It costs rs. 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. if the cost of painting is at the rate of r s 20 p e r m 2 , find the radius of the base.

  1. It costs Rs 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. If the cost of painting is at the rate of Rs 20 per m ^2, find (i) inner curved surface area of the vessel
  2. Question 5
  3. Question 5 iiIt costs Rs. 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. If the cost of painting is at the rate of Rs 20per m2, find:ii The radius of the base.
  4. The cost of painting outer curved surface of a hollow hemispherical iron ball at rate of Rs. 2 per cm square is Rs. 1256 . If thickness of the iron is 1 cm, find the cost of painting the inner curved surface of the ball.Take π=3.14 .A. Rs. 2034.72B. Rs. 1076.32C. Rs. 1017.36D. Rs. 508.68
  5. Question 5
  6. Question 5 iiIt costs Rs. 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. If the cost of painting is at the rate of Rs 20per m2, find:ii The radius of the base.
  7. The cost of painting outer curved surface of a hollow hemispherical iron ball at rate of Rs. 2 per cm square is Rs. 1256 . If thickness of the iron is 1 cm, find the cost of painting the inner curved surface of the ball.Take π=3.14 .A. Rs. 2034.72B. Rs. 1076.32C. Rs. 1017.36D. Rs. 508.68
  8. Question 5
  9. Question 5 iiIt costs Rs. 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. If the cost of painting is at the rate of Rs 20per m2, find:ii The radius of the base.
  10. The cost of painting outer curved surface of a hollow hemispherical iron ball at rate of Rs. 2 per cm square is Rs. 1256 . If thickness of the iron is 1 cm, find the cost of painting the inner curved surface of the ball.Take π=3.14 .A. Rs. 2034.72B. Rs. 1076.32C. Rs. 1017.36D. Rs. 508.68


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It costs Rs 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. If the cost of painting is at the rate of Rs 20 per m ^2, find (i) inner curved surface area of the vessel

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Question 5

Important Deleted for CBSE Board 2024 Exams Deleted for CBSE Board 2024 Exams Important Deleted for CBSE Board 2024 Exams Deleted for CBSE Board 2024 Exams Important Deleted for CBSE Board 2024 Exams Deleted for CBSE Board 2024 Exams Deleted for CBSE Board 2024 Exams Important Deleted for CBSE Board 2024 Exams Important Deleted for CBSE Board 2024 Exams You are here Deleted for CBSE Board 2024 Exams Transcript Question 5 It costs Rs 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. If the cost of painting is at the rate of Rs 20 per m2, find (i) inner curved surface area of the vessel, Cost of painting = Inner curved surface area Rate of painting Rs 2200 = Inner curved surface area 20 2200/20 = Inner curved surface area Inner curved surface area = 2200/20 Inner curved surface area = 110 Therefore, inner curved surface area of vessel = 110 m2 Question 5 (ii) radius of the base, Let radius of cylinder be r Height = h = 10 m We know that Curved surface area of cylinder = 110 m2 2 = 110 2 22/7 r 10 = 110 r = (110 7)/(2 22 10) r = 7/4 r = 1.75 m Question 5 (iii) capacity of the vessel. We know that Height = h = 10 m Radius = r = 1.75 m = 7/4 m Capacity of the vessel = volume = r2h = (22/7 7/4 7/4 10) m3 = (22 1/4 7/4 10) m3 = 96.25 m3 Show More

Question 5 iiIt costs Rs. 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. If the cost of painting is at the rate of Rs 20per m2, find:ii The radius of the base.

(ii) Rs. 20 is the cost of painting 1 m 2 area. Area painted for Rs. 2200 = ( 1 20 × 2200 ) m 2 = 110 m 2 Therefore, the inner surface area of the vessel is 110 m 2. Let the radius of the base of the vessel be r. Height (h) of the vessel = 10 m Surface area = 2 π r h = 110 m 2 ⇒ ( 2 × 22 7 × r × 10 ) m = 110 m 2 ⇒ r = ( 7 4 m ) = 1.75 m

The cost of painting outer curved surface of a hollow hemispherical iron ball at rate of Rs. 2 per cm square is Rs. 1256 . If thickness of the iron is 1 cm, find the cost of painting the inner curved surface of the ball.Take π=3.14 .A. Rs. 2034.72B. Rs. 1076.32C. Rs. 1017.36D. Rs. 508.68

