Class 12 >> Physics >> Dual Nature of Radiation and Matter >> Photons and Photoelectric Effect >> The stopping potential in an experiment Question The stopping potential in an experiment of photon is 2eV. What is the maximum kinetic energy of photoelectrons emitted ? Easy Solution Verified by Toppr Stopping potential, V o=2eV

KE= 4.97 x 10 − 19 − 4.4 x 10 − 19 The kinetic energy of photoelectrons is KE= 5.7 x 10 − 20 J . Example of Calculating Kinetic Energy from Stopping Voltage Light of a certain wavelength is.

Kinetic Energy of satellite: As the gravitational force is providing the necessary centripetal force required for circular motion, Now, Centripetal force = Gravitational force Where G is Universal gravitational constant. The kinetic energy of a satellite orbiting around the earth is given by Potential Energy:

the maximum kinetic energy of, say, one electron emitted will be equal to the incident (photon) energy given as hf (Planck's Constant times frequency) minus the energy that "binds" the electron to the metal (the work function ϕ ). So basically: K = hf −ϕ Kinetic Energy (max) is K = 6.4eV = 6.4 ⋅ 1.6 ×10−19 = 1.024 ×10−18J So we get:

The energy associated with an object’s motion is called kinetic energy. A speeding bullet, a walking person, and electromagnetic radiation like light all have kinetic energy. Another example of kinetic energy is the energy associated with the constant, random bouncing of atoms or molecules.

Textbook Solutions CBSE Notes Kinetic Energy An object possesses kinetic energy when it is in motion. It is defined as the amount of work that should be done to accelerate a body of a given mass from rest to a certain velocity. As this energy is gained during its acceleration, the body retains this kinetic energy till its speed is varied.

Learning Objectives Define electric potential and electric potential energy. Describe the relationship between electric potential difference and electric field. Describe the relationship between electric potential and electrical potential energy. Explain electron volt and its usage in submicroscopic process.

For an ellipse, recall that the semi-major axis is one-half the sum of the perihelion and the aphelion. For a circular orbit, the semi-major axis ( a) is the same as the radius for the orbit. In fact, Equation 13.8 gives us Kepler’s third law if we simply replace r with a and square both sides. T 2 = 4 π 2 G M a 3.

Question Q. A running man has half the kinetic energy than a boy of half his mass has. The man speed up by 1.0ms−1 and then he has the same energy as the boy. The original speeds of the man and boy respectively are 3276 56 Work, Energy and Power Report Error A 2.4ms−1, 1.2ms−1 B 1.2ms−1, 4.4ms−1 C 2.4ms−1, 4.8ms−1 D 4.8ms−1, 2.4ms−1 Solution:

Answer: 21%. Explanation: Let the initial mass of the body be m and its velocity be v. Initial momentum of the body = mv . Initial KE = mv^2/2 . If the momentum increases by 10%, new momentum = mv + 10% of mv

De Broglie wavelength Google Classroom About Transcript Is it a particle or a wave? This is the question that physicists of the 1920s were asking about light. In 1924, Louis de Broglie took this question to another level as he explored how electrons - which are matter, and were thought to be simply particles - can behave like waves. Sort by:

Momentum is the mass of the object times the velocity of the object. The impulse is if that momentum changed, i.e. change in momentum. So in the video, because the car and the truck were stuck together post-crash, there was NO change in momentum, i.e. the impulse was 0.