Int to string java

The Java Programming language is strict about handling data and data types. As a result, there are many different data types in the Java language, and each has specific origins and behaviors. With every kind of data, it’s essential to understand how it works and how it affects your software programming. In this post, you’ll learn the process of converting one data type into another, specifically conversion from int to string. You’ll discover how it works, how to accomplish it, and how to use it to benefit your programming. You’ll also see some code examples of the three most common ways to do this and learn to understand the syntax for each. Without further delay, let’s get started. Integer to String Java Converting data types in Java is a simple process, but it helps to understand the different ways to do it and how those ways behave. For example, converting integers into strings in java can be done in a few ways; each is accomplished differently. Check out the video below to learn more about how these techniques work. Converting integers into strings is helpful for a multitude of different tasks, especially common for displaying data to users in a readable format. However, it is also beneficial for accessing and manipulating numerical data. In addition, string data is more flexible to work with because the string class has more methods. Furthermore, there are other classes and methods than can be used to interact with strings since it is a prevalent data type. A great ex...

One more way- By using java.lang.Integer you can get string representation of the first argument i in the radix (Octal - 8, Hex - 16, Binary - 2) specified by the second argument. Integer.toString(i, radix) Example_ private void getStrtingRadix() OutPut_ Binary eqivalent of 100 = 1100100 Octal eqivalent of 100 = 144 Decimal eqivalent of 100 = 100 Hexadecimal eqivalent of 100 = 64 public class Main This is something I wrote a few minutes ago just messing around. Hope it helps! public class Main Convert Integer to Binary: import java.util.Scanner; public class IntegerToBinary Output: Enter Integer: 10 Binary Number: 1010 The simplest approach is to check whether or not the number is odd. If it is, by definition, its right-most binary number will be "1" (2^0). After we've determined this, we bit shift the number to the right and check the same value using recursion. @Test public void shouldPrintBinary() Using built-in function: String binaryNum = Integer.toBinaryString(int num); If you don't want to use the built-in function for converting int to binary then you can also do this: import java.util.*; public class IntToBinary here is my methods, it is a little bit convince that number of bytes fixed private void printByte(int value) My 2cents: public class Integer2Binary public class BinaryConverter In order to make it exactly 8 bit, I made a slight addition to @sandeep-saini 's answer: public static String intToBinary(int number) So now for an input of 1 you get an ou...

Java is one of the most preferred Here’s what we’ll cover: • Introduction • 5 Different methods to convert integer to string in Java • Java interview questions on converting an integer to a string Introduction String in Java is a collection of characters, and there are many operations, such as finding substring and concatenation, that can be performed on a string but not on an integer. Say we want to concatenate two integers or want to find out if an integer contains a specific digit or not. We can simply convert integers to strings to do this type of operation easily. Different Methods to Convert an Integer to String in Java There are many ways to convert integers to strings; let's look at them one by one. Method 1. Using toString() Method The return type of to String() is String, and it is present in many Java classes. It can be used in two ways: • By the static function of the Integer class like Integer.toString(100) • By using the regular version of the Integer class’s object. We need first to convert int to Integer because this method cannot be used with the primitive type int. We can use a simple assignment using the = operator. Here’s the code: public class IK Output: Before conversion: 100 After conversion: 100 Interview Questions on Converting Integer to String in Java Here are a few sample interview questions related to converting an integer to a string in Java: • How to convert string to int in Java? • How to convert int to string in Java effectively? • Why is s...

Output Converted type : java.lang.String 999999999999 B. Using The valueOf() method converts data from its internal form into human-readable form. It is a static method that is overloaded within a string for all of Java’s built-in types so that each type can be converted properly into a string. It is called when a string representation of some other type of data is needed-for example during concatenation operation. You can call this method with any data type and get a reasonable String representation. Output Converted type : java.lang.String 999999999999 C. Using Long. Object class contains toString() method. We can use toString() method to get string representation of an object. Whenever we try to print the Object reference then internally toString() method is invoked. If we did not define toString() method in your class then Object class toString() method is invoked otherwise our implemented/Overridden toString() method will be called. Syntax: String str = Long.toString(varLong); Since this version of java does not support this constructor. Hence, on running the program, we will get the error displaying Note: prog.java uses or overrides a deprecated API. E. Using The java string format() method returns a formatted string using the given locale, specified format string and arguments. Syntax: long varLong = 9999999L; String str = String.format("%d", varLong); Output Converted type : java.lang.String 9999999 F. Using StringBuffer is a peer class of String that provides mu...

I have written a Java program that converts an integer to String digit by digit and concatenate them together using the + operator without touching the Stock Java API library. I like to have feedback on my code. Where do I need to improve. If I need to deduct something. So please criticize me. Thank you. import java.util.Scanner; public class StrFromInteger Things I like about your code • The idea to calculate the length of a number with the logarithm is really good! • In my opinion you are writing good comments. • Good variable names • Works as intended, without (to my knowledge) any bugs. Criticism returnDigitString() • It is considered bad practice to put more than one command into one line. So please make line breaks after every ";". • Your solution is pretty long (over 30 lines) in comparison to the complexity of the problem. You could also have done something like that: public static String returnDigitString(int digit) instead. • "valStr" is not necessary. You can just write: strSeq = returnDigitString(remainder) + strSeq; But this really is a minor point and just my personal opinion. It's fine to use an extra variable for this. Codestructure • I would use an extra method for the content of the main-method. Just use the main-method to call the new method. \$\begingroup\$ I'm not so familiar with Java in particular, but the code for(int i = 0; i <= 9; i++) replacing each instance of i with digit in ... - which is far more clear (and more efficient, if we care). It ...

