Aniline does not react with methyl chloride

Hint: To determine the reactivity of aniline, we need the proper structure of aniline and the concept of nucleophile and electrophile in an organic reaction. We also need to know the reason for the basic nature of aniline. Complete answer: The structure of aniline contains an ammonia group \[ + \] attached to the benzene ring. Due to the presence of a lone pair of nitrogen atoms of the ammonia group of the aniline, due to which it acts as a nucleophile. It’s ability to donate the lone pair of electrons to an electrophilic center makes it basic in nature. Now, as the lone pair on the nitrogen atom is in conjugation or is under resonance with the benzene ring, it is not easily available for donation to an electrophile due to which its basic nature decreases. Hence, making aniline a weak base. Now, we know that aniline is a weak base. So, when aniline reacts with \[\]having a positive charge will act as an electrophile and hance, can receive the donated lone pair of electrons from the nitrogen atom of aniline. Therefore, we can say that aniline will react with dilute HCl to produce an anilinium ion and a chloride ion. The structure drawn above is of the ANILINIUM ION Now, when we add dilute \[NaOH\] to aniline, aniline won’t react dilute \[NaOH\] because \[NaOH\] is an ionic compound which produces an hydroxide ion \[(O\] ion produced in the reaction is an ion and won’t react with aniline as aniline is a weak base. So, aniline will not react with A. dilute \[NaOH\]. Note: Whi...

Aromatic Reactivity Aromatic Substitution Reactions Part II 4. Electrophilic Substitution of Disubstituted Benzene Rings When a benzene ring has two substituent groups, each exerts an influence on subsequent substitution reactions. The activation or deactivation of the ring can be predicted more or less by the sum of the Orientational Interaction of Substituents Antagonistic or Non-Cooperative Reinforcing or Cooperative D = Electron Donating Group (ortho/para-directing) W = Electron Withdrawing Group (meta-directing) The products from substitution reactions of compounds having a reinforcing orientation of substituents are easier to predict than those having antagonistic substituents. For example, the six equations shown below are all examples of reinforcing or cooperative directing effects operating in the expected manner. Symmetry, as in the first two cases, makes it easy to predict the site at which substitution is likely to occur. Note that if two different sites are favored, substitution will usually occur at the one that is least hindered by ortho groups. The first three examples have two similar directing groups in a meta-relationship to each other. In examples 4 through 6, oppositely directing groups have an ortho or para-relationship. The major products of electrophilic substitution, as shown, are the sum of the individual group effects. The strongly activating hydroxyl (–OH) and amino (–NH 2) substituents favor dihalogenation in examples 5 and six. Substitution re...

Description : Which of the following statements is correct about aniline? (a) is weak acid. (b) diazotizes to benzenediazonium chloride when treated with ice-cold nitrous acid. (c) can be nitrated with ... p-nitroaniline. (d) gives an intense green color with a suspension of bleaching powder in water Last Answer : diazotizes to benzenediazonium chloride when treated with ice-cold nitrous acid. Description : Which of the following statements is false about aniline? (a) It is a primary aromatic amine. (b) It is a weak base which forms salts with acids. (c) It liberates nitrogen on treatment with ice-cold nitrous acid. (d) It can be prepared by the reduction of nitrobenzene with tin and HCl Last Answer : It liberates nitrogen on treatment with ice-cold nitrous acid Description : Aspirin is produced by heating salicylic acid with (a) acetic anhydride in the presence of phosphoric acid (b) benzoic anhydride in the presence of phosphoric acid (c) methyl alcohol in the presence of sulfuric acid (d) phenol in the presence of sulfuric acid Last Answer : acetic anhydride in the presence of phosphoric acid Description : Give reasons of the following observations: a. Aniline is acetylated before nitration reaction. b. pKb of aniline is lower than the m-nitroaniline. c. Primary amine on treatment with benzenesulphonyl ... . d. Aniline does not react with methyl chloride in the presence of anhydrous AlCl3 catalyst. Description : Which of the following statements is false about secondary...

You can Download Chapter 13 Amines Questions and Answers, Notes, Karnataka 2nd PUC Chemistry Question Bank Chapter 13 Amines 2nd PUC Chemistry Amines NCERT Textbook Questions Question 1. Write IUPAC names of the following compounds and classify them into primary, secondary .and tertiary amines. (i) (CH 3) 2CHNH 2 (ii) CH 3(CH 2) 2NH (iii) CH 3NHCH(CH 3) 2 (iv) (CH 3) 3CNH 2 (V) C 6H 5NHCH 3 (vi) (CH 3CH 2) 2NCH 3 (vii) m-BrC 6H 4NH 2 Answer: Question 2. Give one chemical test to distinguish between the following pairs of compounds, • Methylamine and dimethylamine • Secondary and tertiary amines • Ethylamine and aniline • Aniline and benzylamine • Aniline and N-methyl aniline. Answer: 1. Methylamine and dimethylamine • CH 3NH 2 (Methylamine; 1° amine) – Carbyl amine test positive • (CH 3) 2 NH (Dimethylamine; 2° amine) – Doesn’t give this test Carbylamine test:- 2. 2° and 3° amines:- • 2° amine – Libermann Nitrosomine test positive. • 3° amine – Libermann Nitrosomine test negative. Libermann Nitrosomine test : 3. Ethylamine and aniline: • Aromatic amines give brilliantly coloured orange dye on diazotisation and coupling with phenol. • Ethylamine does not give a dye on diazotization and coupling with phenol. Diazotization: 4. Aniline and benzylamine:- (1) Aromatic (1 °) amine gives coloured dye on diazotisation and coupling with phenol. (2) Other non-aromatic 1° amines and which are not an aromatic 1° amine, will not give a dye. Diazotization:- (a) (b) 5. Aniline and N-methy...