Maharashtra board solutions class 7

Maharashtra State Board 7th Standard Mathematics Solutions Guide Shaalaa provides solutions for Maharashtra State Board 7th Standard Mathematics Solutions Digest. Shaalaa is undoubtedly a site that most of your classmates are using to perform well in exams. You can solve 7th Standard Mathematics Book Solutions Maharashtra State Board textbook questions by using Shaalaa.com to verify your answers. This will help you practise better and become more confident. Balbharati Solutions for 7th Standard Mathematics Chapterwise List | 7th Standard Mathematics Digest The answers to the Balbharati books are the best study material for students. The following links are • • • • • • • • • • • • • • • • • Appears in • Concepts covered in Geometrical Constructions are Congruence Among Line Segments, Congruence of Angles, Congruence of Circles, Construct a Right-angled Triangle Given the Hypotenuse and One Side, Construct a Triangle Given Two Angles and the Included Side, Constructing a Bisector of an Angle, Constructing a Triangle When the Length of Its Three Sides Are Known (SSS Criterion), Constructing a Triangle When the Lengths of Two Sides and the Measure of the Angle Between Them Are Known. (SAS Criterion), Construction of Triangles, Drawing a Perpendicular to a Line at a Point on the Line, Perpendicular Bisectors of the Sides of an Acute-angled Triangle, Perpendicular Bisectors of the Sides of an Obtuse-angled Triangle, The Property of the Angle Bisectors of a Triangle Concepts cove...

Balbharti Maharashtra State Board Class 7 Maths Solutions covers the 7th Std Maths Miscellaneous Problems Set 1 Answers Solutions. Maharashtra Board Miscellaneous Problems Set 1 Class 7 Maths Solutions Question 1. Solve the following: i. (-16) × (-5) ii. (72) ÷ (-12) iii. (-24) × (2) iv. 125 ÷ 5 v. (-104) ÷ (-13) vi. … Categories Balbharti Maharashtra State Board Class 7 Maths Solutions covers the 7th Std Maths Miscellaneous Problems Set 2 Answers Solutions. Maharashtra Board Miscellaneous Problems Set 2 Class 7 Maths Solutions Question 1. Angela deposited Rs 15000 in a bank at a rate of 9 p.c.p.a. She got simple interest amounting to Rs 5400. For how many … Categories Balbharti Maharashtra State Board Class 7 Maths Solutions covers the 7th Std Maths Practice Set 40 Answers Solutions Chapter 10 Bank and Simple Interest. Bank and Simple Interest Class 7 Practice Set 40 Answers Solutions Chapter 10 Question 1. If Rihanna deposits Rs 1500 in the school fund at 9 p.c.p.a for 2 years, what … Categories Balbharti Maharashtra State Board Class 7 Maths Solutions covers the 7th Std Maths Practice Set 1 Answers Solutions Chapter 1 Geometrical Constructions. Geometrical Constructions Class 7 Practice Set 1 Answers Solutions Chapter 1 Question 1. Draw line segments of the lengths given below and draw their perpendicular bisectors: i. 5.3 cm ii. 6.7 cm iii. … Categories Balbharti Maharashtra State Board Class 7 Maths Solutions covers the 7th Std Maths Practice Set 31 Answers Solutions ...

NCERT Solutions for Class 12 Business Studies Chapter 7: Jagran Josh brings to you NCERT Solutions for Class 12 Business Studies Chapter 7, Directing. You can also find a free PDF download link for complete solutions of the chapter mentioned here in the article. These solutions should be practised consistently to score good marks in CBSE Board Examinations 2024. This chapter on directing can teach you about: • Concept of directing and its importance in an organization, • Principles guiding directing processes, • Meaning of supervision and its importance, • Meaning of motivation and its importance in business management, • Maslow’s theory of hierarchy of needs and its application, • Financial and non-financial incentives, • Leadership and its importance, • Qualities of a good leader, • Formal and informal communications and • Barriers to effective communications and measures to overcome this barrier Related: CBSE Class 12 Business Studies Revised Syllabus 2023-2024 (PDF) CBSE Class 12 Business Studies Sample Paper 2023-2024(PDF) Find NCERT Solutions for Class 12 Business Studies Chapter 7, Directing Very Short Answer Type 1.What is informal communication? Answer.Communication that does not follow the formal lines of communication is said to be informal communication. In corporate world, it is referred to as grapevines since it spreads throughout the organization with its branches going out in all directions. 2.Which style of leadership does not believe in use of power unles...