You could parse the month using SimpleDateFormat: Date date = new SimpleDateFormat("MMM", Locale.ENGLISH).parse("Feb"); Calendar cal = Calendar.getInstance(); cal.setTime(date); int month = cal.get(Calendar.MONTH); System.out.println(month == Calendar.FEBRUARY); Be careful comparing int month to an int (it does not equal 2!). Safest is to compare them using Calendar's static fields (like Calendar.FEBRUARY). An alternative to SimpleDateFormat using Joda time: import org.joda.time.DateTime; import org.joda.time.format.DateTimeFormat; import org.joda.time.format.DateTimeFormatter; ... // if default locale is ok simply omit '.withLocale(...)' DateTimeFormatter format = DateTimeFormat.forPattern("MMM"); DateTime instance = format.withLocale(Locale.FRENCH).parseDateTime("août"); int month_number = instance.getMonthOfYear(); String month_text = instance.monthOfYear().getAsText(Locale.ENGLISH); System.out.println( "Month Number: " + month_number ); System.out.println( "Month Text: " + month_text ); OUTPUT: Month Number: 8 Month Text: August you could just set up a switch statment, something like this (below). I'm posting this in case anyone wants a simple, easy to understand solution I know I would have wanted it before I typed this up: switch(input2) Here is the way to do it: String a = "August 10, 2021 10:00 AM"; SimpleDateFormat fromUser = new SimpleDateFormat("MMMM dd, yyyy hh:mm a"); SimpleDateFormat myFormat = new SimpleDateFormat("MM/dd/yyyy"); String reformattedStr = myFo...

Mod note: This question has 30 answers and another 82 deleted answers, most of which were removed for repeating existing answers. If you are considering adding a new answer to this question, please ensure that you've read all the existing answers and confirmed that your answer adds something new and useful. String myString = "1234"; int foo = Integer.parseInt(myString); If you look at the NumberFormatException, which you can handle: int foo; try (This treatment defaults a malformed number to 0, but you can do something else if you like.) Alternatively, you can use an Ints method from the Guava library, which in combination with Java 8's Optional, makes for a powerful and concise way to convert a string into an int: import com.google.common.primitives.Ints; int foo = Optional.ofNullable(myString) .map(Ints::tryParse) .orElse(0) For example, here are two ways: Integer x = Integer.valueOf(str); // or int y = Integer.parseInt(str); There is a slight difference between these methods: • valueOf returns a new or cached instance of java.lang.Integer • parseInt returns primitive int. The same is for all cases: Short.valueOf/ parseShort, Long.valueOf/ parseLong, etc. Well, a very important point to consider is that the Integer parser throws NumberFormatException as stated in int foo; String StringThatCouldBeANumberOrNot = "26263Hello"; //will throw exception String StringThatCouldBeANumberOrNot2 = "26263"; //will not throw exception try It is important to handle this exception whe...

For example, suppose we have two variables of type long and Long (one of primitive type and the other of reference type): long l = 10L; Long obj = 15L; We can simply use the toString() method of the Long class to convert them to String: String str1 = Long.toString(l); String str2 = Long.toString(obj); System.out.println(str1); System.out.println(str2); The output will look like this: 10 15 If our obj object is null, we'll get a NullPointerException.

The Java Programming language is strict about handling data and data types. As a result, there are many different data types in the Java language, and each has specific origins and behaviors. With every kind of data, it’s essential to understand how it works and how it affects your software programming. In this post, you’ll learn the process of converting one data type into another, specifically conversion from int to string. You’ll discover how it works, how to accomplish it, and how to use it to benefit your programming. You’ll also see some code examples of the three most common ways to do this and learn to understand the syntax for each. Without further delay, let’s get started. Integer to String Java Converting data types in Java is a simple process, but it helps to understand the different ways to do it and how those ways behave. For example, converting integers into strings in java can be done in a few ways; each is accomplished differently. Check out the video below to learn more about how these techniques work. Converting integers into strings is helpful for a multitude of different tasks, especially common for displaying data to users in a readable format. However, it is also beneficial for accessing and manipulating numerical data. In addition, string data is more flexible to work with because the string class has more methods. Furthermore, there are other classes and methods than can be used to interact with strings since it is a prevalent data type. A great ex...

You could parse the month using SimpleDateFormat: Date date = new SimpleDateFormat("MMM", Locale.ENGLISH).parse("Feb"); Calendar cal = Calendar.getInstance(); cal.setTime(date); int month = cal.get(Calendar.MONTH); System.out.println(month == Calendar.FEBRUARY); Be careful comparing int month to an int (it does not equal 2!). Safest is to compare them using Calendar's static fields (like Calendar.FEBRUARY). An alternative to SimpleDateFormat using Joda time: import org.joda.time.DateTime; import org.joda.time.format.DateTimeFormat; import org.joda.time.format.DateTimeFormatter; ... // if default locale is ok simply omit '.withLocale(...)' DateTimeFormatter format = DateTimeFormat.forPattern("MMM"); DateTime instance = format.withLocale(Locale.FRENCH).parseDateTime("août"); int month_number = instance.getMonthOfYear(); String month_text = instance.monthOfYear().getAsText(Locale.ENGLISH); System.out.println( "Month Number: " + month_number ); System.out.println( "Month Text: " + month_text ); OUTPUT: Month Number: 8 Month Text: August you could just set up a switch statment, something like this (below). I'm posting this in case anyone wants a simple, easy to understand solution I know I would have wanted it before I typed this up: switch(input2) Here is the way to do it: String a = "August 10, 2021 10:00 AM"; SimpleDateFormat fromUser = new SimpleDateFormat("MMMM dd, yyyy hh:mm a"); SimpleDateFormat myFormat = new SimpleDateFormat("MM/dd/yyyy"); String reformattedStr = myFo...