Question What is the remainder left after dividing 1! + 2! + 3! + 100! by 7? A 0 B 5 C 21 D 14 Medium Solution Verified by Toppr Correct option is B) 1!+2!+3!+.100! As after 7! each term has '7' ∴ there Remainder is '0' hence Reminder of above series is (1!+2!+3!+4!+5!+6!)/7=873/7⇒ 5 Was this answer helpful? 0 0 Similar questions

Operators in C language, are classified into several categories. Arithmetic Operators Relational Operators Shift Operators Logical Operators Bitwise Operators Ternary or Conditional Operators Assignment Operators Misc Operators Special Operators Arithmetic Operators