A survey was conducted for 180 people in a city. 70 ate pizza, 60 ate burgers and 50 ate chips. draw a pie diagram for the given information.

  1. Solved To help plan the number of meals to be prepared in a
  2. A survey of 540 adults aged 18
  3. Venn
  4. Markov Chain and Steady States
  5. Solved To help plan the number of meals to be prepared in a
  6. A survey of 540 adults aged 18
  7. Markov Chain and Steady States
  8. Markov Chain and Steady States
  9. Solved To help plan the number of meals to be prepared in a
  10. A survey of 540 adults aged 18


Download: A survey was conducted for 180 people in a city. 70 ate pizza, 60 ate burgers and 50 ate chips. draw a pie diagram for the given information.
Size: 40.43 MB

Solved To help plan the number of meals to be prepared in a

This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer See Answer See Answer done loading Question:To help plan the number of meals to be prepared in a college cafeteria, a survey was conducted, and the following data were obtained. 127 students ate breakfast. 181 students ate lunch. 270 students ate dinner. 60 students ate breakfast and lunch. 111 students ate breakfast and dinner. 95 students ate lunch and dinner. To help plan the number of meals to be prepared in a college cafeteria, a survey was conducted, and the following data were obtained. 127 students ate breakfast. 181 students ate lunch. 270 students ate dinner. 60 students ate breakfast and lunch. 111 students ate breakfast and dinner. 95 students ate lunch and dinner. 54 students ate all three meals. How many students ate (a) At least one meal in the cafeteria? (b) Exactly one meal in the cafeteria? (c) Only dinner in the cafeteria? (d) Exactly two meals in the cafeteria?

A survey of 540 adults aged 18

171 watch tv 150 hung out with friends 200 ate pizza but did not hang out with friends 28 watched Tv and ate pizza but did not hang out with friends 44 watched Tv and hung out with friends, but did not eat pizza 31 hung out with friends and ate pizza but did not watch TV 33 watched TV hung out with friends and ate pizza how many 18-24 yearolds did not do any of these three activities last friday night? This was a fun little puzzle. If we number the statements (and reorder their contents so they all have the same information in the same order), we get the following: 1) 171 watched TV 2) 150 hung out with friends 3) 200 did not hang out with friends, ate pizza 4) 28 watched TV, did not hang out with friends, ate pizza 5) 44 watched TV, hung out with friends, did not eat pizza 6) 31 did not watch TV, hung out with friends, ate pizza 7) 33 watched TV, hung out with friends, ate pizza Combing 3) and 4) you get 8) as follows: 8) 172 did not watch TV, did not hang out with friends, ate pizza Combing 5) and 7) you get 9) as follows: 9) 77 watched TV hung out with friends Combing 2) and 9) you get 10) as follows: 10) 73 did not watch TV, hung out with friends By negating 1) you get 11 as follows: 11) 369 did not watch TV Combing 10) and 11) you get 12) as follows: 12) 296 did not watch TV did not hang out with friends Combining 8) and 12) you get the final conclusion 13) as follows: 13) 124 did not watch TV, did not hang out with friends, did not eat pizza ¢ € £ ¥ ‰ µ · • § ¶ ß ‹ ›...

Venn

A survey of 550 adults aged 18-24 year olds was conducted in which they were asked what they did last Friday night. It found: 157 watched TV 151 hung out with friends 47 watched TV and ate pizza, but did not hang out with friends 50 watched TV and hung out with friends, but did not eat pizza 32 hung out with friends and ate pizza, but did not watch TV 41 watched TV, hung out with friends, and ate pizza 55 did not do any of these three activities How may 18-24 year olds (of these three activities) only ate pizza last Friday night? RELATED QUESTIONS Total - 60,000 people - 33,000 bike - 40,000 jog - 16,000- bike and jog.How many do neither? Answers · 1 52 were asked if they liked salad and tofu. 12 didn't like salad or tofu. 10 like salad and tofu and 13 liked only salad. How many students like only tofu? Answers · 1 basedon venn diagram Answers · 1 based on venn diagram Answers · 1 Use sets to solve the problem. Answers · 3 RECOMMENDED TUTORS

