Class 6 maths chapter 10 exercise 10.3 solutions

Get Free NCERT Solutions for Class 11 Maths Chapter 10 Straight Lines Ex 10.3. Class 11 Maths NCERT Solutions are extremely helpful while doing homework. Exercise 10.3 Class 11 Maths NCERT Solutions were prepared by Experienced LearnCBSE.in Teachers. Detailed answers of all the questions in Chapter 10 Maths Straight Lines Class 11 Exercise 10.3 Provided in NCERT Textbook. • • • • • • • • • • • • You can also save the NCERT Solutions Class 11 Maths Straight Lines images and take the print out to keep it handy for your exam preparation. Topics and Sub Topics in Class 11 Maths Chapter 10 Straight Lines: Section Name Topic Name 10 Straight Lines 10.1 Introduction 10.2 Slope of Line 10.3 Various Forms of the Equation of Line 10.4 General Equation of Line 10.5 Distance of a Point From a Line NCERT Solutions for Class 11 Maths Chapter 10 Straight Lines Ex 10.3 NCERT Solutions for Class 11 Maths Chapter 10 Straight Lines Ex 10.3 are part of Ex 10.3 Class 11 Maths Question-1 Ans. Ex 10.3 Class 11 Maths Question-2 Ans. Ex 10.3 Class 11 Maths Question-3 Ans. Ex 10.3 Class 11 Maths Question-4 Ans. Ex 10.3 Class 11 Maths Question-5 Ans. Ex 10.3 Class 11 Maths Question-6 Ans. Ex 10.3 Class 11 Maths Question-7 Ans. Ex 10.3 Class 11 Maths Question-8 Ans. Ex 10.3 Class 11 Maths Question-9 Ans. Ex 10.3 Class 11 Maths Question-10 Ans. Ex 10.3 Class 11 Maths Question-11 Ans. Ex 10.3 Class 11 Maths Question-12 Ans. Ex 10.3 Class 11 Maths Question-13 Ans. Ex 10.3 Class 11 Maths Question-14 Ans....

NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.3 are part of • • Board CBSE Textbook NCERT Class Class 6 Subject Maths Chapter Chapter 10 Chapter Name Mensuration Exercise Ex 10.3 Number of Questions Solved 12 Category NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.3 Ex 10.3 Class 6 Maths Question 1. Find the areas of the rectangles whose sides are: (a) 3 cm and 4 cm (b) 12 m and 21 m (c) 2 km and 3 km (d) 2 m and 70 cm Solution: (a) Length of the rectangle = 4 cm Breadth of the rectangle = 3 cm Area = Length x Breadth = 4 cm x 3 cm = 12 sq. cm (b) Length of the rectangle = 21 m Breadth of the rectangle = 12 m Area = Length x Breadth = 21 m xl2 m = 252 sq. m. (c) Length of the rectangle = 3 km Breadth of the rectangle =2 km Area = Length x Breadth = 3 km x 2km = 6 sq. km (d) Length of the rectangle =2m = 2 x l00= 200 cm Breadth of the rectangle = 70 cm Area = Length x Breadth = 200 cm x 70 cm = 14000 sq. cm Ex 10.3 Class 6 Maths Question 2. Find the areas of the squares whose sides are: (a) 10 cm (b) 14 cm (c) 5 m Solution: (a) Side of the square = 10 cm Area = (side) 2 = (10) 2 sq. cm = 100 sq. cm (b) Side of the square = 14 cm Area = (side) 2 = (14) 2 sq. cm = 196 sq. cm (c) Side of the square = 5 m Area = (side) 2 = (5) 2 sq. m = 25sq. m Ex 10.3 Class 6 Maths Question 3. The length and breadth of three rectangles are as given below: (a) 9 m and 6 m (b) 17 m and 3 m (c) 4 m and 14 m Which one has the largest area and which one has the smal...

NCERT Solutions For Class 6 Maths Chapter 10 Mensuration Ex 10.1 • • NCERT Solutions For Class 6 Maths Chapter 10 Mensuration Ex 10.1 Exercise 10.1 Ex 10.1 Class 6 Maths Question 1. Find the perimeter of each of the following figures: Solution: (a) Required perimeter = 4 cm + 2 cm + 1 cm + 5 cm = 12 cm (b) Required perimeter = 40 cm + 35 cm + 23 cm + 35 cm = 133 cm or 1.33 m (c) Required perimeter = 15 cm + 15 cm + 15 cm + 15 cm = 15 cm x 4 = 60 cm (d) Required perimeter = 4 cm + 4 cm + 4 cm + 4 cm + 4 cm – 4 cm x 5 = 20 cm (e) Required perimeter = 4 cm + 0.5 cm + 2.5 cm + 2.5 cm + 0.5 cm + 4 cm + 1 cm = 15 cm (f) Required perimeter = 4 cm + 1 cm + 3 cm + 2 cm + 3 cm + 4 cm + 1 cm + 3 cm + 2 cm + 3 cm + 4 cm + 1 cm + 3 cm + 2 cm + 3 cm + 4 cm + 1 cm + 3 cm + 2 cm + 3 cm = 52 cm Ex 10.1 Class 6 Maths Question 2. The lid of a rectangular box of sides 40 cm by 10 cm is sealed all round with tape. What is the length of the tape required? Solution: Total length of the tape required = perimeter of the rectangular lid = 2 [length + breadth] = 2 x [40 + 10] = 2 x 50 = 100 cm Ex 10.1 Class 6 Maths Question 3. A table-top measures 2 m 25 cm by 1 m 50 cm. What is the perimeter of the table-top? Solution: Length of table-top = 2 m 25 cm Breadth of table-top = 1 m 50 cm ∴ Perimeter of the table top = 2 [length + breadth] = 2 [2 m 25 cm + 1 m 50 cm] = 2 x 3 m 75 cm = 7 m 50 cm = 7.5 m Ex 10.1 Class 6 Maths Question 4. What is the length of the wooden strip required to frame a photograph...

