Sodium ethoxide formula

CAS 141-52-6 Molecular Formula C2H5NaO Molecular Weight (g/mol) 68.051 MDL Number MFCD00012417 InChI Key QDRKDTQENPPHOJ-UHFFFAOYSA-N Synonym sodium ethoxide, sodium ethylate, sodium ethanolate, sodiumethoxide, ethoxysodium, ethanol, sodium salt, caustic alcohol, naoet, etona, ethanol, sodium salt 1:1 PubChem CID ChEBI IUPAC Name sodium;ethanolate SMILES CC[O-].[Na+] Sodium ethoxide is used as a strong base in organic synthesis. It is actively involved in the Claisen condensation, Stobbe reaction and Wolf-kishner reduction. It is an important starting material for the synthesis of ethyl ester and diethyl ester of malonic acid. In Williamson ether synthesis, it reacts with ethyl bromide to form diethyl ether. It is widely used as a base for the generation of carbanions which are utilized for alkylation and condensation reactions. This Thermo Scientific Chemicals brand product was originally part of the Alfa Aesar product portfolio. Some documentation and label information may refer to the legacy brand. The original Alfa Aesar product / item code or SKU reference has not changed as a part of the brand transition to Thermo Scientific Chemicals. Applications Sodium ethoxide is used as a strong base in organic synthesis. It is actively involved in the Claisen condensation, Stobbe reaction and Wolf-kishner reduction. It is an important starting material for the synthesis of ethyl ester and diethyl ester of malonic acid. In Williamson ether synthesis, it reacts with ethyl bromide ...

Chemical compound Sodium methoxide is the simplest CH 3ONa, it is a white solid, which is formed by the Preparation and structure [ ] Sodium methoxide is prepared by treating methanol with sodium: 2 Na + 2 CH 3OH → 2 CH 3ONa + H 2 The reaction is so As a solid, sodium methoxide is Na + centers, each bonded to four oxygen centers. The structure, and hence the basicity, of sodium methoxide in solution depends on the solvent. It is a significantly stronger base in Applications [ ] Organic synthesis [ ] Sodium methoxide is a routinely used base in organic chemistry, applicable to the synthesis of numerous compounds ranging from Industrial applications [ ] Sodium methoxide is used as an Stability [ ] The solid hydrolyzes in water to give methanol and CH 3ONa + CO 2 + H 2O → 2 CH 3OH + Na 2CO 3 Commercial batches of sodium methoxide show variable levels of degradation, and were a major source of irreproducibility when used in Safety [ ] Sodium methoxide is highly NFPA 704 [ ] The ratings for this substance vary widely. Rating • Chandran, K.; Kamruddin, M.; Ajikumar, P.K.; etal. (2006). "Kinetics of thermal decomposition of sodium methoxide and ethoxide". Journal of Nuclear Materials. 358 (2–3): 111–128. • ^ a b c • Weiss, E. (1964). "Die Kristallstruktur des Natriummethylats" [The Crystal Structure of Sodium Methylate]. Zeitschrift für Anorganische und Allgemeine Chemie (in German). 332 (3–4): 197–203. • ^ a b El-Kattan, Y.; McAtee, J.; Bessieres, B. (2006). "Sodium Methoxide". ...

CAS No. Chemical Name: Sodium ethoxide Synonyms NaOEt;SODIUM ETHANOLATE;EtONa;SODIUM ETHYLATE;NE-21;ethoxysodium;Sodium ethoxide solution;Sodium ethoxide-ethanol solution;JACS-141-52-6;causticalcohol CBNumber: CB6100652 Molecular Formula: C2H5NaO Molecular Weight: 68.05 MDL Number: MFCD00012417 MOL File: MSDS File: Melting point 260 °C Boiling point 91°C Density 0.868g/mLat 25°C vapor density 1.6 (vs air) vapor pressure <0.1 mm Hg ( 20 °C) refractive index n 20/D 1.386 Flash point 48°F storage temp. Store at +15°C to +25°C. solubility Soluble in ethanol and methanol. form Liquid color Yellow to brown Specific Gravity 0.868 PH 13 (5g/l, H2O, 20℃) Water Solubility Miscible Sensitive Moisture Sensitive Hydrolytic Sensitivity 7: reacts slowly with moisture/water Merck 14,8539 BRN 3593646 Exposure limits ACGIH: STEL 1000 ppm OSHA: TWA 1000 ppm(1900 mg/m3) NIOSH: IDLH 3300 ppm; TWA 1000 ppm(1900 mg/m3) Stability Reacts violently with acids, water. Incompatible with chlorinated solvents, moisture. Absorbs carbon dioxide from the air. Highly flammable. CAS DataBase Reference FDA UNII EPA Substance Registry System Symbol(GHS) Signal word Danger Hazard statements Precautionary statements Hazard Codes Risk Statements Safety Statements RIDADR UN 3274 3/PG 2 WGK Germany 1 F Autoignition Temperature 30 - 50 °C TSCA Yes HazardClass 4.2 PackingGroup II HS Code 29051900 Toxicity LD50 orally in Rabbit: 598 mg/kg NFPA 704 3 3 2 W Manufacturer Product number Product description CAS number Pac...

