Class 8 maths ex 6.3

NCERT Solutions for Class 8 Maths Chapter 6 - Squares and Square Roots Exercise 6.4 NCERT exercise solutions help improve the hold of the students in the problems related to square and square roots. Subject experts have solved all the questions of this exercise. NCERT Solutions for Class 8 Maths helps students in enhancing their skills. Download free Maths Download PDF carouselExampleControls111 Previous Next  Access other exercise solutions of Class 8 Maths Chapter 6 – Squares and Square Roots Access answers of Maths NCERT Class 8 Chapter 6 – Squares and Square Roots Exercise 6.4 Page Number 107 1. Find the square root of each of the following numbers by the Division method. i. 2304 ii. 4489 iii. 3481 iv. 529 v. 3249 vi. 1369 vii. 5776 viii. 7921 ix. 576 x. 1024 xi. 3136 xii. 900 Solution: i. ∴ √2304 = 48 ii. ∴ √4489 = 67 iii. ∴ √3481 = 59 iv. ∴ √529 = 23 v. ∴ √3249 = 57 vi. ∴ √1369 = 37 vii. ∴ √5776 = 76 viii. ∴ √7921 = 89 ix. ∴ √576 = 24 x. ∴ √1024 = 32 xi. ∴ √3136 = 56 xii. ∴ √900 = 30 2. Find the number of digits in the square root of each of the following numbers (without any calculation). i. 144 ii. 4489 iii. 27225 iv. 390625 Solution: i. ∴ √144 = 12 Hence, the square root of the number 144 has 2 digits. ii. ∴ √4489 = 67 Hence, the square root of the number 4489 has 2 digits. iii. √27225 = 165 Hence, the square root of the number 27225 has 3 digits. iv. ∴ √390625 = 625 Hence, the square root of the n...

You can Download KSEEB Solutions for Class 8 Maths Chapter 6 Square and Square Roots Ex 6.3 Question 1. What could be the possible ‘one’s digits of the square root of each of the following numbers? (i) 9801 (ii) 99856 (iii) 998001 (iv) 657666025 Solution: (i) Possible one’s digit in the square root of 9801 is 1 or 9. (ii) Possible one’s digit in the square root of 99856 is 6. (iii) Possible one’s digit in the square root of 998001 is 1 or 9. (iv) Possible one’s digit in the square root of 657666025 is 5. Question 2. Without doing any calculation, find the numbers which are surely not perfect squares. (i) 153 (ii) 257 (iii) 408 (iv) 441 Solution: Since the number which ends with digit 2, 3, 7, 8 are surely not a perfect square. ∴ (i) 153 (ii) 257 (iii) 408 are not perfect square. Question 3. Find the square roots of 100 and 169 by the method of repeated subtraction. Solution: (I) (i) 100 – 1 = 99 (ii) 99 – 3 = 96 (iii) 96 – 5 = 91 (iv) 91 – 7 = 84 (v) 84 – 9 = 75 (vi) 75 – 11 = 64 (vii) 64 – 13 = 51 (viii) 51 – 15 = 36 (ix) 36 – 17 = 19 (x) 19 – 19 = 0 Repeated subtract of successive odd number starting from 1 gives 0 at 10th step. Hence √100 = 10 (II) (i) 169 – 1 = 168 (ii) 168 – 3 = 165 (iii) 165 – 5 = 160 (iv) 160 – 7 = 153 (v) 153 – 9 = 144 (vi) 144 – 11 = 133 (vii) 133 – 13 = 120 (viii) 120 – 15 = 105 (ix) 105 – 17 = 88 (x) 88 – 19 = 69 (xi) 69 – 21 = 48 (xii) 48 – 23 = 25 (xiii) 25 – 25 = 0 Repeated subtraction of successive odd number starting from 1 gives 0 at the 1...

