Ex 8.3 class 7

NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Exercise 8.3 Ex 8.3 Class 7 Maths Question 1. Tell what is the profit or loss in the following transactions. Also find profit per cent or loss per cent in each case. (a) Gardening shears bought for ₹ 250 and sold for ₹ 325. (b) A refrigerator bought for ₹ 12,000 and sold at ₹ 13,500. (c) A cupboard bought for ₹ 2,500 and sold at ₹ 3,000. (d) A skirt bought for ₹ 250 and sold at ₹ 150. Solution: (a) Here, CP = ₹ 250 SP = ₹ 325 Since SP > CP ∴ Profit = SP – CP = ₹ 325 – ₹ 250 = ₹ 75 Hence, the required profit = ₹ 75 and Profit per cent = 30% (b) Here, CP = ₹ 12,000 SP = ₹ 13,500 Since SP > CP ∴ Profit = SP – CP = ₹ 13,500 – ₹ 12,000 = ₹ 1,500 Hence, the required profit = ₹ 1500 × 100 profit % = \(12 \frac\)% (c) Here, CP = ₹ 2500 SP = ₹ 3000 Since SP > CP ∴ Profit = SP – CP = ₹ 3000 – ₹ 2500 = ₹ 500 Hence, the required profit = ₹ 500 and profit% = 20% (d) Here, CP = ₹ 250 SP = ₹ 150 Here CP > SP ∴ Loss = CP – SP = ₹ 250 – ₹ 150 = ₹ 100 Hence, the required loss = ₹ 100 and loss% = 40% Ex 8.3 Class 7 Maths Question 2. Convert each part of the ratio to Percentage: (a) 3:1 (b) 2:3:5 (c) 1 : 4 (d) 1:2:5 Solution: (a) 3 : 1 Sum of the ratio parts = 3 + 1 = 4 (b) 2 : 3 : 5 Sum of the ratio parts = 2 + 3 + 5 = 10 (c) 1 : 4 Sum of the ratio parts =1 + 4 = 5 (d) 1 : 2 : 5 Sum of the ratio parts = 1 + 2 + 5 = 8 Ex 8.3 Class 7 Maths Question 3. The pop...

NCERT Solutions for Class 7 Maths have been updated on aglasem. So now you can download Class 7 Maths Solutions PDF for all chapters here. These Class 7 Maths book namely Mathematics for all exercises. Therefore you can use Maths solutions guide to complete class 7 syllabus, and use it with Maths notes to get full marks in exams. NCERT Solutions for Class 7 Maths What are NCERT Solutions for Class 7 Maths? The NCERT Solutions Class 7 Maths is the collection of questions and their correct answers asked in exercises of all chapters of NCERT Book for Class 7 Maths. Therefore these NCERT Solutions for Class 7 Maths PDF • • • • • • • • • • • • • • • How to download NCERT Solutions for Class 7 Maths PDF? There is a simple way to download class 7 Maths solutions PDF here at aglasem. So if you have to solve exercises of class 7 Maths NCERT book multiple times, then you can use solutions of NCERT book Mathematics as per your convenience. The steps to download class 7 Maths questions answers guidebook is as follows. • Start by searching NCERT Solutions for Class 7 Maths PDF aglasem to come to this page. • Then click the link of the Class 7 Maths Solutions Chapter for which you want to know answers. • Now pdf file of NCERT questions answers for class 7 Maths for that chapter opens. • Thereafter click download pdf link to get Class 7 Maths NCERT Solutions PDF for all exercises of the topic. NCERT Solutions for Class 7 One has to study multiple subjects in addition to Maths in standard...

ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 8 Algebraic Expressions Ex 8.3 Question 1. If m = 2, find the value of: (i) 3m – 5 (ii) 9 – 5m (iii) 3m 2– 2m – 1 (iv) \(\frac \) m – 4 Solution: Question 2. If p = -2, find the value of: (1) 4p + 7 (ii) -3p 2 + 4p + 7 (iii) -2p 3– 3p 2 + 4p + 7 Solution: Question 3. If a = 2, b = -2, find the value of: (i) a 2 + b 2 (ii) a 2 + ab + b 2 (iii) a 2– b 2 Solution: Question 4. When a = 0, b = -1, find the value of the given expressions: (i) 2a 2 + b 2 + 1 (ii) a 2 + ab + 2 (iii) 2a 2b + 2ab 2 + ab Solution: Question 5. If p = -10, find the value of p 2– 2p – 100. Solution: Question 6. If z = 10, find the value of z 3– 3(z – 10). Solution: Question 7. Simplify the following expressions and find their values when x = 2: (i) x + 7 + 4(x – 5) (ii) 3(x + 2) + 5x – 7 (iii) 6x + 5(x – 2) (iv) 4(2x – 1) + 3x + 11 Solution: Question 8. Simplify the following expressions and find their values when a = -1, b = -2: (i) 2a – 2b – 4 – 5 + a (ii) 2(a 2 + ab) + 3 – ab Solution:

NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.1 • • • NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Exercise 8.1 Ex 8.1 Class 7 Maths Question 1. Find the ratio of: (a) ₹ 5 to 50 paise (b) 15 kg to 210 g (c) 9 m to 27 cm (d) 30 days to 36 hours Solution: (a) ₹ 5 to 50 paise Converting the given quantities into same units, we have ₹ 5 = 5 × 100 = 500 paise ∴ ₹ 5 : 50 paise = 500 paise : 50 paise [∵ ₹ 1 = 100 paise] = 10 : 1 So, required ratio is 10 : 1. (b) 15 kg to 210 g Converting the given quantities into same units, we have 15 kg = 15 × 1000 = 15000 g [∵ 1 kg = 1000 g] ∴ 15 kg : 210 g = 15000 g : 210 g = 1500 : 21 = 500 : 7 So, the required ratio is 500 : 7. (c) 9 m to 27 cm Converting the given quantities into same units, we have 9 m = 9 × 100 = 900 cm ∴ 9m: 27 cm = 900 cm : 27 cm [∵ 1 m = 100 cm] = 100 : 3 So, the required ratio is 100 : 3. (d) 30 days to 36 hours Converting the given quantities into same units, we have 30 days = 30 × 24 hours [ ∵ 1 day = 24 hours] = 720 hours ∴ 30 days : 36 hours = 720 hours : 36 hours = 20:1 So, the required ratio is 20 : 1. Ex 8.1 Class 7 Maths Question 2. In a computer lab, there are 3 computers for every 6 students. How many computers will be needed for 24 students? Solution: Using Unitary Method, we have 6 students require 3 computers ∴ 1 student will require = \(\frac\) Since 190 per km 2< 830 per km 2 (ii) Rajasthan is less populated state. Filed Under: Tagged With:

Question 3. -4a 3 + 4a 2 + a by 2a Solution: Question 4. -x 6 + 2x 4 + 4.x 3 + 2x 2 by √2x 2 Solution: Question 5. 5z 3– 6z 2 + 7z by 2z Solution: Question 6. √3 a 4 + 2 √3 a 3 + 3a 2– 6a by 3a Solution: Hope given If you have any doubts, please comment below. Filed Under: Tagged With: Primary Sidebar