I thought that if you have a tertiary carbon, the reaction will be a 1 reaction, not a 2 reaction --and that whether the alpha carbon is tertiary, secondary, etc. is more important in determining whether it will be a 1 or 2 reaction than the strength of the base. How are we then having an E2 reaction on a tertiary carbon? It is the nature of the α carbon that determines the type of substitution. If you have a 3° carbon, the substitution reaction will be SN1. For 1° and 2° carbons, the substitution will be SN2. It is the strength of the base that determines the type of elimination. If you have a strong base, you will get E2 elimination. If you have a weak base, you will get E1 elimination from 3° substrates and probably no reaction from 1° and 2° substrates. The β₁ and β₂ products are each 1-methylcyclohexene, To determine the degree of substitution, we count the number of directly-attached carbon atoms on the alkene carbons . We don't count the alkene carbons themselves. C1 has attached to it the methyl carbon and C6 of the ring. C2 has attached to it C3 of the ring. This makes a total of three directly-attached carbon atoms, so the alkene is trisubstituted. In the β₃ product, the cyclohexane carbon has directly attached to it C2 and C6 of the ring. The exocyclic carbon has no carbon atoms attached to it. This makes a total of two directly-attached carbon atoms, so the alkene is disubstituted. The two carbons in the alkene have a double bond between them. That means, each ...

This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer See Answer See Answer done loading Question:Which method or methods would work to quantitatively prepare a sodium ethoxide solution? What is the formula of sodium ethoxide? (0.5 pts) Systems: CH3CH2OH + NaOH, CH3CH2OH + NaH; CH3CH2OH + Na Method to prepare sodium ethoxide: formula of sodium ethoxide: 2

Hi! I was told in my class that the reaction will only occur if the hydrogen forming the alkene product and the leaving group is anti-coplanar. How do you figure out if this is indeed the case. Should I just use Newman projections and wedge-dash diagrams? Is there a better (and easier) way to do this? Also, why is this the case? The nucleophile can easily attack the back side of a primary halogenoalkane in an SN reaction. In a tertiary halogenoalkane, the bulky alkyl groups prevent backside attack of the carbon bearing the alkyl group (steric hindrance). So the nucleophile acts as a base and does the next best thing — it attacks the hydrogen on the β carbon in an E2 elimination. Yep, it's good to keep in mind that most bases can also act as equally good nucleophiles; methoxide included. Sal is showing the E2 mechanism just to demonstrative, but in reality it's equally as likely for the methoxide to act as a nucleophile and perform an SN2 reaction too. Using a strong nucleophile/base we have the possibility for either an E2 or SN2 reaction. We can further narrow down the reaction mechanism by the type of substrate. 1° will promote SN2, 2° will promote both E2 and SN2 almost equally, and 3° will promote E2. In this problem we have a strong nucleophile/base with a 2° substrate so we can expect nearly equal amount of E2 and SN2 products. Hope that helps. Let's try to come up with the reaction of when we have this molecule right here reacting with sodium methoxide in a methanol...

Why is the behavior of sodium ethoxide inconsistent? In a reaction with 1-bromobutane, the anionic part of sodium ethoxide substitutes for $\ce$ changes the type of reaction. I believe sodium ethoxide, being bulky, must always do elimination, consistent with Rule #3 Given the above: can sodium ethoxide be forced to one type of reaction with a given reactant, by enforcing some reaction conditions? The above reactions belong to The Williamson Ether synthesis reactions follow S N2 mechanism. Since the S N2 mechanism proceeds through a single step where the nucleophile performs a “backside attack” on the alkyl halide, the only thing stopping this, is steric hindrance. Methyl and primary alkyl halides are excellent substrates for this synthesis, as they provide no/very less hindrance for the approaching nucleophile. Since alkoxides are strong bases, competition with elimination (E2) becomes a concern once the alkyl halide becomes more sterically hindered. This is exactly why, the first reaction that you’ve mentioned, proceeds by S N2 but in the second both elimination(major) and substitution (minor) takes place. Also note that, when tertiary alkyl halides are used, there is no hope for substitution because of the bulky groups present around carbon. Hence, only elimination takes place in this case. So the reactions are, • With primary alkyl halide, $$ \ce$. You chose a good link but look at the not very helpful rule: Your mentioned link clearly stated followings rules for the re...