The height at which the weight of a body becomes 1/16

The height at which the weight of a body becomes 1/16thof its weight on the surface of the earth (radius R) is: 1. 5 R 2. 15 R 3. 3 R 4. 4 R Past Year (2006 - 2015) MCQs Gravitation Physics (2022) NEET Practice Questions, MCQs, Past Year Questions (PYQs), NCERT Questions, Question Bank, Class 11 and Class 12 Questions, and PDF solved with answers • Recommended MCQs - 108 Questions • Recommended PYQs (STRICTLY NCERT Based) • Mini Q Bank - Gravitation • NCERT Solved Examples Based MCQs • NCERT Exercise Based MCQs • NCERT Exemplar (Objective) Based MCQs • AR & Other Type MCQs • Padma Shri H C Verma (Objective Exercises) Based MCQs • Past Year (2019 onward - NTA Papers) MCQs • Past Year (2016 - 2018) MCQs • Past Year (2006 - 2015) MCQs • Past Year (1998 - 2005) MCQs A geostationary satellite is orbiting the earth at a height of \(5R\) above the surface of the earth, \(R\) being the radius of the earth. The time period of another satellite in hours at a height of \(2R\) from the surface of the earth is: 1. \(5\) 2. \(10\) 3. \(6\sqrt2\) 4. \(\frac\) A body projected vertically from the earth reaches a height equal to earth’s radius before returning to the earth. The power exerted by the gravitational force: 1.is greatest at the instant just before the body hits the earth. 2. remains constant throughout. 3. is greatest at the instant just after the body is projected. 4. is greatest at the highest position of the body. Two satellites of earth,S 1andS 2, are moving in the same orb...

Correct Answer - Option 4 : 19600 km The correct answer is option 4) i.e. 19600 km CONCEPT: • Acceleration due to gravity on the surface of Earth of mass M and radius R e is denoted by g. • It has an approximated uniform value of 9.8 m/s 2 on the surface of Earth. • The acceleration due to gravity at a depth 'd' below the surface of Earth is given by ​ \(⇒ g' = g(1- \frac\) \(⇒ 4R_e +4h''=R_e +h'\) \(⇒ 3(6400) +4(100)= h'\) ⇒ h' = 19600 km