Solution. Speed of the train = 60 k m / h = 60 × 5 18 m / s. Time taken to cross the pole = 9 s e c. Length of the train = s p e e d × t i m e = 60 × 5 18 × 9 = 150 m. Hence, 150 m is the length of the train. Suggest Corrections.

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1. A train running at the speed of 72 km/hr crosses a man standing on the platform in 12 seconds. What is the length of the train? A. 180 meters B. 210 meters C. 240 meters D. 270 meters View Answer 2. A train 100 m long passes a boy, running at 3 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:

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Seconds in a Day. There are 24 hours in a day. If there are 3,600 seconds in 1 hour, all you must do is multiply that by 24. By doing that, you will find that there are 86,400 seconds in the 24 hours of a day. Seconds in a Week. There are 7 days in a week. 86,400 seconds in a day multiplied by 7 days equals 604,800 seconds in a week. Seconds in.

In a kilometer race, A beats B by 60 meters or 7 seconds. What is the time taken by A over the course?. in a kilometer race, A beats B by 40 meters or by 10 seconds, what is the time taken by A over the course. In a kilometer race, A beats B by 50 meters or by 5 seconds. What is the time taken by A over the course.

Complete step-by-step answer: Given the problem, a farmer moves along the boundary of a square field of side 10m in 40 seconds. We need to find the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position. First, we calculate the perimeter of the square. The side of square A B C D is x = 10 m.

1 Answer +1 vote answered Mar 14, 2019 by Niharika (75.9k points) selected Mar 14, 2019 by Vikash Kumar Best answer The farmer takes 40 s to cover 4 × 10 = 40 m. In 2 min and 20 s (140 s), he will cover a distance = 40/40 x 140 = 140 m

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answer answered A straight highway leads to the foot of a tower. A man standing at the top of the tower observes a car at an angle of depression of 30°, which is approaching the foot of the tower with a uniform speed. Six seconds later, the angle of depression of the car is found to be 60°.

In a km race A beats B by 28metres or 7 sec. It means B covers 28 mtr in 7 secs or 4 mtr /sec. B covers 1 km or 1000 mtr in 1000/4 = 250 secs. A covers 1 km in 250-7 = 243 secs. A's speed per sec = 1000/243 mtrs /sec = 4.115 mtr/sec