Roman to integer leetcode solution

Contents • • • • • • • • • • Problem Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, 2 is written as II in Roman numeral, just two one’s added together. 12 is written as XII, which is simply X + II. The number 27 is written as XXVII, which is XX + V + II. Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII. Instead, the number four is written as IV. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX. There are six instances where subtraction is used: • I can be placed before V (5) and X (10) to make 4 and 9. • X can be placed before L (50) and C (100) to make 40 and 90. • C can be placed before D (500) and M (1000) to make 400 and 900. Given a roman numeral, convert it to an integer. Example 1 : Input: s = "III" Output: 3 Explanation: III = 3. Example 2 : Input: s = "LVIII" Output: 58 Explanation: L = 50, V= 5, III = 3. Example 3 : Input: s = "MCMXCIV" Output: 1994 Explanation: M = 1000, CM = 900, XC = 90 and IV = 4. Constraints • 1 map = new HashMap(); map.put('I', 1); map.put('V', 5); map.put('X', 10); map.put('L', 50); map.put('C', 100); map.put('D', 500); map.put('M', 1000); int len = s.length(), result = map.get(s.charAt(len - 1)); for (int i = len - 2; i >= 0; i--) number = 0 s = s.replace("IV", "IIII").replace("IX", "VIIII"...

Table of Contents • • • • Problem Roman numerals are represented by seven different symbols: I, V X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, 2 is written as II in Roman numeral, just two ones added together 12 is written as XII, which is simply X + II. The number 27 is written as XXVII, which is XX + V + II. Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII. Instead, the number four is written as IV. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX. There are six instances where subtraction is used: • I can be placed before V (5) and X (10) to make 4 and 9. • X can be placed before L (50) and C (100) to make 40 and 90 class Solution(object): def romanToInt(self, s): """ :type s: str :rtype: int """ roman_dic = skip_next_n = False int_sum = 0 for idx, n in enumerate(s): if skip_next_n == True: skip_next_n = False continue try: if roman_dic[n] < roman_dic[s[idx + 1]]: int_sum += roman_dic[s[idx + 1]] - roman_dic[n] skip_next_n = True continue else: int_sum += roman_dic[n] except: int_sum += roman_dic[n] return int_sum Roman to Integer Leetcode Solution in CPP class Solution ; Roman to Integer Leetcode Solution in Java public int romanToInt(String s) Note: This problem

1 Solution: Next Permutation 2 Solution: Trim a Binary Search Tree ... 157 more parts... 3 Leetcode Solutions Index 4 Solution: Minimize Deviation in Array 5 Solution: Vertical Order Traversal of a Binary Tree 6 Solution: Count Ways to Make Array With Product 7 Solution: Smallest String With A Given Numeric Value 8 Solution: Linked List Cycle 9 Solution: Path With Minimum Effort 10 Solution: Concatenation of Consecutive Binary Numbers 11 Solution: Minimum Operations to Make a Subsequence 12 Solution: Longest Harmonious Subsequence 13 Solution: Simplify Path 14 Solution: Building Boxes 15 Solution: Decode XORed Permutation 16 Solution: Binary Tree Right Side View 17 Solution: Find Kth Largest XOR Coordinate Value 18 Solution: Change Minimum Characters to Satisfy One of Three Conditions 19 Solution: Shortest Distance to a Character 20 Solution: Peeking Iterator 21 Solution: Convert BST to Greater Tree 22 Solution: Copy List with Random Pointer 23 Solution: Valid Anagram 24 Solution: Number of Steps to Reduce a Number to Zero 25 Solution: Shortest Path in Binary Matrix 26 Solution: Is Graph Bipartite? 27 Solution: Maximum Score From Removing Substrings (ver. 1) 28 Solution: Maximum Score From Removing Substrings (ver. 2) 29 Solution: Sort the Matrix Diagonally 30 Solution: The K Weakest Rows in a Matrix (ver. 1) 31 Solution: The K Weakest Rows in a Matrix (ver. 2) 32 Solution: Letter Case Permutation 33 Solution: Container With Most Water 34 Solution: Arithmetic Slices 35 Sol...

