In a screw gauge 5 complete rotations

• • For Dropper/Repeater • For Class 11 th Student • For Class 12 th Student • Crash Course for JEE Advanced • For Class 10 th + JEE Student • For Class 9 th + 10 th + JEE Student • • For Class 11 th Student • For Class 12 th Student • For Dropper/Repeater • For Class 10 th + NEET Student • For Class 9 th + 10 th + NEET Student • • For Class 10 th Boards Student • For Class 10 th Boards + JEE/NEET Student • • For Class 9 th Student • For Class 9 th + 10 th Student • For Class 9 th + 10 th + JEE/NEET Student • • For Class 8 th Student • • • • • • Question: Assertion A : If in five complete rotations of the circular scale, the distance travelled on main scale of the screw gauge is 5 mm and there are 50 total divisions on circular scale, then least count is 0.001 cm. Reason R : Least Count $=\frac$ In the light of the above statements, choose the most appropriate answer from the options given below :

In a screw gauge, $$5$$ complete rotations of the screw cause it to move a linear distance of $$0.25$$ $$cm.$$ There are $$100$$ circular scale divisions. The thickness of a wire measured by this screw gauge gives a reading of $$4$$ main scale divisions and $$30$$ circular scale divisions. Assuming negligible zero error, the thickness of the wire is : A physical quantity P is described by the relation P = a$$^$$ b 2 c 3 d $$-$$4 If the relative errors in the measurement of a, b, c and d respectively, are 2%, 1%, 3% and 5%, then the relative error in P will be : The following observations were taken for determining surface tension T of water by capillary method: diameter of capillary, D = 1.25 $$\times$$ 10 -2 m rise of water, h = 1.45 $$\times$$ 10 -2m Using g = 9.80 m/s 2 and the simplified relation T = $$N/m$$, the possible error in surface tension is closest to :