The area of a rectangle gets reduced by 9 square units, if its length is reduced by 5 units and breadth is increased by 3 units. if we increase the length by 3 units and the breadth by 2 units, the area increases by 67 square units. find the dimensions of the rectangle.

  1. The area of a rectangle gets reduced by 9 square units if its length is reduced by 5 units and breadth is increased by 3 units. If we increase the length by 3 units and the breadth by 2 units. The area increases by 67 square units. Find the dimensions of the rectangle.
  2. NCERT Solutions for Class 10 Maths Exercise 3.5 Chapter 3
  3. The area of a rectangle gets reduced by 9 square units, if its length is reduced by 5 units and breadth
  4. The area of a rectangle gets reduced by 9 m^2 if its length is reduced by 5 m and breadth increased by 3 m. if we increase the length by 3 m and breadth by 2 m, the area is increased by 67 m^2 . The length of the rectangle is
  5. The area of a rectangle gets reduced by 9 square units if its length is reduced by 5 units and breadth is increased by 3 units. If we increase the length by 3 units and breadth by 2 units, the area increases by 67 square units. Find the dimensions of the rectangle.


Download: The area of a rectangle gets reduced by 9 square units, if its length is reduced by 5 units and breadth is increased by 3 units. if we increase the length by 3 units and the breadth by 2 units, the area increases by 67 square units. find the dimensions of the rectangle.
Size: 30.15 MB

The area of a rectangle gets reduced by 9 square units if its length is reduced by 5 units and breadth is increased by 3 units. If we increase the length by 3 units and the breadth by 2 units. The area increases by 67 square units. Find the dimensions of the rectangle.

Mathematics The area of a rectangle gets reduced by 9 square units if its length is reduced by 5 units and breadth is increased by 3 units. If we increase the length by 3 units and the breadth by 2 units. The area increases by 67 square units. Find the dimensions of the rectangle. The area of a rectangle gets reduced by 9 square units if its length is reduced by 5 units and breadth is increased by 3 units. If we increase the length by 3 units and the breadth by 2 units. The area increases by 67 square units. Find the dimensions of the rectangle. Solution: Let the length of the rectangle be and breadth be Then area of the rectangle Therefore, length of the rectangle becomes and breadth becomes Then area of the rectangle Then area of the rectangle Simplifying the equation further, we get Therefore, length of the rectangle becomes and breadth becomes Then area of the rectangle Then area of the rectangle We will equate both areas now as these are equal.

NCERT Solutions for Class 10 Maths Exercise 3.5 Chapter 3

CBSE Study Material • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • NCERT Solutions for Class 10 Maths Chapter 3 - Pair of Linear Equations in Two Variables Exercise 3.5 NCERT Solutions for Class 10 Maths Exercise 3.5 Chapter 3 Linear Equations in Two Variables are practice guides for students. All the solutions to the questions provided in the textbook can be found in NCERT Solutions Class 10 Maths Chapter 3 – Pair of Linear Equations in Two Variables is an important chapter from the board examination perspective. The solutions to the questions mentioned in the chapter are provided in NCERT Solutions Class 10 Maths Chapter 3 – Pair of Linear Equations in Two Variables Exercise 3.5. Download PDF carouselExampleControls111 Previous Next Access Other Exercise Solutions of Class 10 Maths Chapter 3 – Pair of Linear Equations in Two Variables Access Answers to NCERT Class 10 Maths Chapter 3 – Pair of Linear Equations in Two Variables Exercise 3.5 1. Which of the following pairs of linear equations has a unique solution, no solution, or in...

The area of a rectangle gets reduced by 9 square units, if its length is reduced by 5 units and breadth

Categories • • (31.9k) • (8.8k) • (764k) • (248k) • (10.0k) • (5.6k) • (36.3k) • (7.5k) • (10.7k) • (11.8k) • (11.2k) • (6.8k) • (4.9k) • (5.3k) • (2.8k) • (19.9k) • (936) • (2.9k) • (5.2k) • (664) • (121k) • (72.1k) • (3.8k) • (19.6k) • (1.4k) • (14.2k) • (12.5k) • (9.3k) • (7.7k) • (3.9k) • (6.7k) • (63.8k) • (26.6k) • (23.7k) • (14.6k) • (25.7k) • (530) • (84) • (765) • (49.1k) • (63.8k) • (1.8k) • (59.3k) • (24.5k)

The area of a rectangle gets reduced by 9 m^2 if its length is reduced by 5 m and breadth increased by 3 m. if we increase the length by 3 m and breadth by 2 m, the area is increased by 67 m^2 . The length of the rectangle is

Let the length of rectangle be = l breadth of rectangle = b Then, l b − ( l − 5 ) ( b + 3 ) = 9 5 b − 3 l = − 6 ----(1) and, ( l + 3 ) ( b + 2 ) − l b = 6 7 3 b + 2 l = 6 1---------- (2) Multiply (1) by 2 and (2) by 3 and add, 1 0 b + 9 b = − 1 2 + 1 8 3 1 9 b = 1 7 1 b = 9 and, 2 . l = 6 1 − ( 3 ∗ 9 ) Thus, length of rectangle is 17 cm

The area of a rectangle gets reduced by 9 square units if its length is reduced by 5 units and breadth is increased by 3 units. If we increase the length by 3 units and breadth by 2 units, the area increases by 67 square units. Find the dimensions of the rectangle.

Step 1: Use the given data and obtain the first equation: Let the area of the rectangle be A square units. Let the length of the rectangle be x units. Let the breadth of the rectangle be y units. ∴ Area of the rectangle, A = x y . It is given that the area of a rectangle gets reduced by 9 square units if its length is reduced by 5 units and breadth is increased by 3 units. The new area will be x y - 9 square units, if the length = x - 5 units, and breadth = y + 3 units. Thus, x y - 9 = x - 5 y + 3 x y - 9 = x y + 3 x - 5 y - 15 - 9 + 15 = 3 x - 5 y 6 = 3 x - 5 y 3 x - 5 y - 6 = 0   . . . . 1 Step 2: Find the second equation by using another given condition: It is given that if we increase the length by 3 units and breadth by 2 units, then the area increases by 67 square units. The new area will be x y + 67 square units, if the length = x + 3 units, and breadth = y + 2 units. Thus, x y + 67 = x + 3 y + 2 x y + 67 = x y + 2 x + 3 y + 6 67 - 6 = 2 x + 3 y 61 = 2 x + 3 y 2 x + 3 y - 61 = 0   . . . . 2 Thus, we get the following system of linear equations: 3 x - 5 y - 6 = 0 2 x + 3 y - 61 = 0   Step 3: Solve this system of linear equations using the cross-multiplication method: x - 5 - 6 3 - 61 = - y - 6 3 - 61 2 = 1 3 - 5 2 3 x 305 + 18 = y - 12 + 183 = 1 9 + 10 x 323 = y 171 = 1 19 x = 323 19 , y = 171 19 x = 17 , y = 9 Hence, the dimensions of the rectangle are as follows: Length = 17 units Breadth = 9 units

Tags: The area of a