Class 6 maths chapter 12 exercise 12.2 solutions

NCERT Solutions Class 6 Maths Chapter 12 Exercise 12.2 Ratio and Proportion NCERT Solutions for Class 6 Maths Chapter 12 exercise 12.2 ratio and proportion is a short but significant exercise. This exercise contains questions that help the students in learning how to establish relations between The ☛ Download NCERT Solutions Class 6 Maths Chapter 12 Exercise 12.2 Exercise 12.2 Class 6 Chapter 12 Download PDF

Get Free NCERT Solutions for Class 10 Maths Chapter 12 Ex 12.2 PDF. Areas Related to Circles Class 10 Maths NCERT Solutions are extremely helpful while doing your homework. Exercise 12.2 Class 10 Maths NCERT Solutions were prepared by Experienced LearnCBSE.in Teachers. Detailed answers of all the questions in Chapter 12 Maths Class 10 Areas Related to Circles Exercise 12.2 provided in NCERT TextBook. Topics and Sub Topics in Class 10 Maths Chapter 12 Areas Related to Circles: Section Name Topic Name 12 Areas Related to Circles 12.1 Introduction 12.2 Perimeter And Area Of A Circle – A Review 12.3 Areas Of Sector And Segment Of A Circle 12.4 Areas Of Combinations Of Plane Figures 12.5 Summary • • • • • • • You can also download the free PDF of Ex 12.2 Class 10 Areas Related to Circles NCERT Solutions or save the solution images and take the print out to keep it handy for your exam preparation. Board CBSE Textbook NCERT Class Class 10 Subject Maths Chapter Chapter 12 Chapter Name Areas Related to Circles Exercise Ex 12.2 Number of Questions Solved 14 Category NCERT Solutions for Class 10 Maths Chapter 12 Areas Related to Circles Ex 12.2 NCERT Solutions for Class 10 Maths Chapter 12 Areas Related to Circles Ex 12.2 are part of Ex 12.2 Class 10 Maths Question 1. Find the area of a sector of a circle with radius 6 cm if angle of the sector is 60°. Solution: Ex 12.2 Class 10 Maths Question 2. Find the area of a quadrant of a circle whose circumference is 22 cm. Solution: Ex 12.2 ...

• • Board CBSE Textbook NCERT Class Class 6 Subject Maths Chapter Chapter 12 Chapter Name Ratio and Proportion Exercise Ex 12.2 Number of Questions Solved 4 Category NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.2 Question 1. Determine if the following are in proportion: (a) 15, 45, 40, 120 (b) 33, 121, 9, 96 (c) 24, 28, 36, 48 (d) 32, 48, 70, 210 (e) 4, 6, 8, 12 (f) 33, 44, 75, 100 Solution : Question 2. Write True (T) or False (F) against each of the following statements : (a) 16: 24: : 20: 30 (b) 21: 6: 35: 10 (c) 12: 18: 28: 12 (d) 8: 9: : 24: 27 (e) 5.2: 3.9: : 3: 4 (f) 0.9: 0.36: : 10: 4 Solution : Question 3. Are the following statements true₹ I (a) 40 Persons : 200 Persons =₹ 15: ₹75 ; (b) 7.5 litre : 15 litre = 5 kg : 10 kg 1 (c) 99 kg : 45 kg = f 44 : ₹20 (d) 32 m : 64 m = 6 sec: 12 sec (e) 45 km: 60 km = 12 hours : 15 hours. Solution : Since the two ratios are equal, therefore, the given statement is true. Since the two ratios are equal, therefore, the given statement is true. Since, the two ratios are equal, therefore, the given statement is true. Since the two ratios are equal, therefore the given statement is true. Since the two ratios are not equal, therefore the given statement is false. Question 4. Determine if the following ratios form a proportion. Also, write the middle terms and extreme terms where the ratios form a proportion. (a) 25 cm: 1 m and 7 40 : 7160 (b) 39 litre : 65 litre and 6 bottle : 10 bottle (c) 2 kg : 80 kg and...

NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Exercise 12.2 By referring to the NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Exercise 12.2 while solving problems from the NCERT textbook, students gain an overall idea about the concepts covered under this exercise. When two ratios are equal, we consider them to be proportional to each other. These Previous Next  Access NCERT Solutions for Class 6 Chapter 12: Ratio and Proportion Exercise 12.2 1. Determine if the following are in proportion. (a) 15, 45, 40, 120 (b) 33, 121, 9, 96 (c) 24, 28, 36, 48 (d) 32, 48, 70, 210 (e) 4, 6, 8, 12 (f) 33, 44, 75, 100 Solutions: (a) 15, 45, 40, 120 15 / 45 = 1 / 3 40 / 120 = 1 / 3 Hence, 15: 45 = 40:120 ∴ These are in proportion. (b) 33, 121, 9, 96 33 / 121 = 3 / 11 9 / 96 = 3 / 32 Hence, 33:121 ≠9: 96 ∴ These are not in proportion. (c) 24, 28, 36, 48 24 / 28 = 6 / 7 36 / 48 = 3 / 4 Hence, 24: 28 ≠36:48 ∴ These are not in proportion. (d) 32, 48, 70, 210 32 / 48 = 2 / 3 70 / 210 = 1 / 3 Hence, 32: 48 ≠70: 210 ∴ These are not in proportion. (e) 4, 6, 8, 12 4 / 6 = 2 / 3 8 / 12 = 2 / 3 Hence, 4: 6 = 8: 12 ∴ These are in proportion. (f) 33, 44, 75, 100 33/ 44 = 3/ 4 75 / 100 = 3 / 4 Hence, 33:44 = 75: 100 ∴ These are in proportion. 2. Write True (T) or False ( F ) against each of the following statements. (a) 16 : 24 :: 20 : 30 (b) 21: 6 :: 35 : 10 (c) 12 : 18 :: 28 : 12 (d) 8 : 9 :: 24 : 27 (e) 5.2 : 3.9 :: 3 : 4 (f) 0.9 : 0.36 :: 10...

Like Our Facebook Page For Educational Updates These 11th Class math exercise 12.2 notes prepared according to the syllabus of all Punjab Boards. Other boards other than Punjab do not follow 1st year math notes. These Punjab boards are Gujranwala Board, Lahore Board, Faisalabad Board, Multan Board, Rawalpindi Board, Bahawalpur Board Sargodha Board, DG Khan Board, Sahiwal Board. Final words, we made our finest efforts to make these notes beneficial for you. But if you find any mistake, so any suggestion for its further precision is however invited. And if you find that our efforts help you, share it with your mates because “Sharing is Caring”.

An equality of two ratios is called proportion. In general, four numbers a, b, c, d are said to be in proportion, if the ratio of the first two is equal to the ratio of the last two, i.e., a : b = c : d. This is equivalent to a/b = c/d, i.e., ad = bc. The equality “3 :5 = 6 :10” forms a proportion. We sometimes write “3 : 5 = 6 : 10” as “3 : 5 :: 6 : 10”, which is read as “3 is to 5 as 6 is to 10” or “3 to 5 as 6 to 10”. (i) Product of extremes = 3 × 21 = 63 Product of means = 7 × 12 = 84 Since, the product of extremes ≠product of means, Therefore 3 : 7 and 12 : 21 are not in proportion. (ii) Product of extremes = 14 × 24 = 336 Product of means = 8 × 42 = 336 Since, the product of extremes = product of means, Therefore, the two ratios are in proportion. (iii) Product of extremes = 31 × 2 = 62 Product of means = 5 × 15 = 75 Since, the two product are not equal, Therefore, the two ratios are not in proportion. Exercise 12.2 of 6th class Maths contains 4 questions and 3 examples (examples 8, 9, and 10) only. This exercise is short and not lengthy. Students require only one day to complete exercise 12.2 of 6th class Maths. This time can vary because it depends on the student’s working speed, ability, efficiency, etc.

Table of Contents • • • • • • • • • • • • • • • NCERT Solutions for Class 6 Maths Exercise 12.2 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 6 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free. NCERT solutions for Maths Ratio and proportion NCERT Solutions for Class 6 Maths Ratio and proportion Class –VI Mathematics (Ex. 12.2) Question 1. Determine the following are in proportion: (a) 15, 45, 40, 120 (b) 33, 121, 9, 96 (c) 24, 28, 36, 48 (d) 32, 48, 70, 210 (e) 4, 6, 8, 12 (f) 33, 44, 75, 100 Answer: (a) 15 : 45 = = 1 : 3 40 : 120 = = 1 : 3 Since 15 : 45 = 40 : 120 Therefore 15, 45, 40, 120 are in proportion. (b) 33 : 121 = = 3 : 11 9 : 96 = = 3 : 32 Since 33 : 121 12 hours : 15 hours Hence, the statement is true. NCERT Solutions for Class 6 Maths Exercise 12.2 Question 4.Determine if the following ratios form a proportion. Also, write the middle terms and extreme terms where the ratios form a proportion: (a) 25 cm : 1 m and Rs. 40 : Rs. 160 (b) 39 liters : 65 liters and 6 bottles : 10 bottles (c) 2 kg : 80 kg and 25 g : 625 g (d) 200 ml : 2.5 ml and Rs. 4 : Rs. 50 Answer: (a) 25 cm : 1 m = 25 cm : (1 x 100) cm = 25 cm : 100 cm = = 1 : 4 Rs. 40 : Rs. 160 = = 1 : 4 Since the ratios ar...