Class 8 maths ex 6.4

NCERT Solutions Class 8 Mathematics Chapter – 6 (Squares and Square) The NCERT Solutions in English Language for Class 8 Mathematics Chapter – 6 Squares and Square Exercise 6.4 has been provided here to help the students in solving the questions from this exercise. Chapter 6: Squares and Square Roots • • • Exercise – 6.4 1. Find the square root of each of the following numbers by Division method. (i) 2304 (ii) 4489 (iii) 3481 (iv) 529 (v) 3249 (vi) 1369 (vii) 5776 (viii) 7921 (ix) 576 (x) 1024 (xi) 3136 (xii) 900 Solution – (i) 2304 ∴ √2304 = 48 (ii) 4489 ∴ √4489 = 67 (iii) 3481 ∴ √3481 = 59 (iv) 529 ∴ √529 = 23 (v) 3249 ∴ √3249 = 57 (vi) 1369 ∴ √1369 = 37 (vii) 5776 ∴ √5776 = 76 (viii) 7921 ∴ √7921 = 89 (ix) 576 ∴ √576 = 24 (x) 1024 ∴ √1024 = 32 (xi) 3136 ∴ √3136 = 56 (xii) 900 ∴ √900 = 30 2. Find the number of digits in the square root of each of the following numbers (without any calculation). (i) 64 (ii) 144 (iii) 4489 (iv) 27225 (v) 390625 Solution – (i) 64 Number (n) of digits in 64 = 2 which is even. ∴ Number of digits in the square root of 64. = 1 (ii) 144 Number (n) of digits in 144 = 3 which is ∴ Number of digits in the square root of 144. = 2 (iii) 4489 Number (n) of digits in 4489 = 4 which is even. ∴ Number of digits in the square root of 4489. 2 (iv) 27225 Number (n) of digits in 27225 = 5 which is odd. ∴ Number of digits in the square root of 27225. = 3 (v) 390625 Number (n) of digits in 390625 = 6 which is even. ∴ Number of digits in the square root of 3906...

NCERT Solutions for Class 6 Maths Chapter 8 Decimals Exercise 8.4 The various applications of decimals in our daily lives are discussed in the NCERT Solutions for Class 6 Maths Chapter 8 Decimals Exercise 8.4. The uses of decimals in measuring money, length and weight are the concepts covered in Exercise 8.4. The problems given in this exercise are solved in In order to gain in-depth knowledge about the concepts discussed in this exercise, students can refer to the Previous Next  Access NCERT Solutions for Class 6 Chapter 8: Decimals Exercise 8.4 1. Express as rupees using decimals: (a) 5 paise (b) 75 paise (c) 20 paise (d) 50 rupees 90 paise (e) 725 paise Solutions: We know that there are 100 paise in 1 rupee (a) 5 paise = 5 / 100 rupees = Rupees 0.05 (b) 75 paise = 75 / 100 rupees = Rupees 0.75 (c) 20 paise = 20 / 100 rupees = Rupees 0.20 (d) 50 rupees 90 paise = [(50 + 90 / 100)] rupees = Rupees 50.90 (e) 725 paise = 725 / 100 rupees = Rupees 7.25 2. Express as metres using decimals: (a) 15 cm (b) 6 cm (c) 2 m 45 cm (d) 9 m 7 cm (e) 419 cm Solutions: We know that there are 100 cm in 1 metre (a) 15 cm = 15 / 100 m = 0.15 m (b) 6 cm = 6 / 100 m = 0.06 m (c) 2 m 45 cm = [(2 + 45 / 100)] m = 2.45 m (d) 9 m 7 cm = [(9 + 7 / 100)] m = 9.07 m (e) 419 cm = 419 / 100 m = 4.19 m 3. Express as cm using decimals: (a) 5 mm (b) 60 mm (c) 164 mm (d) 9 cm 8 mm (e) 93 mm Solutions: We know that there are 10 mm in 1 cm (a) 5 mm = 5 / 10 cm = 0.5 cm (b) 60 mm = 60 / 10 cm = 6.0 cm (c) 16...