Markov Chain and Steady States

I've been given the following problem and I want to know if the answer that I found makes sense. A student center cafeteria has three fast-food centers - serving burgers, tacos, and pizza.A survey of students found the following information concerning lunch: 75% who ate burgers will eat burgers again at the next lunch, 5% will eat tacos next, and 20% will eat pizza next. Of those who ate tacos last, 20% will eat burgers next, 60% will stay with tacos, and 20% will eat pizza next. Of those who ate pizza, 40% will eat burgers next, 20% tacos, and 40% pizza again. Assume initially that one-third of students ate at each of the burger, taco, and pizza stations. Find the long-term behavior of the students regarding fast food. Explain and interpret your findings. What I found is the following matrix(approximate numbers): $\begin$ So when I explain my findings I believe that this is a steady state and the matrix has reached equilibrium. So in the long run 55% of the students who ate burgers will eat burgers again the next day, 55% of the students that ate tacos will eat burgers the next day, 55% of the students that ate pizza will eat burgers the next day, so on and so forth. Does this sound accurate?? So in the long run 55% of the students who ate burgers will eat burgers again the next day Not really. On the long run $55\%$ of the students will eat burgers. The equation to calculate the steady state is $A\cdot \vec x=\vec x$ Thus your result is a vector not a matrix. $\vec x=\le...

Solved To help plan the number of meals to be prepared in a

• • • • Question:To help plan the number of meals to be prepared in a college cafeteria, a survey was conducted and the following data were obtained. Draw a Venn diagram and answer the questions that follow. 400 students ate breakfast 250 students ate lunch 425 students ate dinner 80 students ate dinner, but not breakfast or lunch 70 students ate breakfast and lunch 60 To help plan the number of meals to be prepared in a college cafeteria, a survey was conducted and the following data were obtained. Draw a Venn diagram and answer the questions that follow. 400 students ate breakfast 250 students ate lunch 425 students ate dinner 80 students ate dinner, but not breakfast or lunch 70 students ate breakfast and lunch 60 students ate lunch and dinner 16 students ate all three meals In the cafeteria, how many of the students ate a. breakfast and lunch, but not dinner? b. at least one meal? C. exactly one meal? Previous question Next question

A survey of 540 adults aged 18

171 watch tv 150 hung out with friends 200 ate pizza but did not hang out with friends 28 watched Tv and ate pizza but did not hang out with friends 44 watched Tv and hung out with friends, but did not eat pizza 31 hung out with friends and ate pizza but did not watch TV 33 watched TV hung out with friends and ate pizza how many 18-24 yearolds did not do any of these three activities last friday night? This was a fun little puzzle. If we number the statements (and reorder their contents so they all have the same information in the same order), we get the following: 1) 171 watched TV 2) 150 hung out with friends 3) 200 did not hang out with friends, ate pizza 4) 28 watched TV, did not hang out with friends, ate pizza 5) 44 watched TV, hung out with friends, did not eat pizza 6) 31 did not watch TV, hung out with friends, ate pizza 7) 33 watched TV, hung out with friends, ate pizza Combing 3) and 4) you get 8) as follows: 8) 172 did not watch TV, did not hang out with friends, ate pizza Combing 5) and 7) you get 9) as follows: 9) 77 watched TV hung out with friends Combing 2) and 9) you get 10) as follows: 10) 73 did not watch TV, hung out with friends By negating 1) you get 11 as follows: 11) 369 did not watch TV Combing 10) and 11) you get 12) as follows: 12) 296 did not watch TV did not hang out with friends Combining 8) and 12) you get the final conclusion 13) as follows: 13) 124 did not watch TV, did not hang out with friends, did not eat pizza ¢ € £ ¥ ‰ µ · • § ¶ ß ‹ ›...

Markov Chain and Steady States

I've been given the following problem and I want to know if the answer that I found makes sense. A student center cafeteria has three fast-food centers - serving burgers, tacos, and pizza.A survey of students found the following information concerning lunch: 75% who ate burgers will eat burgers again at the next lunch, 5% will eat tacos next, and 20% will eat pizza next. Of those who ate tacos last, 20% will eat burgers next, 60% will stay with tacos, and 20% will eat pizza next. Of those who ate pizza, 40% will eat burgers next, 20% tacos, and 40% pizza again. Assume initially that one-third of students ate at each of the burger, taco, and pizza stations. Find the long-term behavior of the students regarding fast food. Explain and interpret your findings. What I found is the following matrix(approximate numbers): $\begin$ So when I explain my findings I believe that this is a steady state and the matrix has reached equilibrium. So in the long run 55% of the students who ate burgers will eat burgers again the next day, 55% of the students that ate tacos will eat burgers the next day, 55% of the students that ate pizza will eat burgers the next day, so on and so forth. Does this sound accurate?? So in the long run 55% of the students who ate burgers will eat burgers again the next day Not really. On the long run $55\%$ of the students will eat burgers. The equation to calculate the steady state is $A\cdot \vec x=\vec x$ Thus your result is a vector not a matrix. $\vec x=\le...

