The de broglie wavelength of an electron moving with kinetic energy of 144 ev is nearly

The problem is that for an electron $\nu \ne c/\lambda$. You need to replace $c$ by the phase velocity, which is somewhat involved to calculate. However you can get an approximate equation for the energy and wavelength by noting that the de Broglie wavelength is given by: $$ \lambda = \frac $$ Just as we concluded above. the energy of a debroglie wave can be gotten from the equation below E=hv/2l where l=wavelength it is obvious that a change in velocity will lead to a change in wavelength and energy. Therefore E=f(v,l) Using partial derivatives, the change in energy, dE is expressed through the following equation dE=h/2l(dv.(v/l).dl)

BEST MATCH What is the de Broglie wavelength of an electron that has a kinetic energy of (a) $1.60 \times 10-19 \mathrm$ ?

a proton and an electron have the same kinetic energy if the mass of the proton is 1800 times the mass of the electron find the ratio of their de broy wavelengths where do we begin well since we're dealing with debris wavelengths we could probably start by de roy's wavelength equation we've seen already in previous videos the debris wavelength that is the wavelength associated with any object having some momentum p can be written as lambda equals h the planck's constant divided by the momentum of the object and this is a pretty cool equation because it's saying that if you throw a ball which has some momentum it will have some wavelength a ball a moving cricket ball has a wavelength it behaves like a wave and that's the whole idea behind the wave particle duality that all things can behave like both waves and particles and where does this equation come from well we've derived this equation in a previous video and you can feel free to go back and check that out but i would recommend remembering this equation as a fundamental equation mainly because the derivation requires us to know about einstein's relationships of energy mass and momentum which is also beyond the scope of our syllabus so it's one of those few equations in physics that you can treat it as a fundamental equation and i would just recommend remembering it so this could be a starting point for whenever we're dealing with uh debris wavelengths all right so now we are what are we given we are asked to find the r...