NCERT Solutions Class 8 Maths Chapter 6 Squares and Square Roots The NCERT solutions for Class 8 maths Chapter 6 Squares and Square Roots sheds light on square numbers and square roots, their properties, and some interesting patterns between them. We know that when a number is multiplied by itself, the product that we get is known as the square of that particular number. For example, 4 is square of 2, 9 is square of 3, and so on. Concepts like finding squares of big numbers by expansion techniques and other patterns observed in square numbers are also covered in the NCERT solutions Class 8 maths Chapter 6. All square numbers will end with 0, 1, 4, 5, 6, or 9 at units' place. And square numbers will have an even number of zeroes in the end. These are a few of the important facts which will help the students throughout the Class 8 maths NCERT solutions Chapter 6 for the understanding of the examples and the exercise questions asked. The pdf file of this chapter can be found below and also you can find some of these in the exercises given below. • • • • NCERT Solutions for Class 8 Maths Chapter 6 PDF The concept of square root forms the basis for many higher math topics ahead. Sufficient practice on the same is required to build up a quick mental math skill which will help students in examinations too while saving enough time on calculations. A brief glance at the exercises in the ☛ Download Class 8 Maths NCERT Solutions Chapter 6 NCERT Class 8 Maths Chapter 6 Download PDF NC...

AP State Syllabus AP State Syllabus 8th Class Maths Solutions 6th Lesson Square Roots and Cube Roots Exercise 6.4 Question 1. Find the cubes of the following numbers (1) 8 (ii) 16 (iii) 21 (iv) 30 Solution: Number Cube Of a Number i) 8 8 3 = 8 × 8 × 8 = 512 ii) 16 16 3 = 16 × 16 × 16 = 4096 iii) 21 21 3 = 21 × 21 × 21 = 9261 iv) 30 30 3 = 30 × 30 × 30 = 27000 Question 2. Test whether the given numbers are perfect cubes or not. (i) 243 (ii) 516 (iii) 729 (iv) 8000 (v)2700 Solution: Number Cube Of a Number Yes / No i) 243 3 × 3 × 3 × 3 × 3 = 3 5 No ii) 516 2 × 2 × 3 × 43 No iii) 729 9 × 9 × 9 = 9 3 Yes iv) 8000 20 × 20 × 20 = (20) 3 Yes v) 2700 (30) × (30) × 3 No Question 3. Find the smallest number by which 8788 must be multiplied to obtain a perfect cube? Solution: The prime factorisation of 8788 = (2 × 2) × (13 × 13 × 13) ∴ From the above product 2 ¡s left in the triplet. ∴ 2 should be multiplied with 8788 we will get a perfect cube number. Question 4. What smallest number should 7803 be multiplied with so that the product becomes a perfect cube? Solution: The prime factorisation of 7803 = (3 × 3 × 3) × (17 × 17) ∴ From the above product 17 is left in the triplet. ∴ 17 should be multiplied to 7803 then we will get a perfect cube number. Question 5. Find the smallest number by which 8640 must be divided so that the quotient is a perfect cube’? Solution: The prime factorisation of 8640 = (2 × 2 × 2) × (2 × 2 × 2) × 5 × (3 × 3 × 3) = (2) 3 × (2) 3 × 5 × (3) 3 Question 6. Rav...

RS Aggarwal Class 8 Maths Chapter 6 Ex 6.4 Solutions: In this exercise, the student will study the problems based on the multiplication of a monomial & a binomial. The Mathematics experts have solved the questions in a step-by-step manner for easy understanding of the topics which assists students to increase their speed in solving the questions quickly in the exams. These solutions can be used as a handy last-minute revision tool. These solutions are comprehensive that assists the students to clear all their doubts related to the multiplication of a monomial & a binomial. These solutions are prepared as per the CBSE guidelines & have strong chances to attain excellent marks in the Class 8 th Maths exam. When students download these solutions in PDF format, they can also examine the pattern of questions which enable them to identify the topics which are most likely to come in the final exams. Important Definition for RS Aggarwal Class 8 Maths Chapter 6 Ex 6.4 Solutions RS Aggarwal Class 8 Maths Chapter 6 Ex 6.4 Solutions enable the students to improve their proficiency & Maths subject knowledge. The students will study the basic definitions & problems on multiplication of a monomial & a binomial. This exercise is created stepwise containing neat descriptions of each solution. The students can either practice online or download in the PDF format & practice different types of questions from this exercise. • Monomial Definition It is a type of polynomial which is an algebraic...