He knows me well passive voice

What is the difference between the active voice and the passive voice in English? Compare these two sentences: Active = “The doctor gave me a prescription” Passive = “I was given a prescription” The first sentence is in the “active voice”. The subject is the doctor, and the verb is “gave”. In active sentences, the focus of the sentence is on the subject. The second sentence is in the “passive voice”. The object of the sentence (“I”) becomes the focus of the sentence. How to form a passive sentence 1. Firstly, you need to make the object (from the active sentence) into the new subject. For example, in “John helped me”, “me” is the object. The subject form of “me” is “I”. Here is a list of objects and subjects: me – I you – You him / her – He / She us – We them – They 2. Then you make the verb passive. Put the verb “to be” into the same tense as the verb in the active sentence. For example, in the sentence “John helped me”, “helped” is the past tense. Therefore, you need the past simple tense of the verb “to be”, which is “was” or “were”. “I was…” Here’s a list of tenses for the verb “to be”: Present simple – am / are / is Present continuous – is being / are being Present perfect – has been / have been Simple past – was / were Past continuous – was being / were being Modals will, can etc – will be, can be etc. 3. Then add the past participle of the verb. For example “gave”–“given”, “help”–“helped” “I was helped by John.” “I was given a prescription by the doctor.” 4. If nece...

Views: 5,228 r = 5 cm. 2. The radius of a soap-bubble is increasing at the rate of 0.2 cm / sec. Find the rate of incte of (i) its volume when the radius is 5 cm. (ii) its surface area when radius is 4 cm. 3. A particle is moving in a straight line so that distance covered after t seconds is given = t 2 + 3 t + 5. Find velocity at time t = 3. Find initial velocity and acceleration at time ' t 4. If s = t ​ + 3 is the displacement of the particle, what is its acceleration? 5. A point moves in a fixed straight line so that s = 1 + t ​ . Show that the accelerat negative and proportional to the cube of the velocity. 6. If S = u t + 2 1 ​ a t 2 where u and a are constants, prove that ( d t d S ​ ) 2 = u 2 + 2 a s. 7. The radius of a circle is increasing at the rate of 0.7 cm / sec. What is the rate of incr its circumference when r = 4.9 m. The side of a square is increasing at the rate of 0.2 cm / sec. Find the rate of increas perimeter of the square. An edge of a variable cube is increasing at the rate of 5 cm per second. How fa volume of the cube increasing when the edge is 10 cm long? • Solve differential equations, x lo g x d x d y ​ + y = x 2 ​ lo g x (July 2014) • Solve the differential equation, d x d y ​ + ( sec x ) y = tan x ( March 2015, March 2019) • Find the general solution of differential equation , x d x d y ​ + 2 y = x 2 (July 2016, July 2018, Model Paper -01, Model Paper 2022) • Find the general solution of differential equation cos 2 x d x d y ​ + y = tan x (M...