Markov Chain and Steady States

I've been given the following problem and I want to know if the answer that I found makes sense. A student center cafeteria has three fast-food centers - serving burgers, tacos, and pizza.A survey of students found the following information concerning lunch: 75% who ate burgers will eat burgers again at the next lunch, 5% will eat tacos next, and 20% will eat pizza next. Of those who ate tacos last, 20% will eat burgers next, 60% will stay with tacos, and 20% will eat pizza next. Of those who ate pizza, 40% will eat burgers next, 20% tacos, and 40% pizza again. Assume initially that one-third of students ate at each of the burger, taco, and pizza stations. Find the long-term behavior of the students regarding fast food. Explain and interpret your findings. What I found is the following matrix(approximate numbers): $\begin$ So when I explain my findings I believe that this is a steady state and the matrix has reached equilibrium. So in the long run 55% of the students who ate burgers will eat burgers again the next day, 55% of the students that ate tacos will eat burgers the next day, 55% of the students that ate pizza will eat burgers the next day, so on and so forth. Does this sound accurate?? So in the long run 55% of the students who ate burgers will eat burgers again the next day Not really. On the long run $55\%$ of the students will eat burgers. The equation to calculate the steady state is $A\cdot \vec x=\vec x$ Thus your result is a vector not a matrix. $\vec x=\le...

Solved To help plan the number of meals to be prepared in a

This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer See Answer See Answer done loading Question:To help plan the number of meals to be prepared in a college cafeteria, a survey was conducted, and the following data were obtained. 127 students ate breakfast. 181 students ate lunch. 270 students ate dinner. 60 students ate breakfast and lunch. 111 students ate breakfast and dinner. 95 students ate lunch and dinner. To help plan the number of meals to be prepared in a college cafeteria, a survey was conducted, and the following data were obtained. 127 students ate breakfast. 181 students ate lunch. 270 students ate dinner. 60 students ate breakfast and lunch. 111 students ate breakfast and dinner. 95 students ate lunch and dinner. 54 students ate all three meals. How many students ate (a) At least one meal in the cafeteria? (b) Exactly one meal in the cafeteria? (c) Only dinner in the cafeteria? (d) Exactly two meals in the cafeteria?

A survey of 540 adults aged 18

171 watch tv 150 hung out with friends 200 ate pizza but did not hang out with friends 28 watched Tv and ate pizza but did not hang out with friends 44 watched Tv and hung out with friends, but did not eat pizza 31 hung out with friends and ate pizza but did not watch TV 33 watched TV hung out with friends and ate pizza how many 18-24 yearolds did not do any of these three activities last friday night? This was a fun little puzzle. If we number the statements (and reorder their contents so they all have the same information in the same order), we get the following: 1) 171 watched TV 2) 150 hung out with friends 3) 200 did not hang out with friends, ate pizza 4) 28 watched TV, did not hang out with friends, ate pizza 5) 44 watched TV, hung out with friends, did not eat pizza 6) 31 did not watch TV, hung out with friends, ate pizza 7) 33 watched TV, hung out with friends, ate pizza Combing 3) and 4) you get 8) as follows: 8) 172 did not watch TV, did not hang out with friends, ate pizza Combing 5) and 7) you get 9) as follows: 9) 77 watched TV hung out with friends Combing 2) and 9) you get 10) as follows: 10) 73 did not watch TV, hung out with friends By negating 1) you get 11 as follows: 11) 369 did not watch TV Combing 10) and 11) you get 12) as follows: 12) 296 did not watch TV did not hang out with friends Combining 8) and 12) you get the final conclusion 13) as follows: 13) 124 did not watch TV, did not hang out with friends, did not eat pizza ¢ € £ ¥ ‰ µ · • § ¶ ß ‹ ›...