Gujarat Board Gujarat Board Textbook Solutions Class 6 Maths Chapter 10 Mensuration Ex 10.3 Question 1. Find the areas of the rectangles whose sides are: (a) 3 cm and 4 cm (b) 12 m and 21 m (c) 2 km and 3 km (d) 2 m and 70 cm Solution: (a) ∵ Length of the rectangle = 4 cm Breadth of the rectangle = 3 cm ∴ Area = length × breadth = 4 cm × 3 cm = 12 sq. cm (b) ∵ Length of the rectangle = 21 m Breadth of the rectangle = 12 m ∴ Area = length × breadth = 21 m × 12 m = 252 sq. m (c) ∵ Length of the rectangle = 3 km Breadth of the rectangle = 2 km Area = length × breadth = 3 km × 2 km = 6 sq. km (d) ∵ Length of the rectangle = 2 m = 200 cm Breadth of the rectangle = 70 cm Area = length × breadth = 200 cm × 70 cm = 14000 sq. cm Question 2. Find the areas of the squares whose sides are: (a) 10 cm (b) 14 cm (c) 5 m Solution: (a) ∵ Side of the square = 10 cm ∴ Area of the square = side × side = 10 cm × 10 cm = 100 sq. cm (b) ∵ Side of the square = 14 cm ∴ Area of the square = side × side = 14 cm × 14 cm = 196 sq. cm (c) ∵ Side of the square = 5 m Area of the square = side × side = 5 m × 5 m = 25 sq. m Question 3. The length and breadth of the three rectangles are as given below: (a) 9 m and 6 m (b) 17 m and 3 m (c) 4 m and 14 m Which one has the largest area and which one has the smallest? Solution: (a) Area of rectangle = length × breadth = 9 m × 6 m = 54 sq. m (b) Area of rectangle = length × breadth = 17 m × 3 m = 51 sq. m (c) Area of rectangle = length × breadth = 4 m × 14 m = 56...

Free PDF download of NCERT Solutions for Class 6 Maths Chapter 10 Exercise 10.3 (Ex 10.3) and all chapter exercises at one place prepared by an expert teacher as per NCERT (CBSE) books guidelines. Class 6 Maths Chapter 10 Mensuration Exercise 10.3 Questions with Solutions to help you to revise complete Syllabus and Score More marks. Register and get all exercise solutions in your emails. Every NCERT Solution is provided to make the study simple and interesting on Vedantu. Subjects like Science, Maths, English,Hindi will become easy to study if you have access to NCERT Solution for Class 6 Science , Maths solutions and solutions of other subjects. Exercise- 10.3 Refer to page 1 - 10 for exercise 10.3 in the PDF” 1. Find the areas of the rectangles whose sides are: a) 3 cm and 4 cm Ans: We know that the area of a rectangle is given by \[\] 11. By splitting the following figures into rectangles, find their areas (The measures are given in centimetres). (a) The area of orange region is \[ \Rightarrow 3 \times 3 = 9\,c\] (b) The area of green region is \[ \Rightarrow 3 \times 1 = 3\,c\] 12. Split the following shapes into rectangles and find their areas. (The measures are given in centimetres) a) Area of the orange rectangle is \[ \Rightarrow 2 \times 1 = 2\,c = 42\] Hence 42 tiles are needed. NCERT Solutions For Class 6 Maths Chapter 10 Mensuration Exercise 10.3 Opting for the NCERT solutions for Ex 10.3 Class 6 Maths is considered as the best option for the CBSE students when...

NCERT Solutions for Class 6 Maths Chapter 10 – Mensuration comprises of the 3 Exercises • Exercise 10.1 • Exercise 10.2 • Exercise 10.3 This Chapter contains the Exercises relating to the following topics, which are discussed in Chapter 10 – Mensuration Class 6 NCERT book : – • 10.1 Introduction • 10.2 Perimeter • 10.2.1 Perimeter of a rectangle • 10.2.2 Perimeter of regular shapes • 10.3 Area • 10.3.1 Area of a rectangle • 10.3.2 Area of a square NCERT Solutions for Class 6 Maths Chapter 10 Exercise 10.1 Ques. 1. Find the perimeter of each of the following figures: Sol.1. Perimeter of a figure = sum of measurements of all sides a) Perimeter = (4+2+1+5) cm = 12 cm (b) Perimeter = (35+23+35+40) cm = 133 cm (c) Perimeter = (15+15+15+15) cm = 60 cm (d) Perimeter = (4+4+4+4+4) cm = 20 cm (e) Perimeter = (1+4+0.5+2.5+2.5+0.5+4) cm = 15 cm (f) Perimeter = (1+3+2+3+4) × 4 cm = 52 cm Ques. 2. The lid of a rectangular box of sides 40 cm by 10 cm is sealed all round with tape. What is the length of the tape required? Sol.2. Length of the tape = perimeter of the rectangular lid = 2 × (l + b) = 2 × (40 + 10) cm = 100 cm Ques. 3. A table-top measures 2 m 25 cm by 1 m 50 cm. What is the perimeter of the table-top? Sol.3. Perimeter of the table top = 2 × (l + b) l = 2 m 25 cm = 2.25 m b = 1 m 50 cm = 1.50 m Perimeter = 2 × (2.25 + 1.50) = 7.50 m = 7 m 50 cm Ques. 4. What is the length of the wooden strip required to frame a photograph of length and breadth 32 cm and 21 cm respectively? S...