Table of Contents • • • • Problem Roman numerals are represented by seven different symbols: I, V X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, 2 is written as II in Roman numeral, just two ones added together 12 is written as XII, which is simply X + II. The number 27 is written as XXVII, which is XX + V + II. Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII. Instead, the number four is written as IV. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX. There are six instances where subtraction is used: • I can be placed before V (5) and X (10) to make 4 and 9. • X can be placed before L (50) and C (100) to make 40 and 90 class Solution(object): def romanToInt(self, s): """ :type s: str :rtype: int """ roman_dic = skip_next_n = False int_sum = 0 for idx, n in enumerate(s): if skip_next_n == True: skip_next_n = False continue try: if roman_dic[n] < roman_dic[s[idx + 1]]: int_sum += roman_dic[s[idx + 1]] - roman_dic[n] skip_next_n = True continue else: int_sum += roman_dic[n] except: int_sum += roman_dic[n] return int_sum Roman to Integer Leetcode Solution in CPP class Solution ; Roman to Integer Leetcode Solution in Java public int romanToInt(String s) Note: This problem

Contents • • • • • • • • • • Problem Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, 2 is written as II in Roman numeral, just two one’s added together. 12 is written as XII, which is simply X + II. The number 27 is written as XXVII, which is XX + V + II. Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII. Instead, the number four is written as IV. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX. There are six instances where subtraction is used: • I can be placed before V (5) and X (10) to make 4 and 9. • X can be placed before L (50) and C (100) to make 40 and 90. • C can be placed before D (500) and M (1000) to make 400 and 900. Given a roman numeral, convert it to an integer. Example 1 : Input: s = "III" Output: 3 Explanation: III = 3. Example 2 : Input: s = "LVIII" Output: 58 Explanation: L = 50, V= 5, III = 3. Example 3 : Input: s = "MCMXCIV" Output: 1994 Explanation: M = 1000, CM = 900, XC = 90 and IV = 4. Constraints • 1 map = new HashMap(); map.put('I', 1); map.put('V', 5); map.put('X', 10); map.put('L', 50); map.put('C', 100); map.put('D', 500); map.put('M', 1000); int len = s.length(), result = map.get(s.charAt(len - 1)); for (int i = len - 2; i >= 0; i--) number = 0 s = s.replace("IV", "IIII").replace("IX", "VIIII"...

1 Solution: Next Permutation 2 Solution: Trim a Binary Search Tree ... 157 more parts... 3 Leetcode Solutions Index 4 Solution: Minimize Deviation in Array 5 Solution: Vertical Order Traversal of a Binary Tree 6 Solution: Count Ways to Make Array With Product 7 Solution: Smallest String With A Given Numeric Value 8 Solution: Linked List Cycle 9 Solution: Path With Minimum Effort 10 Solution: Concatenation of Consecutive Binary Numbers 11 Solution: Minimum Operations to Make a Subsequence 12 Solution: Longest Harmonious Subsequence 13 Solution: Simplify Path 14 Solution: Building Boxes 15 Solution: Decode XORed Permutation 16 Solution: Binary Tree Right Side View 17 Solution: Find Kth Largest XOR Coordinate Value 18 Solution: Change Minimum Characters to Satisfy One of Three Conditions 19 Solution: Shortest Distance to a Character 20 Solution: Peeking Iterator 21 Solution: Convert BST to Greater Tree 22 Solution: Copy List with Random Pointer 23 Solution: Valid Anagram 24 Solution: Number of Steps to Reduce a Number to Zero 25 Solution: Shortest Path in Binary Matrix 26 Solution: Is Graph Bipartite? 27 Solution: Maximum Score From Removing Substrings (ver. 1) 28 Solution: Maximum Score From Removing Substrings (ver. 2) 29 Solution: Sort the Matrix Diagonally 30 Solution: The K Weakest Rows in a Matrix (ver. 1) 31 Solution: The K Weakest Rows in a Matrix (ver. 2) 32 Solution: Letter Case Permutation 33 Solution: Container With Most Water 34 Solution: Arithmetic Slices 35 Sol...

Contents • • • • • • • • • • Problem Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, 2 is written as II in Roman numeral, just two one’s added together. 12 is written as XII, which is simply X + II. The number 27 is written as XXVII, which is XX + V + II. Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII. Instead, the number four is written as IV. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX. There are six instances where subtraction is used: • I can be placed before V (5) and X (10) to make 4 and 9. • X can be placed before L (50) and C (100) to make 40 and 90. • C can be placed before D (500) and M (1000) to make 400 and 900. Given a roman numeral, convert it to an integer. Example 1 : Input: s = "III" Output: 3 Explanation: III = 3. Example 2 : Input: s = "LVIII" Output: 58 Explanation: L = 50, V= 5, III = 3. Example 3 : Input: s = "MCMXCIV" Output: 1994 Explanation: M = 1000, CM = 900, XC = 90 and IV = 4. Constraints • 1 map = new HashMap(); map.put('I', 1); map.put('V', 5); map.put('X', 10); map.put('L', 50); map.put('C', 100); map.put('D', 500); map.put('M', 1000); int len = s.length(), result = map.get(s.charAt(len - 1)); for (int i = len - 2; i >= 0; i--) number = 0 s = s.replace("IV", "IIII").replace("IX", "VIIII"...

