6

This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer See Answer See Answer done loading Question:A refrigerator has a coefficient of performance equal to 6.00. The refrigerator takes in 135 J of energy from a cold reservoir in each cycle.

This problem has been solved: Solutions for Chapter 4 Problem 31P: Refrigerators and Heat Pumps If a refrigerator discards 80 J of heat per cycle and its coefficient of performance is 6.0, what are (a) the quantity off heat it removes per cycle from a cold reservoir and (b) the amount of work per cycle required for its operation? … Get solutions Get solutions Get solutions done loading • 1CQ • 2CQ • 3CQ • 4CQ • 5CQ • 6CQ • 7CQ • 8CQ • 9CQ • 10CQ • 11CQ • 12CQ • 13CQ • 14CQ • 15CQ • 16CQ • 17CQ • 18P • 19P • 20P • 21P • 22P • 23P • 24P • 25P • 26P • 27P • 28P • 29P • 30P • 31P • 32P • 33P • 34P • 35P • 36P • 37P • 38P • 39P • 40P • 41P • 42P • 43P • 44P • 45P • 46P • 47P • 48P • 49P • 50P • 51P • 52P • 53P • 54P • 55P • 56P • 57P • 58P • 59P • 60P • 61P • 62P • 63P • 64P • 65P • 66P • 67AP • 68AP • 69AP • 70AP • 71AP • 72AP • 73AP • 74AP • 75AP • 76AP • 77AP • 78AP • 79AP • 80AP • 81AP • 82AP • 83CP • 84CP • 85CP • 86CP • 87CP • 88CP • 89CP • 90CP • 91CP • 92CP • 93CP The co-efficient of performance, can be expressed as, Here, heat removed from cold reservoir per cycle is and work done per cycle is . The work done is expressed as follows, Here, is the heat discarded from hot reservoir. Therefore, the above expression of co-efficient of performance can be written as follows, Substitute for W in the equation , University Physics Volume 2 (0th Edition) Solutions for Chapter 4 Problem 31P: Refrigerators and Heat Pumps If a refrigerator discards 80 J of heat per cycle and its co...

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https://phys.libretexts.org/@app/auth/3/login?returnto=https%3A%2F%2Fphys.libretexts.org%2FBookshelves%2FUniversity_Physics%2FBook%253A_University_Physics_(OpenStax)%2FBook%253A_University_Physics_II_-_Thermodynamics_Electricity_and_Magnetism_(OpenStax)%2F04%253A_The_Second_Law_of_Thermodynamics%2F4.05%253A_Statements_of_the_Second_Law_of_Thermodynamics Expand/collapse global hierarchy • Home • Bookshelves • University Physics • Book: University Physics (OpenStax) • University Physics II - Thermodynamics, Electricity, and Magnetism (OpenStax) • 4: The Second Law of Thermodynamics • 4.5: Statements of the Second Law of Thermodynamics Expand/collapse global location \( \newcommand\) • • • • • • • Learning Objectives By the end of this section, you will be able to: • Contrast the second law of thermodynamics statements according to Kelvin and Clausius formulations • Interpret the second of thermodynamics via irreversibility Earlier in this chapter, we introduced the Clausius statement of the second law of thermodynamics, which is based on the irreversibility of spontaneous heat flow. As we remarked then, the second law of thermodynamics can be stated in several different ways, and all of them can be shown to imply the others. In terms of heat engines, the second law of thermodynamics may be stated as follows: Second Law of Thermodynamics (Kelvin statement) It is impossible to convert the heat from a single source into work without any other effect. This is known as the Kelvin...

This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer See Answer See Answer done loading Question:Problem 5 (9 points) At steady state, a refrigerator whose coefficient of performance is 3 removes energy by heat transfer from a freezer compartment at 0°C at the rate of 6000 kJ/h and discharges energy by heat transfer to the surroundings, which are at 20°C. (a) Determine the power input to the refrigerator and compare with the power input required by a Problem 5 (9 points) At steady state, a refrigerator whose coefficient of performance is 3 removes energy by heat transfer from a freezer compartment at 0°C at the rate of 6000 kJ/h and discharges energy by heat transfer to the surroundings, which are at 20°C. (a) Determine the power input to the refrigerator and compare with the power input required by a reversible refrigeration cycle operating between reservoirs at these two temperatures. (6 points) (b) If electricity costs 8 cents per determine the actual and minimum theoretical operating costs, each in $/day. (3 points) Previous question Next question