Hydrogen sulphide gas burns in air to give water and sulphur dioxide

Answer: Hydrogen sulphide gas burns in air to give water and sulphur dioxide can be expressed as : H 2 ​S(g) + O 2​ ​(g)→H 2​ ​O(l) + SO 2​ (g) To balance this equation, you’re required to write the unbalanced chemical equation. After that, note down the number of atoms of each element that is present on both the reactant side as well as product side. Further, add coefficients to balance the mass in the given chemical equation. Example : • 2H 2 O means 4 Hydrogen atoms along with 2 oxygen atoms. • The first step includes balancing the single element of the oxygen atom and then coming to Hydrogen. • Here, first sulphur and oxygen will be balanced. • Utilize trial and error methods. Add 2 Hydrogen on both the sides, then it will turn out to be 4 on reactants side as well as on product side. • So 2H makes sense. • Use the same trial and error method to balance oxygen. • Adding 2 on both the sides, it will become 6 oxygen atoms on the reactant side along with 6 oxygen atoms on the product side. • Finally, the balanced chemical equation will be : 2H 2 S + 3O 2 → 2SO 2 + 2H 2 O

Balanced chemical equation: A chemical equation in which the number of atoms of each element on both sides of the equation is equal is called a balanced chemical equation. Step 1: Representation of the chemical reaction: • Hydrogen sulfide gas burns in the air to give water and sulfur dioxide. • The reaction can be written as: H 2 S Hydrogen sulphide + O 2 Oxygen → SO 2 Sulphur dioxide + H 2 O Water Step 2: Calculating the number of atoms on both sides of the reaction: Elements Number of atoms on the reactant side Number of atoms on the product side H 2 2 S 1 1 O 2 3 Step 3: Balancing the uneven number of atoms on the reactants and products side: • As the number of atoms on the reactants and products side is different, so balancing of hydrogen, oxygen, and sulfur atoms can be done by multiplying the required coefficient for them in the reaction. • This is done by multiplying 2 to hydrogen sulfide and 3 to oxygen on the reactant side and also 2 to sulfur dioxide and 2 to water on the product side, to make the two sides equal. 2 H 2 S Hydrogen sulphide + 3 O 2 Oxygen → 2 SO 2 Sulphur dioxide + 2 H 2 O Water Elements Number of atoms on the reactant side Number of atoms on the product side H 4 4 S 2 2 O 6 6 Now, we can see that the balanced equation is: 2 H 2 S Hydrogen sulfide + 3 O 2 Oxygen → 2 SO 2 Sulfur dioxide + 2 H 2 O Water Q. Translate the following statements into chemical equations and then balance them. (a) Hydrogen gas combines with nitrogen to form ammonia....

The equation Hydrogen Sulfide gas burns in the air to give Water and Sulfur dioxide is balanced as 2H2S + 3O2 → 2SO2 + 2H2O. To balance a chemical equation, the stoichiometric coefficients on the reactants and products sides must be equal. As the chemical equation abides by the rule of conservation of mass and momentum, this must be done. The following is the equation for the reaction that releases water and sulphur dioxide after burning hydrogen sulphide gas in the air: H2S (g) + O2 (g) → H2O (l) + SO2 (g) Steps to balance the Equation Step 1: Create the chemical equation with the unbalance. Let's consider the indicated response. That is how sulphur dioxide and water are produced when hydrogen sulphide gas burns in the atmosphere. H2S + O2 → SO2 + H2O Step 2: Calculate the number of atoms. List the atoms of each element on the reactant and product sides, respectively. Atom Reactant Side Product Side H 1 2 S 1 1 O 2 3 Step 3: In a chemical equation, add coefficients to balance the mass. The coefficients that must be added must be whole numbers, and each coefficient must be applied to every atom in that specific molecule. Example - In 2H2O, 4 hydrogen atoms and 2 oxygen atoms are implied. Balance the lone oxygen atom first, then go on to the hydrogen atom. In this case, sulphur will be balanced before oxygen. Use the trial-and-error approach. Adding 2 hydrogen will result in 4 on both the reactants' and the product's sides. Therefore, 2 H works and 2 hydrogen sulphide res...