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Question 5

Important Deleted for CBSE Board 2024 Exams Deleted for CBSE Board 2024 Exams Important Deleted for CBSE Board 2024 Exams Deleted for CBSE Board 2024 Exams Important Deleted for CBSE Board 2024 Exams You are here Deleted for CBSE Board 2024 Exams Important Deleted for CBSE Board 2024 Exams Deleted for CBSE Board 2024 Exams Transcript Question 5 It costs Rs 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. If the cost of painting is at the rate of Rs 20 per m2, find (i) inner curved surface area of the vessel, Cost of painting = Inner curved surface area Rate of painting Rs 2200 = Inner curved surface area 20 2200/20 = Inner curved surface area Inner curved surface area = 2200/20 Inner curved surface area = 110 Therefore, inner curved surface area of vessel = 110 m2 Question 5 (ii) radius of the base, Let radius of cylinder be r Height = h = 10 m We know that Curved surface area of cylinder = 110 m2 2 = 110 2 22/7 r 10 = 110 r = (110 7)/(2 22 10) r = 7/4 r = 1.75 m Question 5 (iii) capacity of the vessel. We know that Height = h = 10 m Radius = r = 1.75 m = 7/4 m Capacity of the vessel = volume = r2h = (22/7 7/4 7/4 10) m3 = (22 1/4 7/4 10) m3 = 96.25 m3 Show More

Question 5 iiIt costs Rs. 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. If the cost of painting is at the rate of Rs 20per m2, find:ii The radius of the base.

(ii) Rs. 20 is the cost of painting 1 m 2 area. Area painted for Rs. 2200 = ( 1 20 × 2200 ) m 2 = 110 m 2 Therefore, the inner surface area of the vessel is 110 m 2. Let the radius of the base of the vessel be r. Height (h) of the vessel = 10 m Surface area = 2 π r h = 110 m 2 ⇒ ( 2 × 22 7 × r × 10 ) m = 110 m 2 ⇒ r = ( 7 4 m ) = 1.75 m

The cost of painting outer curved surface of a hollow hemispherical iron ball at rate of Rs. 2 per cm square is Rs. 1256 . If thickness of the iron is 1 cm, find the cost of painting the inner curved surface of the ball.Take π=3.14 .A. Rs. 2034.72B. Rs. 1076.32C. Rs. 1017.36D. Rs. 508.68

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Question 5

Important Deleted for CBSE Board 2024 Exams Deleted for CBSE Board 2024 Exams Important Deleted for CBSE Board 2024 Exams Deleted for CBSE Board 2024 Exams Important Deleted for CBSE Board 2024 Exams Deleted for CBSE Board 2024 Exams Deleted for CBSE Board 2024 Exams Important Deleted for CBSE Board 2024 Exams Important Deleted for CBSE Board 2024 Exams You are here Deleted for CBSE Board 2024 Exams Transcript Question 5 It costs Rs 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. If the cost of painting is at the rate of Rs 20 per m2, find (i) inner curved surface area of the vessel, Cost of painting = Inner curved surface area Rate of painting Rs 2200 = Inner curved surface area 20 2200/20 = Inner curved surface area Inner curved surface area = 2200/20 Inner curved surface area = 110 Therefore, inner curved surface area of vessel = 110 m2 Question 5 (ii) radius of the base, Let radius of cylinder be r Height = h = 10 m We know that Curved surface area of cylinder = 110 m2 2 = 110 2 22/7 r 10 = 110 r = (110 7)/(2 22 10) r = 7/4 r = 1.75 m Question 5 (iii) capacity of the vessel. We know that Height = h = 10 m Radius = r = 1.75 m = 7/4 m Capacity of the vessel = volume = r2h = (22/7 7/4 7/4 10) m3 = (22 1/4 7/4 10) m3 = 96.25 m3 Show More

Question 5 iiIt costs Rs. 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. If the cost of painting is at the rate of Rs 20per m2, find:ii The radius of the base.

(ii) Rs. 20 is the cost of painting 1 m 2 area. Area painted for Rs. 2200 = ( 1 20 × 2200 ) m 2 = 110 m 2 Therefore, the inner surface area of the vessel is 110 m 2. Let the radius of the base of the vessel be r. Height (h) of the vessel = 10 m Surface area = 2 π r h = 110 m 2 ⇒ ( 2 × 22 7 × r × 10 ) m = 110 m 2 ⇒ r = ( 7 4 m ) = 1.75 m

The cost of painting outer curved surface of a hollow hemispherical iron ball at rate of Rs. 2 per cm square is Rs. 1256 . If thickness of the iron is 1 cm, find the cost of painting the inner curved surface of the ball.Take π=3.14 .A. Rs. 2034.72B. Rs. 1076.32C. Rs. 1017.36D. Rs. 508.68

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