1 Solution: Next Permutation 2 Solution: Trim a Binary Search Tree ... 157 more parts... 3 Leetcode Solutions Index 4 Solution: Minimize Deviation in Array 5 Solution: Vertical Order Traversal of a Binary Tree 6 Solution: Count Ways to Make Array With Product 7 Solution: Smallest String With A Given Numeric Value 8 Solution: Linked List Cycle 9 Solution: Path With Minimum Effort 10 Solution: Concatenation of Consecutive Binary Numbers 11 Solution: Minimum Operations to Make a Subsequence 12 Solution: Longest Harmonious Subsequence 13 Solution: Simplify Path 14 Solution: Building Boxes 15 Solution: Decode XORed Permutation 16 Solution: Binary Tree Right Side View 17 Solution: Find Kth Largest XOR Coordinate Value 18 Solution: Change Minimum Characters to Satisfy One of Three Conditions 19 Solution: Shortest Distance to a Character 20 Solution: Peeking Iterator 21 Solution: Convert BST to Greater Tree 22 Solution: Copy List with Random Pointer 23 Solution: Valid Anagram 24 Solution: Number of Steps to Reduce a Number to Zero 25 Solution: Shortest Path in Binary Matrix 26 Solution: Is Graph Bipartite? 27 Solution: Maximum Score From Removing Substrings (ver. 1) 28 Solution: Maximum Score From Removing Substrings (ver. 2) 29 Solution: Sort the Matrix Diagonally 30 Solution: The K Weakest Rows in a Matrix (ver. 1) 31 Solution: The K Weakest Rows in a Matrix (ver. 2) 32 Solution: Letter Case Permutation 33 Solution: Container With Most Water 34 Solution: Arithmetic Slices 35 Sol...

Table of Contents • • • • Problem Roman numerals are represented by seven different symbols: I, V X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, 2 is written as II in Roman numeral, just two ones added together 12 is written as XII, which is simply X + II. The number 27 is written as XXVII, which is XX + V + II. Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII. Instead, the number four is written as IV. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX. There are six instances where subtraction is used: • I can be placed before V (5) and X (10) to make 4 and 9. • X can be placed before L (50) and C (100) to make 40 and 90 class Solution(object): def romanToInt(self, s): """ :type s: str :rtype: int """ roman_dic = skip_next_n = False int_sum = 0 for idx, n in enumerate(s): if skip_next_n == True: skip_next_n = False continue try: if roman_dic[n] < roman_dic[s[idx + 1]]: int_sum += roman_dic[s[idx + 1]] - roman_dic[n] skip_next_n = True continue else: int_sum += roman_dic[n] except: int_sum += roman_dic[n] return int_sum Roman to Integer Leetcode Solution in CPP class Solution ; Roman to Integer Leetcode Solution in Java public int romanToInt(String s) Note: This problem

Table of Contents • • • • Problem Roman numerals are represented by seven different symbols: I, V X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, 2 is written as II in Roman numeral, just two ones added together 12 is written as XII, which is simply X + II. The number 27 is written as XXVII, which is XX + V + II. Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII. Instead, the number four is written as IV. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX. There are six instances where subtraction is used: • I can be placed before V (5) and X (10) to make 4 and 9. • X can be placed before L (50) and C (100) to make 40 and 90 class Solution(object): def romanToInt(self, s): """ :type s: str :rtype: int """ roman_dic = skip_next_n = False int_sum = 0 for idx, n in enumerate(s): if skip_next_n == True: skip_next_n = False continue try: if roman_dic[n] < roman_dic[s[idx + 1]]: int_sum += roman_dic[s[idx + 1]] - roman_dic[n] skip_next_n = True continue else: int_sum += roman_dic[n] except: int_sum += roman_dic[n] return int_sum Roman to Integer Leetcode Solution in CPP class Solution ; Roman to Integer Leetcode Solution in Java public int romanToInt(String s) Note: This problem