Force = shear stress ∝ uo = µuo (3.1.2) areaYY As shown in (3.1.2), the proportionality constant between shear stress and the velocity gradient uo/Y is called the viscosity of the liquid, µ.

About dimension formula of coefficient of viscosity Cofficient of viscosity (η) = F × r × [A × v] -1 . (1) Where F = tangential force, r = distance between layers, A = Area, and v = velocity.

(8/ π) is that the drag coefficient is defined as the drag divided by the product of the projected area of the sphere and the velocity head. Thus, 22 22 8 1 42 DD D p p F F C π d V ρ πρdV = ×. Therefore, dimensional analysis tells us that drag coefficient is a universal function of the

Easy Solution Verified by Toppr Correct option is A) Surface tension = lF= L 1M 1L 1T −2=M 1T −2 Coeff of viscosity = qA dzdvk = LL 2LT −1M 1L 1T −2=M 1L −1T −1 Hence, mass has the same power. Solve any question of Units And Measurements with:- Patterns of problems > Was this answer helpful? 0 0 Similar questions

At low temperatures, the excess viscosity of the glycerol−water mixtures can be very well described by a regular-like solution coefficient. Cited By This article is cited by 57 publications.