Contents • 1 Maharashtra Board Solutions Class 7-Maths (Practice Set 42): Chapter 11- Circle • 2 Download PDF • 3 Chapterwise Maharashtra Board Solutions Class 7 Maths : • 4 FAQs • 5 About Maharashtra State Board (MSBSHSE) • 5.1 Related Maharashtra Board Solutions Class 7-Maths (Practice Set 42): Chapter 11- Circle Maharashtra Board 7th Maths Chapter 11, Class 7 Maths Chapter 11 solutions Question 1. Complete the table below: Sr. No Radius (r) Diameter (d) Circumference (c) i. 7 cm ii. 28 cm iii. 616 cm iv. 72.6 cm Solution: i. Radius (r) = 7 cm Diameter (d) = 2r = 2 x 7 = 14 cm Circumference (c) = πd = 227 x 14 = 44 cm ii. Diameter (d) = 28 cm Radius (r) = d2=282 = 14 cm Circumference (c) = πd = 227 x 28 = 88 cm iii. Circumference (c) = 616 cm ∴ πd = 616 ∴ 227 x d = 616 ∴ d = 616 x 722 ∴ d = 196 cm ∴ Diameter (d) = 196 cm Radius (r) = d2=1962 = 98 cm iv. Circumference (c) = 72.6 cm ∴ πd = 72.6 227 x d = 72.6 ∴ d=72.6×722=72610×722=33×710 ∴ d = 23.1 cm ∴ Diameter (d) = 23.1 cm Radius (r) = d2=23.12 = 11.55 cm Sr. No Radius (r) Diameter (d) Circumference (c) i. 7 cm 14 cm 44 cm ii. 14 cm 28 cm 88 cm iii. 98 cm 196 cm 616 cm iv. 11.55 cm 23.1 cm 72.6 cm Question 2. If the circumference of a circle is 176 cm, find its radius. Solution: Circumference (c) = 176 cm ∴ 2πr = 176 ∴ 2 x 227 x r = 176 ∴ 447 x r = 176 ∴ r = 176 x 744 = 28 cm ∴ The radius of the circle is 28 cm. Question 3. The radius of a circular garden is 56 m. What would it cost to put a 4-round fence around this g...

NCERT Solutions for Class 12 Commerce: Jagran Josh presents subject-wise complete NCERT Solutions for Commerce Subjects. In this article you can find easy and accurate, chapter-wise NCERT Solutions for Accountancy, Business Studies and Economics subjects. All these solutions have been prepared by our subject experts, as per latest CBSE guidelines. CBSE’s updated syllabus 2023-2024 has been referred to, in making of this article. NCERT Solutions are important for scoring good marks in CBSE Board Examinations. Consistent practise of these solutions can help you clear your concepts about Accountancy, Management, Economy of India and much more. Every year CBSE marks down some important topics from each chapter, for upcoming Board Examinations. Developing a thorough understanding about concepts of these chapters, practise of in-text questions, practise of NCERT Solutions present at the end of each chapter, practise of sample papers, practise of previous years papers of atleast last 5 years, can help you score well in CBSE Board Examinations 2023-2024. Related: CBSE Revised Syllabus for Business Studies(2023-2024) CBSE Revised Syllabus for Accountancy(2023-2024) CBSE Revised Syllabus for Economics(2023-2024) CBSE Sample Paper for Economics(2023-2024) CBSE Sample Paper for Accountancy(2023-2024) CBSE Sample Paper for Business studies(2023-2024) Find PDF links for chapter-wise NCERT Solutions of Accountancy. Accountancy(Part-1) Chapter No PDF Link Chapter-1 Chapter-2 Chapter-3 Cha...

Balbharti Algebraic Formulae – Expansion of Squares Class 7 Practice Set 50 Answers Solutions Chapter 14 Question 1. Expand: i. (5a + 6b)² ii. \(\left(\frac\) Solution: i. (5a + 6b)² Here, A = 5a and B = 6b (5a + 6b)² = (5a)² + 2 × 5a × 6b + (6b)² …. [(A + B)² = A² + 2AB + B²] ∴ (5a + 6b)² = 25a² + 60ab + 36b² ii. \(\left(\frac\) v. (ax + by)² Here, A = ax and B = by (ax + by)² = (ax)² + 2 × ax × by + (by)² …. [(A + B)² = A² + 2AB + B²] ∴ (ax + by)² = a²x² + 2abxy + b²y² viii. \(\left(a-\frac\) Question 3. Of which of the binomials given below is the m²n² + 14mnpq + 49p²q² the expansion? (A) (m + n) (p + q) (B) (mn – pq) (C) (7mn + pq) (D) (mn + 7pq) Solution: (D) (mn + 7pq) Hint: Here, square root of the first term = mn Square root of the last term = 7pq ∴ Required binomial = (mn + 7pq)² Question 4. Use an expansion formula to find the values of: i. (997)² ii. (102)² iii. (97)² iv. (1005)² Solution: i. (997)² = (1000 – 3)² Here, a = 1000 and b = 3 (1000 – 3)² = (1000)² – 2 x 1000 x 3 + 3² …. [(a – b)² = a² – 2ab + b²] = 1000000 – 6000 + 9 = 994009 ∴ (997)² = 994009 ii. (102)² = (100 + 2)² Here, a = 100 and b = 2 (100 + 2)² = (100)² + 2 x 100 x 2 + 2² …. [(a + b)² = a² + 2ab + b²] = 10000 + 400 + 4 = 10404 ∴ (102)² = 10404 iii. (97)² = (100 – 3)² Here, a = 100 and b = 3 (100 – 3)² = (100)² – 2 x 100 x 3 + 3² …. [(a – b)² = a² – 2ab + b²] = 10000 – 600 + 9 = 9409 ∴ (97)² = 9409 iv. (1005)² = (1000 + 5)² Here, a = 1000 and b = 5 (1000 + 5)² = (1000)² + 2 x 1000 x 5 + 5² …. [...