NCERT Solutions Class 8 Maths Chapter 6 Exercise 6.3 Squares and Square Roots The NCERT solutions for Class 8 maths Chapter 6 exercise 6.3 Squares and Square Roots explains that finding the square root is the process of finding a number with a known square. Also, concepts like the square root are also the inverse operation of The students will observe that in the prime factorization for the square of the number, every prime factor appears twice the times that it occurs in the prime factorization of the original number. The students can find the questions in the exercise of the Class 8 maths NCERT solutions Chapter 6 exercise 6.3 Squares and Square Roots below : ☛ Download NCERT Solutions Class 8 Maths Chapter 6 Exercise 6.3 Exercise 6.3 Class 8 Chapter 6 Download PDF More Exercises in Class 8 Maths Chapter 6 • • • NCERT Solutions Class 8 Maths Chapter 6 Exercise 6.3 Tips The When solving problems in Download Cuemath NCERT Solutions PDF for free and start learning! NCERT Video Solutions for Class 8 Maths Chapter 6 Exercise 6.3 Video Solutions for Class 8 Maths Chapter 6 Exercise 6.3

• • • Board CBSE Textbook NCERT Class Class 8 Subject Maths Chapter Chapter 6 Chapter Name Squares and Square Roots Exercise Ex 6.4 Number of Questions Solved 9 Category NCERT Solutions for Class 8 Maths Chapter 6 Squares and Square Roots Ex 6.4 Question 1. Find the square root of each of the following numbers by Division method: Solution. (i) 2304 (ii) 4489 (iii) 3481 (iv) 529 (v) 3249 (vi) 1369 (vii) 5776 (viii) 7921 (ix) 576 (x) 1024 (xi) 3136 (xii) 900 Question 2. Find the number of digits in the square root of each of the following numbers (without any calculation): (i) 64 (ii) 144 (iii) 4489 (iv) 27225 (v) 390625. Solution. (i) 64 Number (n) of digits in 64 = 2 which is even. ∴ Number of digits in the square root of 64 \(\frac \) ∴ Length of the side of the square Question 7. In a right triangle ABC, ∠B = 90°. (a) If AB = 6 cm, BC = 8 cm, find AC (b) If AC 13 cm, BC = 5 cm, find AB. Solution. (a) In the right triangle ABC, ∠B = 90° Given Question 8. A gardener has 1000 plants. He wants to plant these in such a way that the number of rows and the number of columns remain same. Find the minimum number of plants he needs more for this. Solution. Let the number of rows be x. Then the number of columns is x. Question 9. There are 500 children in a school. For a P.T. drill they have to stand in such a manner that the number of rows is equal to number of columns. How many children would be left out in this arrangement? Solution. Let the number of rows be x. Then the number ...

NCERT Solutions Class 8 Mathematics Chapter – 6 (Squares and Square) The NCERT Solutions in English Language for Class 8 Mathematics Chapter – 6 Squares and Square Exercise 6.3 has been provided here to help the students in solving the questions from this exercise. Chapter 6: Squares and Square Roots • • • Exercise – 6.3 1. What could be the possible ‘one’s’ digits of the square root of each of the following numbers? (i) 9801 (ii) 99856 (iii) 998001 (iv) 657666025 Solution – (i) 9801 1 x 1 = 1 and 9 x 9 = 81 ∵ The possible one’s digit of the square root of the number 9801 could be 1 or 9. (ii) 99856 4 x 4 = 16 and 6 x 6 = 36 ∵ The possible one’s digit of the square root of the number 99856 could be 4 or 6. (iii) 998001 1 × 1 = 1 and 9 x 9 = 81 ∵ The possible one’s digit of the square root of the number 998001 could be 1 or 9. (iv) 657666025 5 x 5 = 25 ∵ The possible one’s digit of the square root of the number 657666025 could be 5. 2. Without doing any calculation, find the numbers which are surely not perfect squares. (i) 153 (ii) 257 (iii) 408 (iv) 441 Solution –We know that natural numbers ending with the digits 0, 2, 3, 7 and 8 are not perfect square. (i) 153 The number 153 is surely not a perfect square because it ends in 3 whereas the square numbers end with 0, 1, 4, 5, 6 or 9. (ii) 257 The number 257 is surely not a perfect square because it ends in 7 whereas the square numbers end with 0, 1, 4, 5, 6 or 9. (iii) 408 The number 408 is surely not a perfect square beca...

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